Problem 39
Question
Factor. $$ 64 x^{3}-27 y^{3} $$
Step-by-Step Solution
Verified Answer
The factored form is \((4x-3y)(16x^2 + 12xy + 9y^2)\).
1Step 1: Identify the Form of the Expression
The given expression is a binomial with two terms: \(64x^3\) and \(27y^3\). We notice that both terms are perfect cubes.
2Step 2: Recognize the Formula for a Difference of Cubes
The formula for factoring a difference of cubes is \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\). Our goal is to rewrite \(64x^3 - 27y^3\) in this form.
3Step 3: Identify \(a\) and \(b\) in the Difference of Cubes Formula
In the expression \(64x^3\), the cube root is \((4x)^3\), hence \(a = 4x\). In the term \(27y^3\), the cube root is \((3y)^3\), so \(b = 3y\).
4Step 4: Substitute \(a\) and \(b\) into the Difference of Cubes Formula
Substitute \(a = 4x\) and \(b = 3y\) into the formula: \[(4x-3y)((4x)^2 + (4x)(3y) + (3y)^2)\].
5Step 5: Simplify the Resulting Expression
Simplify each part of the expression:1. \((4x)^2 = 16x^2\)2. \((4x)(3y) = 12xy\)3. \((3y)^2 = 9y^2\).Thus, the expression becomes \((4x-3y)(16x^2 + 12xy + 9y^2)\).
Key Concepts
Understanding BinomialsRecognizing Perfect CubesWorking with Algebraic Expressions
Understanding Binomials
In algebra, a **binomial** is a type of polynomial that consists of exactly two terms. These terms are connected by either a plus or a minus sign. Binomials are very common in algebraic expressions and are a critical concept to understand when learning polynomial arithmetic. Consider the example:
- The expression \(64x^3 - 27y^3\) is a binomial because it contains two distinct terms: \(64x^3\) and \(-27y^3\).
- The terms in a binomial can involve variables raised to a power, as well as coefficients (numbers multiplying the variables).
Recognizing Perfect Cubes
A **perfect cube** is a number that can be expressed as the cube of an integer or a variable raised to the third power. Perfect cubes are essential in algebra, particularly when dealing with the difference of cubes or sum of cubes.For instance:
- The number 64 is a perfect cube because it equals \(4^3\).
- Similarly, the term \(x^3\) is a perfect cube since it is \((x)^3\).
- For the expression \(64x^3\), \(4x\) is the base that when cubed gives the term: \((4x)^3 = 64x^3\).
Working with Algebraic Expressions
**Algebraic expressions** are mathematical phrases that can include numbers, variables, and operation symbols. They form the foundation of algebra and are used for modeling real-world situations, solving equations, and more.Key points to understand:
- Algebraic expressions can range from simple monomials like \(3x\) to complex polynomials like \(64x^3 - 27y^3\).
- These expressions can be manipulated in various ways, such as by factoring, which involves expressing the equation as a product of its factors.
- When working with algebraic expressions, especially those involving perfect cubes and binomials, understanding and applying the appropriate formulas (like factoring the difference of cubes) becomes crucial.
Other exercises in this chapter
Problem 39
Factor. If a polynomial can't be factored, write "prime." $$ x^{2}-16 $$
View solution Problem 39
Factor. See Example 6 or Example 11. $$a^{2}+4 a b+3 b^{2}$$
View solution Problem 39
Solve each equation. $$ 4 x^{2}-1=0 $$
View solution Problem 39
Find the GCF of each list of terms. $$ 4(p-t), p(p-t) $$
View solution