Problem 39
Question
Determine the amplitude and period of each function. Then graph one period of the function. $$y=-4 \cos \frac{1}{2} x$$
Step-by-Step Solution
Verified Answer
The amplitude of the function is 4 and the period is \(4\pi\). The function can be graphed as a reflection of the standard cosine function over the x-axis, stretching from \(0\) to \(4\pi\), with a maximum height of 4 and a minimum depth of -4.
1Step 1: Find the Amplitude
The amplitude is simply the absolute value of the coefficient of the cosine function. Here, the coefficient is \(-4\), so the amplitude is \(| -4 | = 4\).
2Step 2: Find the Period
The period of the function is found by dividing \(2\pi\) by the absolute value of the term with which \(x\) is being multiplied inside the cosine function, which is \(0.5\) or \(\frac{1}{2}\). Hence the period is \(2\pi/0.5 = 4\pi\).
3Step 3: Graph the Function
The function is negative, so it will be a reflection of the standard cosine function over the x-axis. The amplitude tells the maximum height and depth of the function, which are \(-4\) and \(4\). The function completes one cycle over the range \(0\) to \(4\pi\). By plotting a few key points, such as the start and end points (0, -4) and (4pi, -4), and the maximum and minimum points in between, the final curve representing one period of the function can be drawn.
Other exercises in this chapter
Problem 38
Use an identity to find the value of each expression. Do not use a calculator. $$\csc ^{2} \frac{\pi}{6}-\cot ^{2} \frac{\pi}{6}$$
View solution Problem 38
In Exercises \(37-40,\) an object moves in simple harmonic motion described by the given equation, where \(t\) is measured in seconds and d in inches In each ex
View solution Problem 39
Graph two periods of the given cosecant or secant function. $$y=-\frac{1}{2} \sec \pi x$$
View solution Problem 39
Convert each angle in radians to degrees. Round to two decimal places. -4.8 radians
View solution