Problem 39
Question
Find a unit vector in the direction of the given vector. $$\mathbf{v}=(24,-7)$$
Step-by-Step Solution
Verified Answer
The unit vector in the direction of \( \mathbf{v} = (24, -7) \) is \( \left( \frac{24}{25}, -\frac{7}{25} \right) \)."}
1Step 1: Analyze the problem
Identify the type of problem and select the appropriate mathematical approach.
2Step 2: Solve step by step
The unit vector in the direction of \( \mathbf{v} = (24, -7) \) is \( \left( \frac{24}{25}, -\frac{7}{25} \right) \)."}.
3Step 3: Verify
Check the solution by substitution or alternative method.
Key Concepts
Vector MagnitudeVector DirectionMagnitude Calculation
Vector Magnitude
When we talk about the magnitude of a vector, we are essentially discussing how long the vector is. Magnitude represents the size or length of a vector.
For a two-dimensional vector \( \mathbf{v} = (x, y) \), the magnitude is calculated using the Pythagorean theorem. This is because a vector can be thought of as the hypotenuse of a right triangle, with its components \( x \) and \( y \) forming the other two sides.
The formula for the magnitude \( \| \mathbf{v} \| \) is:
For a two-dimensional vector \( \mathbf{v} = (x, y) \), the magnitude is calculated using the Pythagorean theorem. This is because a vector can be thought of as the hypotenuse of a right triangle, with its components \( x \) and \( y \) forming the other two sides.
The formula for the magnitude \( \| \mathbf{v} \| \) is:
- \( \| \mathbf{v} \| = \sqrt{x^2 + y^2} \)
- First component (x): 24
- Second component (y): -7
Vector Direction
Vectors not only have a magnitude, but they also have a direction. The direction of a vector is the angle it forms with a reference line, usually the positive x-axis in two-dimensional space.
This direction is especially significant in problems where the orientation of a force or movement is needed. In our case, identifying the direction helps in forming a unit vector in the same path as the original vector \( \mathbf{v} = (24, -7) \).
Remember, a unit vector is a vector that has a magnitude of exactly 1 but points in the same direction as the original vector. To find the unit vector's specific direction, we might calculate the angle using trigonometric functions, though in many cases it is enough to understand its pathway for computation without specifically measuring the angle.
This direction is especially significant in problems where the orientation of a force or movement is needed. In our case, identifying the direction helps in forming a unit vector in the same path as the original vector \( \mathbf{v} = (24, -7) \).
Remember, a unit vector is a vector that has a magnitude of exactly 1 but points in the same direction as the original vector. To find the unit vector's specific direction, we might calculate the angle using trigonometric functions, though in many cases it is enough to understand its pathway for computation without specifically measuring the angle.
Magnitude Calculation
Calculating the magnitude of a vector involves several steps. First, ensure you have all the vector's components; these are usually given in the format \( (x, y) \) for two dimensions.
For the vector \( \mathbf{v} = (24, -7) \), calculate the square of each component:
For the vector \( \mathbf{v} = (24, -7) \), calculate the square of each component:
- \( x^2 = 24^2 = 576 \)
- \( y^2 = (-7)^2 = 49 \)
- \( 576 + 49 = 625 \)
- \( \| \mathbf{v} \| = \sqrt{625} = 25 \)
Other exercises in this chapter
Problem 39
Find all \(n\) th roots of \(z\). Write the answers in polar form, and plot the roots in the complex plane. $$8 \sqrt{2}-8 \sqrt{2} i, n=4$$
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Use a calculator to express each complex number in polar form. $$4.02-2.11 i$$
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Graph equation. \(r=5 \cos (2 \theta)\)
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Find all \(n\) th roots of \(z\). Write the answers in polar form, and plot the roots in the complex plane. $$-\sqrt{128}+\sqrt{128} i, n=4$$
View solution