Problem 39
Question
Finding a Term of a Geometric Sequence Find a formula for the \(n\)th term of the geometric sequence. Then find the indicated term of the geometric sequence. 9th term: \(7,21,63, \dots\)
Step-by-Step Solution
Verified Answer
The \(n\)th term of the given geometric sequence is \(7 \cdot 3^{(n-1)}\). The 9th term of the sequence is \(7 \cdot 3^{8}\), or 150807.
1Step 1: Understand the Formula for a Geometric Sequence
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number. The formula for the \(n\)th term of a geometric sequence is \(a \cdot r^{(n-1)}\), where \(a\) is the first term, \(r\) is the common ratio, and \(n\) is the term number.
2Step 2: Identify the First Term and Common Ratio
In the given sequence, the first term \(a\) is 7. The common ratio \(r) can be found by dividing any term by the previous term. For instance, \(21 ÷ 7 = 3\) or \(63 ÷ 21 = 3\). Therefore, the common ratio \(r\) is 3.
3Step 3: Substitute Into the Formula
Substitute the values \(a = 7\), \(r = 3\) into the geometric sequence formula to find the formula for the \(n\)th term, which becomes \(7 \cdot 3^{(n-1)}\).
4Step 4: Find the 9th Term
Substitute \(n = 9\) in the formula to find the 9th term. So, the 9th term will be \(7 \cdot 3^{(9-1)} = 7 \cdot 3^{8}\).
Key Concepts
Common RatioNth Term FormulaSequence Terms
Common Ratio
In a geometric sequence, the magic number that ties the sequence together is known as the 'common ratio'. This ratio is the factor that each term is multiplied by to get the next term in the sequence. To identify the common ratio, simply divide any term in the sequence by the previous term.
For example, in the sequence you are working with \(7, 21, 63, \ldots\), the common ratio can be calculated by taking \(21 \div 7 = 3\) and similarly, \(63 \div 21 = 3\). Hence, the common ratio is 3.
The common ratio essentially dictates the pace at which the sequence grows or shrinks, ensuring a constant multiplicative relationship among terms.
For example, in the sequence you are working with \(7, 21, 63, \ldots\), the common ratio can be calculated by taking \(21 \div 7 = 3\) and similarly, \(63 \div 21 = 3\). Hence, the common ratio is 3.
The common ratio essentially dictates the pace at which the sequence grows or shrinks, ensuring a constant multiplicative relationship among terms.
- It must be a non-zero number to ensure that the sequence is meaningful.
- It defines whether the sequence is increasing (when \(r > 1\)) or decreasing (when \(r < 1\)).
- If \(r = 1\), the sequence is constant.
Nth Term Formula
The formula for finding the nth term in a geometric sequence is your key to unlocking any term in the sequence. It's expressed as: \(a \cdot\ r^{(n-1)}\) where \(a\) represents the first term, \(r\) is the common ratio, and \(n\) is the term number you want to find. This formula enables you to find any term in the sequence without listing all terms.
Here's how each part functions:
In your exercise, substituting \(a = 7\) and \(r = 3\) gives the formula: \(7\cdot3^{(n-1)}\).
Here's how each part functions:
- \(a\): The starting point of your sequence. In your example, \(a = 7\).
- \(r\): Describes the repetitive multiplicative factor between terms. Here, \(r = 3\).
- \(n-1\): The exponent \(n-1\) determines how many times the common ratio is used, starting after the first term. This calculation helps to jump directly to any term in the sequence.
In your exercise, substituting \(a = 7\) and \(r = 3\) gives the formula: \(7\cdot3^{(n-1)}\).
Sequence Terms
Sequence terms refer to the individual elements or numbers within a sequence. In a geometric sequence, each term is a result of multiplying the previous term by the common ratio. Understanding sequence terms is essential for identifying patterns and predicting future terms without listing every single one.
For the sequence \(7, 21, 63, \ldots\):
For the sequence \(7, 21, 63, \ldots\):
- The first term is 7. This serves as your original starting point.
- Subsequent terms are generated by multiplying the previous term by the common ratio, which is 3 in this instance.
- Every term in the sequence can be predicted using the nth term formula rather than manually multiplying each time.
Other exercises in this chapter
Problem 39
Evaluate \(_{n} P_{r}\) using a graphing utility. $$_{120} P_{4}$$
View solution Problem 39
You are given the probability that an event will not happen. Find the probability that the event will happen. $$P\left(E^{\prime}\right)=\frac{13}{20}$$
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Use the Binomial Theorem to expand and simplify the expression. \(\left(5-x^{2}\right)^{5}\)
View solution Problem 40
Write an expression for the apparent \(n\) th term of the sequence. (Assume \(n\) begins with \(1 .\)) $$3,7,11,15,19, \ldots$$
View solution