Problem 39
Question
Each of the following functions is one-to-one. Find the inverse of each function and express it using \(f^{-1}(x)\) notation. $$ f(x)=\frac{x-4}{5} $$
Step-by-Step Solution
Verified Answer
The inverse function is \( f^{-1}(x) = 5x + 4 \).
1Step 1: Write the function equation
Let's start by writing the given function equation: \[ f(x) = \frac{x - 4}{5} \] This is the equation we need to find the inverse for.
2Step 2: Replace f(x) with y
Replace \( f(x) \) with \( y \) to set up the equation for finding the inverse:\[ y = \frac{x - 4}{5} \] This will help us rewrite the equation in terms of \( x \) and \( y \).
3Step 3: Swap x and y
To find the inverse, swap \( x \) and \( y \) in the equation. This gives:\[ x = \frac{y - 4}{5} \] This equation will be solved for \( y \) to find the inverse function.
4Step 4: Solve for y
Multiply both sides of the equation by 5 to eliminate the fraction:\[ 5x = y - 4 \]Add 4 to both sides to isolate \( y \):\[ y = 5x + 4 \] This is the expression for the inverse function.
5Step 5: Write the inverse function
Now that we have expressed \( y \) in terms of \( x \), we can write the inverse function:\[ f^{-1}(x) = 5x + 4 \] This is the inverse of the original function.
Key Concepts
One-to-One FunctionsSolving EquationsFunction Notation
One-to-One Functions
One-to-One Functions allow us to find their inverses, which reverses the input-output relationship of the function. A One-to-One Function is a special type of function where each output value is paired with exactly one input value. This property is important in ensuring that the inverse is also a function, as it maintains a unique input-output relationship.
Key characteristics of One-to-One Functions include:
Key characteristics of One-to-One Functions include:
- Each X value (input) produces a unique Y value (output).
- If two outputs from the function are equal, then their inputs must also be equal: if \( f(x_1) = f(x_2) \) then \( x_1 = x_2 \).
- Graphically, they pass the Horizontal Line Test: any horizontal line will intersect the function graph at most once.
Solving Equations
Finding the inverse of a function involves solving equations. By manipulating the function's expression, we reverse the roles of the input and output.
To find the inverse, we can follow these steps:
To find the inverse, we can follow these steps:
- Replace the function notation \( f(x) \) with \( y \). This simplifies working with the equation.
- Swap \( x \) and \( y \) to switch the input and output roles. This step sets us up to solve for \( y \).
- Solve the resulting equation for \( y \) to get the inverse. Use algebraic techniques such as adding, subtracting, multiplying, or dividing both sides of the equation to isolate \( y \).
Function Notation
Function Notation is an essential language of mathematics that helps express relationships between variables clearly and concisely. When working with functions, it is important to be comfortable with how they are denoted and manipulated.
Key elements of function notation include:
Key elements of function notation include:
- Functions are typically denoted by a letter, such as \( f \), \( g \), or \( h \), followed by the variable in parentheses: \( f(x) \).
- The notation \( f(x) = \frac{x-4}{5} \) means that \( f \) is a function in which \( x \) is the variable.
- When functions have inverses, the inverse is usually represented as \( f^{-1}(x) \). This denotes the function that will undo the work done by \( f \).
Other exercises in this chapter
Problem 39
Let \(f(x)=2 x+1\) and \(g(x)=x^{2}-1 .\) Find each of the following. See Example 3 . $$ (g \circ f)(-3) $$
View solution Problem 39
Solve each equation. Give the exact solution and an approximation to four decimal places. $$ e^{-0.2 t}=14.2 $$
View solution Problem 40
Find A using the formula \(A=P e^{r t}\) given the following values of \(P, r,\) and \(t .\) Round to the nearest hundredth. $$ P=110, r=-0.25 \%, t=9 \text { y
View solution Problem 40
Write each logarithm as a difference. Then simplify, if possible. See Example 3 . $$ \ln \frac{27}{e} $$
View solution