Problem 39
Question
How many geometric isomers are possible for the square planar complex \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)(\mathrm{CN}) \mathrm{Cl}_{2}\right]^{-} ?^{-}\)
Step-by-Step Solution
Verified Answer
There are 2 geometric isomers for this complex: cis and trans.
1Step 1: Understanding the Problem
We need to determine the number of geometric isomers for the square planar complex \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)(\mathrm{CN}) \mathrm{Cl}_{2}\right]^{-}\). In square planar complexes, ligands are positioned at the four corners of a square plane, and geometric isomerism arises from different spatial arrangements of these ligands around the central metal atom.
2Step 2: Identifying the Ligands
The given complex has four ligands: one \(\mathrm{NH}_{3}\), one \(\mathrm{CN}\), and two chlorine ions \(\mathrm{Cl}^-\). The ligands can be arranged differently around the central platinum atom \(\mathrm{Pt}\) due to these different types, leading to possible geometric isomers.
3Step 3: Determining Isomer Arrangements
In a square planar complex, geometric isomerism can occur by arranging ligands either cis (adjacent) or trans (opposite) to each other. For this complex, we should consider how each pair of similar ligands (such as the two \(\mathrm{Cl}^-\) ions) are placed relative to each other.
4Step 4: Counting the Geometric Isomers
For \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)(\mathrm{CN}) \mathrm{Cl}_{2}\right]^{-}\), key isomer arrangements include:1. Both \(\mathrm{Cl}^-\) ions adjacent (cis) to each other.2. Both \(\mathrm{Cl}^-\) ions opposite (trans) to each other.Thus, there are 2 geometric isomers possible: cis- and trans- forms.
Key Concepts
Square Planar ComplexesLigand ArrangementCis-Trans Isomers
Square Planar Complexes
Square planar complexes are a fascinating area of coordination chemistry. These complexes involve a central metal atom bonded to four ligands arranged at the corners of a square. This structure creates a two-dimensional geometry, distinct from the three-dimensional structures seen in other complex ions like tetrahedral or octahedral.
The square planar arrangement is often associated with transition metals, especially those possessing a d8 electron configuration. Platinum (Pt), used in our exercise, is a prime example since it frequently forms complexes with this configuration. This specific arrangement allows for unique interactions among the ligands, leading to the possibility of geometric isomerism.
Geometric isomerism in square planar complexes arises from the ability to arrange the same ligands in different spatial positions around the central metal. This is crucial to understanding how molecules with the same chemical formula can have different physical and chemical properties due to their distinct geometries.
The square planar arrangement is often associated with transition metals, especially those possessing a d8 electron configuration. Platinum (Pt), used in our exercise, is a prime example since it frequently forms complexes with this configuration. This specific arrangement allows for unique interactions among the ligands, leading to the possibility of geometric isomerism.
Geometric isomerism in square planar complexes arises from the ability to arrange the same ligands in different spatial positions around the central metal. This is crucial to understanding how molecules with the same chemical formula can have different physical and chemical properties due to their distinct geometries.
Ligand Arrangement
In square planar complexes, the arrangement of ligands is key to understanding geometric isomerism. Ligands are the ions or molecules bound to the central metal atom, and their positions can dramatically affect the properties of the complex.
For the complex \([\mathrm{Pt}\left(\mathrm{NH}_{3}\right)(\mathrm{CN})\mathrm{Cl}_{2}\right]^{-},\) the ligands involved are ammonia (\(\mathrm{NH}_{3}\)), cyanide (\(\mathrm{CN}^-\)), and two chloride ions (\(\mathrm{Cl}^-\)). These ligands are arranged around the platinum in various configurations.
When arranging ligands in a square planar complex, consider how similar ligands, such as the two \(\mathrm{Cl}^-\) ions, can be positioned either next to each other (cis) or opposite each other (trans). This arrangement gives rise to different geometric isomers and affects the overall stability and reactivity of the complex.
For the complex \([\mathrm{Pt}\left(\mathrm{NH}_{3}\right)(\mathrm{CN})\mathrm{Cl}_{2}\right]^{-},\) the ligands involved are ammonia (\(\mathrm{NH}_{3}\)), cyanide (\(\mathrm{CN}^-\)), and two chloride ions (\(\mathrm{Cl}^-\)). These ligands are arranged around the platinum in various configurations.
When arranging ligands in a square planar complex, consider how similar ligands, such as the two \(\mathrm{Cl}^-\) ions, can be positioned either next to each other (cis) or opposite each other (trans). This arrangement gives rise to different geometric isomers and affects the overall stability and reactivity of the complex.
Cis-Trans Isomers
Cis-trans isomerism is a type of geometric isomerism that notably occurs in square planar complexes like \([\mathrm{Pt}\left(\mathrm{NH}_{3}\right)(\mathrm{CN})\mathrm{Cl}_{2}\right]^{-}.\) This form of isomerism involves the spatial arrangement of specific ligands relative to each other.
In the cis isomer:
In the cis isomer:
- The two \(\mathrm{Cl}^-\) ions are positioned next to each other.
- This proximity can create stronger interactions between the ligands, potentially affecting the complex's properties like solubility and biological activity.
- The \(\mathrm{Cl}^-\) ions are on opposite sides of the platinum atom.
- This arrangement may lead to reduced steric hindrance and different reactivity patterns compared to the cis isomer.
Other exercises in this chapter
Problem 37
Which of the following complexes is (are) square planar? (a) \(\left[\mathrm{Ti}(\mathrm{CN})_{4}\right]^{2-}\) (b) \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^
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Which of the following complexes containing the oxalate ion is (are) chiral? (a) \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right) \mathrm{C}_{4}\ri
View solution Problem 41
A transition metal complex absorbs 425-nm light. What is its color? (a) red (c) yellow (b) green (d) blue
View solution Problem 42
For the low-spin complex [Fe(en) \(\left._{2} \mathrm{Cl}_{2}\right]\) Cl, identify the following. (a) the oxidation number of iron (b) the coordination number
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