Problem 39
Question
Find an equation of the parabola with vertex \((0,0)\) that satisfies the given conditions. Horizontal axis, passing through \((1,-2)\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \( y^2 = 4x \).
1Step 1: Identify the Parabola Form
Since the parabola has a horizontal axis, its general equation is of the form \( y^2 = 4px \). The parabola opens to the right or the left depending on the sign of \( p \). Since the vertex is at the origin \((0,0)\), the equation simplifies to \( y^2 = 4px \).
2Step 2: Use Given Point to Find 'p'
We know the parabola passes through the point \((1, -2)\). Substitute \(x = 1\) and \(y = -2\) into the equation \( y^2 = 4px \):\( (-2)^2 = 4p(1) \).This gives us \( 4 = 4p \), so \( p = 1 \).
3Step 3: Write the Final Equation
Substitute the value of \( p \) back into the parabola's equation, we get:\( y^2 = 4(1)x \) or \( y^2 = 4x \). This is the equation of the parabola with the vertex at \((0,0)\) and a horizontal axis passing through the point \((1, -2)\).
Key Concepts
Vertex FormHorizontal AxisFocus and Directrix
Vertex Form
The vertex form of a parabola's equation is a special way to express it, focusing on the parabola's vertex—a point that's often key to understanding its shape and orientation. The vertex of a parabola is its "peak"; the highest or lowest point depending on the orientation of the parabola. For a vertical parabola, the vertex form is given by:
However, for horizontal parabolas, like in our exercise, the equation is structured differently:
Understanding the vertex form helps in quickly identifying the vertex, direction, and size of a parabola just by looking at its equation.
- Vertical Parabola: \( y = a(x-h)^2 + k \)
However, for horizontal parabolas, like in our exercise, the equation is structured differently:
- Horizontal Parabola: \( x = a(y-k)^2 + h \)
Understanding the vertex form helps in quickly identifying the vertex, direction, and size of a parabola just by looking at its equation.
Horizontal Axis
When a parabola has a horizontal axis, it means it opens either left or right instead of the usual up or down. This impacts the orientation and shapes the form of its equation. In such cases, the standard form of the parabola equation shifts from the usual \( y = ax^2 + bx + c \) to:
This equation makes it clear that, if we were to graph it, the parabola would start from the vertex at \((0, 0)\) and would "head" to the right, given that \( p \,= \,1 \) is a positive value.
Such understanding allows us to easily plot and understand the behavior of the curve on a graph without plotting multiple points.
- For horizontal open parabolas: \( y^2 = 4px \).
This equation makes it clear that, if we were to graph it, the parabola would start from the vertex at \((0, 0)\) and would "head" to the right, given that \( p \,= \,1 \) is a positive value.
Such understanding allows us to easily plot and understand the behavior of the curve on a graph without plotting multiple points.
Focus and Directrix
The concepts of focus and directrix are fundamental in understanding the properties of a parabola. A parabola is defined as the set of all points equidistant from a point known as the "focus" and a line called the "directrix." This geometric property not only defines the shape but also affects the analytic form of the equation.
Visualizing the focus and directrix helps learners understand why a parabola "bends" the way it does and provides a more comprehensive grasp of the curve's geometric nature.
- Focus: This point lies along the axis of symmetry of the parabola. For the equation \( y^2 = 4px \), the focus is located at \((p, 0)\).
- Directrix: It is a line that is perpendicular to the axis of symmetry of the parabola. For the equation \( y^2 = 4px \), the directrix is the line \( x = -p \).
Visualizing the focus and directrix helps learners understand why a parabola "bends" the way it does and provides a more comprehensive grasp of the curve's geometric nature.
Other exercises in this chapter
Problem 38
Sketch a graph of the ellipse. $$ x^{2}+\frac{(y-3)^{2}}{4}=1 $$
View solution Problem 38
Find an equation of the parabola with vertex \((0,0)\) that satisfies the given conditions. Directrix \(y=-1\)
View solution Problem 40
Find an equation of the parabola with vertex \((0,0)\) that satisfies the given conditions. Vertical axis, passing through \((-2,3)\)
View solution Problem 41
Find an equation of a parabola that satisfies the given conditions. Focus \((0,-3)\) and directrix \(y=3\)
View solution