Problem 39
Question
Find the limits. \(\lim _{x \rightarrow 0^{-}} \frac{|x|}{x}\)
Step-by-Step Solution
Verified Answer
The limit is -1.
1Step 1: Understanding the Limit Expression
We need to find the limit of the expression \( \frac{|x|}{x} \) as \( x \) approaches 0 from the left (denoted as \( 0^- \)). This means we're considering values of \( x \) that are slightly less than 0.
2Step 2: Analyzing the Absolute Value
The expression \( |x| \) represents the absolute value of \( x \). When \( x \) is negative, the absolute value function changes the sign of \( x \) to positive, so \(|x| = -x\).
3Step 3: Substituting Absolute Value in the Expression
Since \( x \) is approaching 0 from the negative side, substitute \(|x| = -x\) into the expression: \[ \frac{|x|}{x} = \frac{-x}{x} = -1 \]
4Step 4: Evaluating the Limit
As \( x \) approaches 0 from the left, the expression \( \frac{-x}{x} \) simplifies to -1. This means: \[ \lim_{x \rightarrow 0^{-}} \frac{|x|}{x} = -1 \]
Key Concepts
Understanding Absolute ValueApproaching From the LeftEvaluating Limits Involving Absolute Values
Understanding Absolute Value
The absolute value of a number is its distance from zero on the number line without considering direction. In simple terms, for any real number \( x \):
In this exercise, recognizing that \( |x| = -x \) for \( x < 0 \) is crucial when finding the limit as \( x \) approaches 0 from the negative side.
- If \( x \) is positive or zero, \(|x| = x\).
- If \( x \) is negative, \(|x| = -x\), which converts the negative value into positive.
In this exercise, recognizing that \( |x| = -x \) for \( x < 0 \) is crucial when finding the limit as \( x \) approaches 0 from the negative side.
Approaching From the Left
When we evaluate limits like \( \lim_{x \rightarrow 0^-} \), we focus on values of \( x \) that are slightly less than zero. This is called approaching from the left.
Visualize the number line. Approaching 0 from the left means moving from negative values toward zero. For example, from -0.1 to -0.01, and so on. This specific direction influences how certain functions behave near the point of interest.
In our exercise, as \( x \) approaches 0 from the left, \( x \) takes on negative values. Consequently, for the expression \( \frac{|x|}{x} \), the numerator becomes \(-x\) while the denominator is \(x\). Understanding this directional approach is key to correctly evaluating the limit.
Visualize the number line. Approaching 0 from the left means moving from negative values toward zero. For example, from -0.1 to -0.01, and so on. This specific direction influences how certain functions behave near the point of interest.
In our exercise, as \( x \) approaches 0 from the left, \( x \) takes on negative values. Consequently, for the expression \( \frac{|x|}{x} \), the numerator becomes \(-x\) while the denominator is \(x\). Understanding this directional approach is key to correctly evaluating the limit.
Evaluating Limits Involving Absolute Values
Limits can seem challenging, especially with absolute values involved. The trick is to carefully analyze the behavior of each component as \( x \) approaches a specific value.
Remember, limits describe the behavior of a function as \( x \) nears a specified point. Breaking down the function using these steps helps us accurately find \( \lim_{x \rightarrow 0^-} \frac{|x|}{x} = -1 \).
- First, assess the role of the absolute value for \( x < 0 \), where \( |x| = -x \).
- Next, substitute this into the expression, which transforms \( \frac{|x|}{x} \) into \( \frac{-x}{x} \).
Remember, limits describe the behavior of a function as \( x \) nears a specified point. Breaking down the function using these steps helps us accurately find \( \lim_{x \rightarrow 0^-} \frac{|x|}{x} = -1 \).
Other exercises in this chapter
Problem 39
Sketch the graph of a function that has domain \([0,6]\) and is continuous on \((0,6)\) but not on \([0,6]\).
View solution Problem 39
Prove that \(\lim _{x \rightarrow c}|x|=|c|\).
View solution Problem 40
In Problems 37-40, use natural logarithms to solve each of the exponential equations. Hint: To solve \(3^{x}=11\), take ln of both sides, obtaining \(x \ln 3=\l
View solution Problem 40
Sketch, as best you can, the graph of a function \(f\) that satisfies all the following conditions. (a) Its domain is the interval \([0,4]\). (b) \(f(0)=f(1)=f(
View solution