Problem 39
Question
Factor. $$ (x+y) u+(x+y) v $$
Step-by-Step Solution
Verified Answer
The expression factors to \((x+y)(u+v)\).
1Step 1: Identify Common Factors
Look at the expression \((x+y)u + (x+y)v\). Notice that \((x+y)\) is a common factor in both terms of the expression.
2Step 2: Factor Out the Common Factor
Since \((x+y)\) is common in both terms, we can factor it out. The expression becomes: \[(x+y)(u+v)\] This is the factored form of the original expression.
Key Concepts
Common FactorsAlgebraic ExpressionsFactoring Process
Common Factors
In algebra, the term **common factors** refers to components that appear in multiple parts of an expression or equation. When we talk about factoring expressions, identifying common factors is one of the most crucial steps. Let's break it down.
A common factor in a mathematical expression is a term that each part of the expression shares. It can be a number, a variable, or even a more complex expression. For instance, in the expression \((x+y)u + (x+y)v\), the term \((x+y)\) is a common factor because it appears in both parts of the expression.
To effectively find common factors, look for repeated components in the expression. Sometimes it requires multiplying and rearranging terms until the commonality becomes evident. By recognizing these shared pieces, one can simplify expressions or solve equations more efficiently.
A common factor in a mathematical expression is a term that each part of the expression shares. It can be a number, a variable, or even a more complex expression. For instance, in the expression \((x+y)u + (x+y)v\), the term \((x+y)\) is a common factor because it appears in both parts of the expression.
To effectively find common factors, look for repeated components in the expression. Sometimes it requires multiplying and rearranging terms until the commonality becomes evident. By recognizing these shared pieces, one can simplify expressions or solve equations more efficiently.
Algebraic Expressions
**Algebraic expressions** are mathematical statements that include numbers, variables, and operations, like addition or multiplication, to represent a value or relationship. Let's explore what makes these a key component of algebra.
When we talk about algebraic expressions, they can be simple or complex:
Working with these expressions requires understanding the roles of each element:
When we talk about algebraic expressions, they can be simple or complex:
- Simple expressions might be something like \(3a + 5b\), where numbers (coefficients) and letters (variables) are used.
- More complex expressions, such as \((x+y)u + (x+y)v\), include multiple terms and operations.
Working with these expressions requires understanding the roles of each element:
- Co-efficients: These are the numbers that multiply the variables (e.g., in \(3x\), 3 is the coefficient).
- Variables: Often letters like \(x\) or \(y\), variables act as placeholders and can represent different quantities.
Factoring Process
The **factoring process** is a method used to simplify algebraic expressions by extracting common elements. This process makes expressions easier to work with and solve. Let’s see how it operates in detail.
Starting with an expression like \((x+y)u + (x+y)v\), the factoring process consists of a few clear steps:
Remember, successful factoring relies on careful recognition of what terms can be "shared." By consistently applying this process, it becomes a fundamental skill for solving algebra problems efficiently.
Starting with an expression like \((x+y)u + (x+y)v\), the factoring process consists of a few clear steps:
- **Identify Common Factors:** First, as we did in the original problem, find components common to all terms of the expression. In \((x+y)u + (x+y)v\), this is \((x+y)\).
- **Factor Out the Common Factor:** Once identified, factor out the common factor from each term, essentially dividing every part of the expression by the common component. Here, factoring out \((x+y)\) results in \((x+y)(u+v)\).
Remember, successful factoring relies on careful recognition of what terms can be "shared." By consistently applying this process, it becomes a fundamental skill for solving algebra problems efficiently.
Other exercises in this chapter
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