Problem 39
Question
Evaluate the expression and write the result in the form \(a+b i .\) $$ i^{3} $$
Step-by-Step Solution
Verified Answer
\(-i = 0 - i\)
1Step 1: Understanding Imaginary Unit
The imaginary unit is denoted as \(i\) and is defined as the square root of \(-1\). This means \(i^2 = -1\).
2Step 2: Simplifying Higher Powers of i
To evaluate expressions like \(i^3\), we need to simplify higher powers of \(i\) using the fact that \(i^2 = -1\). Recall that powers of \(i\) follow a pattern every four exponents: \(i^1 = i\), \(i^2 = -1\), \(i^3 = -i\), \(i^4 = 1\), and then it repeats.
3Step 3: Calculate \(i^3\)
Using the pattern of powers of \(i\), recognize that \(i^3 = i^{2+1} = (i^2) \cdot i = (-1) \cdot i = -i\).
Key Concepts
Imaginary UnitPowers of iSimplification of Expressions
Imaginary Unit
The imaginary unit, symbolized by \(i\), is a fundamental concept in complex numbers. It's defined as \(i = \sqrt{-1}\). This may seem strange at first, but the imaginary unit allows us to work with numbers that are impossible to handle on the real number line.
By definition, multiplying the imaginary unit by itself, that is \(i \cdot i\), gives \(i^2 = -1\).
This pivotal property of \(i\) serves as a building block for dealing with complex numbers and simplifies mathematical expressions that involve negative square roots.
By definition, multiplying the imaginary unit by itself, that is \(i \cdot i\), gives \(i^2 = -1\).
This pivotal property of \(i\) serves as a building block for dealing with complex numbers and simplifies mathematical expressions that involve negative square roots.
- \(i\) is the imaginary unit.
- \(i^2 = -1\).
- The imaginary unit helps solve equations like \(x^2 = -1\) by making \(x = i\) a solution.
Powers of i
Understanding the powers of \(i\) is crucial as they form a predictable cycle. This cycle repeats every four exponents, a pattern that simplifies working with higher powers of \(i\).
The cycle is as follows:
For example, if you have \(i^7\), you can think of it as four full cycles plus three additional steps: \(i^7 = i^4 \cdot i^3 = 1 \cdot (-i) = -i\). This technique simplifies complex calculations and is powerful when evaluating expressions involving \(i\).
The cycle is as follows:
- \(i^1 = i\)
- \(i^2 = -1\)
- \(i^3 = -i\)
- \(i^4 = 1\)
For example, if you have \(i^7\), you can think of it as four full cycles plus three additional steps: \(i^7 = i^4 \cdot i^3 = 1 \cdot (-i) = -i\). This technique simplifies complex calculations and is powerful when evaluating expressions involving \(i\).
Simplification of Expressions
Simplifying expressions with the imaginary unit involves using the cyclical nature of \(i\). Once you grasp this pattern, evaluating expressions becomes much less daunting.
Consider the expression \(i^3\) as an example. Here’s how you simplify it:
Such simplification techniques are fundamental when writing complex numbers in their standard form \(a + bi\), where \(a\) and \(b\) are real numbers. It ensures clarity and eases further mathematical operations, which are essential in calculations involving electrical engineering, fluid dynamics, and other fields.
Consider the expression \(i^3\) as an example. Here’s how you simplify it:
- With \(i^3 = i^{2+1}\), recognize this as the product of \(i^2\) and \(i\).
- Knowing \(i^2 = -1\), substitute this in: \((-1) \cdot i = -i\).
Such simplification techniques are fundamental when writing complex numbers in their standard form \(a + bi\), where \(a\) and \(b\) are real numbers. It ensures clarity and eases further mathematical operations, which are essential in calculations involving electrical engineering, fluid dynamics, and other fields.
Other exercises in this chapter
Problem 39
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