Problem 39
Question
Evaluate by any method. $$ \frac{d}{d x} \int_{x}^{1} \frac{d t}{t} $$
Step-by-Step Solution
Verified Answer
The derivative is \(-\frac{1}{x}\).
1Step 1: Understand the Problem
We need to differentiate the integral \( \int_{x}^{1} \frac{dt}{t} \). This involves finding \( \frac{d}{dx} \int_{x}^{1} \frac{dt}{t} \). Since the upper limit is a constant and the lower limit is a variable, we can use Leibniz rule for differentiation of parameterized integrals.
2Step 2: Apply Leibniz Rule
The Leibniz rule states that if we have an integral \( \int_{a(x)}^{b(x)} f(t) \, dt \), then the derivative with respect to \( x \) is \( f(b(x)) b'(x) - f(a(x)) a'(x) \). In our case, the integral is \( \int_{x}^{1} \frac{dt}{t} \) with \( a(x) = x \) and \( b(x) = 1 \). Thus, we have \( \frac{1}{b(x)} \cdot 0 - \left(\frac{1}{a(x)} \cdot 1\right) = -\frac{1}{x} \).
3Step 3: Simplify the Expression
From the application of the Leibniz Rule, the result simplifies to \( -\frac{1}{x} \). There is no further simplification necessary as this is the derivative of the given integral with respect to \( x \).
Key Concepts
Leibniz RuleParameterized IntegralsDerivative with Respect to a Variable
Leibniz Rule
The Leibniz Rule is a powerful tool in calculus that helps us differentiate an integral when one or both of its limits are functions of a variable. It's especially handy when dealing with parameterized integrals.
To apply the Leibniz Rule to an integral of the form \( \int_{a(x)}^{b(x)} f(t) \, dt \), the rule provides a method for finding the derivative with respect to \( x \).
To apply the Leibniz Rule to an integral of the form \( \int_{a(x)}^{b(x)} f(t) \, dt \), the rule provides a method for finding the derivative with respect to \( x \).
- The formula derived from the rule is: \( f(b(x)) b'(x) - f(a(x)) a'(x) \).
- This means you evaluate the function \( f(t) \) at the upper limit \( b(x) \) and multiply by the derivative of \( b(x) \), then subtract the evaluation at the lower limit \( a(x) \) multiplied by the derivative of \( a(x) \).
Parameterized Integrals
Parameterized integrals are integrals where one or both of the limits are not constants, but instead depend on a variable. This creates a more dynamic scenario for integration since the area being integrated beneath can shift as the parameter changes.
These types of integrals are crucial in understanding systems where the conditions change over time or space, making them an essential part of advanced calculus and applied mathematics.
These types of integrals are crucial in understanding systems where the conditions change over time or space, making them an essential part of advanced calculus and applied mathematics.
- In parameterized integrals, evaluating the area under a curve requires careful consideration of each limit's dependency on a variable.
- The derivative of such integrals involves applying rules that account for these changing limits, such as the Leibniz Rule.
Derivative with Respect to a Variable
When we talk about taking the derivative with respect to a variable, we are looking to understand how a function changes as we change one of its inputs. In cases where the function is an integral with variable limits, these derivatives help track these changes in a more complex system.
Given a function integrated over a parameter, differentiating helps pinpoint how the collective output varies as the boundaries of integration move.
Given a function integrated over a parameter, differentiating helps pinpoint how the collective output varies as the boundaries of integration move.
- This process unveils the rate of change of the integral with respect to the parameter, providing insights into dynamic changes in areas under curves.
- It is pivotal in understanding how functions grow, shrink, or transform based on modifying inputs, especially when modeled by integrals with variable limits.
Other exercises in this chapter
Problem 38
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