Problem 39
Question
Identify and graph each polar equation. $$ r=2+2 \cos \theta $$
Step-by-Step Solution
Verified Answer
Graph the limaçon with an inner loop present at \( r = 2 + 2 \, \cos \theta \).
1Step 1: Recognize the Standard Polar Form
Identify the given polar equation and recognize it as part of a standard form. The equation given is \[ r = 2 + 2 \, \cos \theta \]This is a polar equation that can be identified as a limaçon.
2Step 2: Determine Key Characteristics
A limaçon of the form \[ r = a + b \, \cos \theta \]The constants in the equation are: \[ a = 2 \, \text{and} \, b = 2 \]Since \[ a = b \]this specific limaçon will have an inner loop.
3Step 3: Find Important Points
Find and plot the points for specific values of \( \theta \):For \( \theta = 0 \):\[ r = 2 + 2 \, \cos(0) = 4 \]For \( \theta = \frac{\pi}{2} \):\[ r = 2 + 2 \, \cos \left( \frac{\pi}{2} \right) = 2 \]For \( \theta = \pi \):\[ r = 2 + 2 \, \cos(\pi) = 0 \]For \( \theta = \frac{3\pi}{2} \):\[ r = 2 + 2 \, \cos \left( \frac{3\pi}{2} \right) = 2 \]
4Step 4: Sketch the Graph
Using the points calculated from Step 3, sketch the graph of the limaçon. The plot should reflect the shape with an inner loop, starting at (4, 0) and going through (0, π).
Key Concepts
limaçongraphing polar coordinatestrigonometric functions
limaçon
A limaçon is a type of curve represented by polar equations of the form either \( r = a + b \, \text{cos} \, \theta \) or \( r = a + b \, \text{sin} \, \theta \). Limaçons have unique and interesting shapes that vary depending on the values of \( a \) and \( b \). In our case, \( r = 2 + 2 \, \text{cos} \, \theta \), the constants \( a \) and \( b \) both equal 2. Some key characteristics of limaçons include:
- If \( a < b \), the limaçon has an inner loop.
- If \( a = b \), it's a special limaçon with an inner loop.
- If \( a > b \), it appears without an inner loop.
graphing polar coordinates
Understanding polar coordinates is essential for graphing polar equations like the limaçon. A polar coordinate system represents a point in the plane using the distance from the origin \( r \) and the angle \( \theta \) from the positive x-axis. Here’s a quick overview:
- The distance \( r \) measures how far away a point is from the origin (pole).
- The angle \( \theta \) measures the rotational offset from the positive x-axis (polar axis).
- Calculate \( r \) for several values of \( \theta \), like \( 0 \, \text{and} \, \frac{\text{π}}{2}, \, \text{π}, \, \frac{\text{3π}}{2} \).
- Plot these points on the polar coordinate plane.
- Connect the points to visualize the limaçon curve.
trigonometric functions
Trigonometric functions like \( \text{cos} \, \theta \) and \( \text{sin} \, \theta \) are fundamental to understanding polar equations. In our exercise, \( r = 2 + 2 \, \text{cos} \, \theta \), we rely on the cosine function to determine \( r \) for different \( \theta \) values. Let's break down their role:
- Cosine function \( \text{cos} \, \theta \) returns a value between -1 and 1.
- For \( \theta = 0 \), \( \text{cos} \, 0 = 1 \), effectively making \( r = 2 + 2 \times 1 = 4 \).
- For \( \theta = \frac{\text{π}}{2} \), \( \text{cos} \, \frac{\text{π}}{2} = 0 \), leading to \( r = 2 + 2 \times 0 = 2 \).
- For \( \theta = \text{π} \), \( \text{cos} \, \text{π} = -1 \), resulting in \( r = 2 + 2 \times -1 = 0 \).
Other exercises in this chapter
Problem 39
Find \(z w\) and \(\frac{z}{w} .\) Write each answer in polar form and in exponential form. \(z=3 e^{i \frac{13 \pi}{18}}\) \(w=4 e^{i \frac{3 \pi}{2}}\)
View solution Problem 39
Plot each point given in polar coordinates, and find other polar coordinates \((r, \theta)\) of the point for which: (a) \(r>0, \quad-2 \pi \leq \theta0, \quad
View solution Problem 40
Find \(z w\) and \(\frac{z}{w} .\) Write each answer in polar form and in exponential form. \(z=2 e^{i \frac{4 \pi}{9}}\) \(w=6 e^{i \frac{10 \pi}{9}}\)
View solution Problem 40
Plot each point given in polar coordinates, and find other polar coordinates \((r, \theta)\) of the point for which: (a) \(r>0, \quad-2 \pi \leq \theta0, \quad
View solution