Problem 39
Question
For each of the following pairs, predict which substance has the higher entropy per mole at a given temperature: (a) \(\mathrm{I}_{2}(s)\) or \(\mathrm{I}_{2}(g)\) (b) \(\mathrm{O}_{2}(g)\) at \(50.7 \mathrm{kPa}\) or \(\mathrm{O}_{2}\) at \(101.3 \mathrm{kPa}\) (c) 1 molof \(\mathrm{N}_{2}\) in 22.4 Lor \(1 \mathrm{~mol}\) of \(\mathrm{N}_{2}\) in \(44.8 \mathrm{~L}\). (d) \(\mathrm{CH}_{3} \mathrm{OH}(I)\) or \(\mathrm{CH}_{3} \mathrm{OH}(s)\)
Step-by-Step Solution
Verified Answer
In summary:
(a) \(\mathrm{I}_{2}(g)\) has higher entropy than \(\mathrm{I}_{2}(s)\).
(b) \(\mathrm{O}_{2}(g)\) at \(50.7 \mathrm{kPa}\) has higher entropy than \(\mathrm{O}_{2}(g)\) at \(101.3 \mathrm{kPa}\).
(c) \(\mathrm{N}_{2}\) in \(44.8 \mathrm{~L}\) has higher entropy than \(\mathrm{N}_{2}\) in \(22.4 \mathrm{~L}\).
(d) \(\mathrm{CH}_{3}\mathrm{OH}(l)\) has higher entropy than \(\mathrm{CH}_{3}\mathrm{OH}(s)\).
1Step 1: Pair (a) Analysis
For iodine, we have to compare the entropy of the solid phase and the gas phase. As mentioned, entropy is higher for gases than for solids.
2Step 2: Pair (a) Conclusion
In pair (a), Iodine gas (\(\mathrm{I}_{2}(g)\)) has the higher entropy per mole at a given temperature compared to solid iodine (\(\mathrm{I}_{2}(s)\)).
3Step 3: Pair (b) Analysis
In this case, we have to compare the entropy of oxygen gas at two different pressures. As pressure increases, entropy decreases.
4Step 4: Pair (b) Conclusion
In pair (b), oxygen gas (\(\mathrm{O}_{2}\)) at \(50.7 \mathrm{kPa}\) pressure has higher entropy per mole at a given temperature compared to oxygen gas at \(101.3 \mathrm{kPa}\).
5Step 5: Pair (c) Analysis
In this case, we have to compare the entropy of 1 mole of nitrogen gas in different volumes. As volume increases, entropy also increases.
6Step 6: Pair (c) Conclusion
In pair (c), 1 mole of nitrogen gas in 44.8 L (\(\mathrm{N}_{2}\) in \(44.8 \mathrm{~L}\)) has higher entropy per mole at a given temperature compared to 1 mole of nitrogen gas in 22.4 L (\(\mathrm{N}_{2}\) in 22.4 L).
7Step 7: Pair (d) Analysis
For methanol (\(\mathrm{CH}_{3}\mathrm{OH}\)), we have to compare the entropy of the liquid phase and the solid phase. As mentioned, entropy is higher for liquids than for solids.
8Step 8: Pair (d) Conclusion
In pair (d), liquid methanol (\(\mathrm{CH}_{3}\mathrm{OH}(l)\)) has higher entropy per mole at a given temperature compared to solid methanol (\(\mathrm{CH}_{3}\mathrm{OH}(s)\)).
Key Concepts
Phase TransitionGas LawsPressure and VolumeThermodynamics
Phase Transition
Phase transitions are changes in the state of matter. They involve transformations like solid to liquid, liquid to gas, or vice versa. These changes play a crucial role in altering the entropy of a substance.
Entropy, which measures the disorder of a system, often increases when there is a phase transition. Here's why:
Entropy, which measures the disorder of a system, often increases when there is a phase transition. Here's why:
- In solids, particles are tightly packed, with minimal freedom of movement. This results in lower entropy.
- Liquids allow more particle movement, leading to higher entropy compared to solids.
- Gases have particles widely dispersed and moving freely, thus possessing the highest entropy among the phases.
Gas Laws
Gas laws describe the behavior of gases and relate different gas properties such as pressure, volume, and temperature. These laws are crucial to understanding gas entropy.
One primary law is the **Ideal Gas Law**, expressed as \( PV = nRT \), where \(P\) is pressure, \(V\) is volume, \(n\) is moles, \(R\) is the gas constant, and \(T\) is temperature.
In the context of entropy:
One primary law is the **Ideal Gas Law**, expressed as \( PV = nRT \), where \(P\) is pressure, \(V\) is volume, \(n\) is moles, \(R\) is the gas constant, and \(T\) is temperature.
In the context of entropy:
- An increase in volume (\(V\)) at constant pressure allows gas particles more space to move, increasing entropy.
- A decrease in pressure (\(P\)) could imply a volume increase or a drop in temperature, affecting entropy.
Pressure and Volume
Pressure and volume are key factors in a gas's entropy. They are inversely related in the Ideal Gas Law, meaning a change in one affects the other.
**Understanding their relationship: **
**Understanding their relationship: **
- When volume increases, gases expand, allowing molecules more room to move freely. This leads to an increase in entropy.
- Conversely, when pressure rises, the volume decreases, limiting molecular movement and reducing entropy.
Thermodynamics
Thermodynamics assesses the principles that govern energy and matter interactions, including entropy. It offers insight into how and why changes occur in physical systems.
**The four laws of thermodynamics** primarily guide these interactions:
This understanding explains phenomena such as the persistence of methanol in a liquid state or the higher entropy of gases compared to solids.
**The four laws of thermodynamics** primarily guide these interactions:
- The **zeroth law** establishes temperature as a uniform measure.
- The **first law**, or conservation of energy, highlights that energy cannot be created or destroyed.
- The **second law** states that entropy tends to increase, driving spontaneous processes.
- The **third law** posits that absolute zero is unattainable as it requires zero entropy.
This understanding explains phenomena such as the persistence of methanol in a liquid state or the higher entropy of gases compared to solids.
Other exercises in this chapter
Problem 37
Indicate whether each statement is true or false. (a) The third law of thermodynamics says that the entropy of a perfect, pure crystal at absolute zero increase
View solution Problem 38
Indicate whether each statement is true or false. (a) Unlike enthalpy, where we can only ever know changes in \(H,\) we can know absolute values of \(S .(\mathb
View solution Problem 40
For each of the following pairs, predict which substance possesses the larger entropy per mole: (a) \(1 \mathrm{~mol}\) of \(\mathrm{O}_{2}(g)\) at \(300^{\circ
View solution Problem 41
Predict the sign of the entropy change of the system for each of the following reactions: (a) \(\mathrm{CO}(g)+\mathrm{H}_{2}(g) \longrightarrow C(s)+\mathrm{H}
View solution