Problem 39
Question
Factor using the Binomial Theorem. $$x^{4}+4 x^{3} y+6 x^{2} y^{2}+4 x y^{3}+y^{4}$$
Step-by-Step Solution
Verified Answer
The expression factors as \((x+y)^{4}\).
1Step 1: Recognize the Pattern
Observe that the given expression \(x^{4}+4x^{3}y+6x^{2}y^{2}+4xy^{3}+y^{4}\) appears to match the form of a binomial expansion. Specifically, it resembles \((x+y)^{4}\).
2Step 2: Verify the Terms
We need to verify that the terms match the formula for the binomial expansion of \((x+y)^{4}\), which is \[\binom{4}{0} x^{4} y^{0} + \binom{4}{1} x^{3} y^{1} + \binom{4}{2} x^{2} y^{2} + \binom{4}{3} x^{1} y^{3} + \binom{4}{4} x^{0} y^{4}\]. Comparing each corresponding coefficient confirms the match.
3Step 3: Use Binomial Theorem
Since the expression matches the form given in the Binomial Theorem, we can express the original polynomial as \((x+y)^{4}\) by observing the full sequence of coefficients \(1, 4, 6, 4, 1\).
4Step 4: Conclude the Factorization
Having verified the arrangement of terms and coefficients, we conclude that the polynomial \(x^{4}+4x^{3}y+6x^{2}y^{2}+4xy^{3}+y^{4}\) is factored completely as \((x+y)^{4}\).
Key Concepts
Polynomial FactorizationBinomial ExpansionPascal's Triangle
Polynomial Factorization
Polynomial factorization is the process of breaking down a complex polynomial into simpler components, or 'factors.' This helps to simplify expressions and solve polynomial equations more easily. When we factor a polynomial, we aim to express it as a product of its factors. The original polynomial can be thought of as a "product" that has been expanded, similar to turning ingredients into a finished meal.In the given exercise, the polynomial is factored using the Binomial Theorem, which reveals that the expression in question can be written as a power of a binomial, specifically \((x+y)^4\). This factored form is simpler and more compact. Factoring is especially helpful in solving equations where we're required to find roots or zeros of the polynomial. Once in factored form, understanding the individual factors opens the door to deeper insights into the polynomial's properties and potential solutions.
Binomial Expansion
Binomial expansion involves expanding expressions that are raised to a power, specifically polynomials with two terms. It is a specific case of polynomial expansion that uses a formula to expand expressions like \((x + y)^n\), where \(n\) is a non-negative integer.The Binomial Theorem provides the framework to expand any binomial. The formula is \[(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^{k},\]where \(\binom{n}{k}\) represents binomial coefficients. These coefficients can be calculated using combinations, which tell us how many ways we can choose \(k\) elements from a set of \(n\) elements.By using binomial expansion, complex polynomials can be rewritten into more manageable forms. In our exercise, the transformation of the polynomial \(x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4\) into \((x+y)^4\), illustrates the magic of using binomial expansion to simplify expressions.
Pascal's Triangle
Pascal's Triangle is a powerful tool that provides binomial coefficients in a triangular form, making calculations for binomial expansions quick and efficient. Each row in Pascal's Triangle corresponds to the coefficients of the expanded form of \((a + b)^n\). The triangle starts with a peak value of one at the top.To construct Pascal's Triangle:
- Begin with a "1" at the top.
- Each following row starts and ends with "1".
- The interior values are obtained by summing the two values directly above in the previous row.
Other exercises in this chapter
Problem 38
Find the first four partial sums and the \(n\) th partial sum of the sequence \(a_{n}\) $$a_{n}=\log \left(\frac{n}{n+1}\right)$$
View solution Problem 39
Find the partial sum \(S_{n}\) of the arithmetic sequence that satisfies the given conditions. $$a=1, d=2, n=10$$
View solution Problem 39
Find the partial sum \(S_{n}\) of the geometric sequence that satisfies the given conditions. $$a=5, \quad r=2, \quad n=6$$
View solution Problem 39
Find the sum. $$\sum_{k=1}^{4} k$$
View solution