Problem 39
Question
Expand and simplify the rule of the function \(g .\) $$f(x)=x^{3}-2 x^{2}+x-4 \text { and } g(x)=f(x+1)$$
Step-by-Step Solution
Verified Answer
Based on the step-by-step solution provided:
Question: Expand and simplify the function `g(x) = f(x+1)` when `f(x) = x^3 - 2x^2 + x - 4`.
Answer: g(x) = x^3 + x^2 - 4
1Step 1: Understand the given functions
We are given two functions, f(x) and g(x). The function f(x) is defined as \(f(x) = x^3 - 2x^2 + x - 4\). The function g(x) is defined as the function f evaluated at \(x+1\), meaning that \(g(x) = f(x+1)\).
2Step 2: Substitute x+1 into f(x)
We will substitute x+1 into f(x) to find the expression of g(x). Replace x in the expression of f(x) with x+1:
$$
g(x) = f(x+1) = ((x+1)^3 - 2(x+1)^2 + (x+1) - 4)
$$
3Step 3: Expand and simplify the expression
Now we will expand and simplify the expression we obtained in step 2:
$$
g(x) = ((x+1)^3 - 2(x+1)^2 + (x+1) - 4) \\
= ((x^3+3x^2+3x+1) - 2(x^2+2x+1) + x + 1 - 4) \\
= (x^3+3x^2+3x+1 - 2x^2-4x-2 + x + 1 - 4) \\
= (x^3+3x^2+3x+1 - 2x^2-4x-2 + x + 1 - 4) \\
=x^3 + (3-2)x^2 + (3-4+1)x + (1-2+1-4) \\
=x^3 + x^2 - 4
$$
So, the rule for g(x) is simplified as:
$$
g(x) = x^3 + x^2 - 4
$$
Key Concepts
Polynomial FunctionsFunction ExpansionSimplified Expressions
Polynomial Functions
Polynomial functions are an essential building block of algebra that represent expressions composed of variables raised to power and their coefficients. These functions are formed by adding together terms like \(x^3\), \(-2x^2\), \(x\), and constants such as \(-4\). The highest exponent in the polynomial dictates its degree, which informs us about the potential number of roots and the shape of its graph. In the given exercise, the original function \(f(x) = x^3 - 2x^2 + x - 4\) is a degree 3 polynomial.
- Degrees: Indicate the highest power of the variable (e.g., cubic means the highest degree is 3).
- Coefficients: The numbers multiplying each term (e.g., -2 in \(-2x^2\)).
- Constant Term: A term without a variable (e.g., \(-4\) in the given function).
Function Expansion
Function expansion involves extending a polynomial by substituting variables or values, leading to a new polynomial expression. In the exercise, the transformation from \(f(x)\) to \(g(x) = f(x+1)\) demanded expanding the function \(f(x)\) by replacing \(x\) with \(x+1\). This method broadens the function, affecting each term as shown:
- Replace \(x\) with a new expression \((x+1)\) in every term of \(f(x)\).
- Calculate each power post-substitution, e.g., \((x+1)^3\) becomes \(x^3 + 3x^2 + 3x + 1\).
- Adjust and combine results into a comprehensive polynomial.
Simplified Expressions
Simplified expressions aim to reduce a complex polynomial into its most concise form while retaining the same value. In our exercise's context, after expanding \(g(x) = f(x+1)\), we simplified the function. Simplification entails collecting like terms and performing algebraic operations meticulously. Here is how the simplification process unfolded:
- Combine like terms: This means adding or subtracting coefficients of terms with the same degree, e.g., \((3 - 2)x^2\) gets simplified to just \(x^2\).
- Follow the order of operations: Carefully compute addition, subtraction, and any multiplicative conjunctions.
- Check and recheck the work: Ensure that each step aligns correctly, leading to the ultimate clean expression.
Other exercises in this chapter
Problem 38
Express the sum in \(\Sigma\) notation. $$(-6)^{11}+(-6)^{12}+(-6)^{13}+(-6)^{14}+(-6)^{15}$$
View solution Problem 39
In Exercises \(39-42,\) find the kth partial sum of the geometric sequence \(\left\\{a_{n}\right\\}\) with common ratio \(r\) $$k=6, a_{1}=5, r=\frac{1}{2}$$
View solution Problem 39
Express the sum in \(\Sigma\) notation. $$2+\frac{2^{2}}{2}+\frac{2^{3}}{3}+\frac{2^{4}}{4}+\frac{2^{5}}{5}+\frac{2^{6}}{6}+\frac{2^{7}}{7}$$
View solution Problem 40
In Exercises \(39-42,\) find the kth partial sum of the geometric sequence \(\left\\{a_{n}\right\\}\) with common ratio \(r\). $$k=8, a_{1}=9, r=\frac{1}{3}$$
View solution