Problem 39
Question
(a) For the generic reaction \(\mathrm{A} \rightarrow \mathrm{B}\) what quantity, when graphed versus time, will yield a straight line for a first- order reaction? (b) How can you calculate the rate constant for a first-order reaction from the graph you made in part (a)?
Step-by-Step Solution
Verified Answer
(a) The natural logarithm of the concentration of \( A \) vs time yields a straight line. (b) The rate constant \( k \) is found from the negative slope of this line.
1Step 1: Understanding First Order Reactions
In a first-order reaction, the rate of the reaction is directly proportional to the concentration of one reactant. For a generic reaction \( \mathrm{A} \rightarrow \mathrm{B} \), the rate is \( -\frac{d[\mathrm{A}]}{dt} = k [\mathrm{A}] \), where \( k \) is the rate constant.
2Step 2: Identifying the Logarithmic Relationship
For first-order kinetics, we know that the concentration of reactant \( A \) over time is given by the equation \( [\mathrm{A}] = [\mathrm{A}]_0 e^{-kt} \). By taking the natural logarithm of both sides, \( \ln([\mathrm{A}]) = \ln([\mathrm{A}]_0) - kt \), which resembles the equation of a straight line, \( y = mx + b \).
3Step 3: Graphing Natural Logarithm vs Time
According to the linear equation \( \ln([\mathrm{A}]) = \ln([\mathrm{A}]_0) - kt \), when \( \ln([\mathrm{A}]) \) is plotted against time \( t \), it yields a straight line where the slope \( m \) is equal to \(-k\), and the intercept \( b \) is \( \ln([\mathrm{A}]_0) \).
4Step 4: Determining the Rate Constant
From the graph produced in the previous step, you can determine the rate constant \( k \) by calculating the slope. Since \( \text{slope} = -k \), the absolute value of the slope of the line gives you the rate constant \( k \).
Key Concepts
Reaction KineticsRate ConstantConcentration vs. Time Graph
Reaction Kinetics
Reaction kinetics is an essential aspect of understanding how reactions proceed over time. When studying the kinetics of a reaction, we focus on the rate at which reactants are converted into products. For a first-order reaction, the rate is directly related to the concentration of one reactant. This means that as the concentration of the reactant decreases, the rate of the reaction also decreases proportionally. To put it simply, the speed at which the reaction occurs depends on how much reactant you have.
- First-order reactions are characterized by a single reactant whose concentration influences the rate.
- These reactions are common in chemical processes such as radioactive decay and certain enzyme reactions.
Rate Constant
The rate constant, denoted as \( k \), is a fundamental parameter in reaction kinetics. It provides insight into the speed of a reaction under certain conditions. In the context of a first-order reaction, the rate constant can be thought of as a measure of how fast the reaction proceeds when there is a unit concentration of the reactant.
- The value of \( k \) always remains constant at a fixed temperature for a specific reaction type.
- Higher values of \( k \) generally indicate faster reactions.
Concentration vs. Time Graph
In first-order reaction kinetics, a concentration vs. time graph provides a visual insight into how the concentration of a reactant changes over time. For these reactions, plotting the natural logarithm of the concentration of reactant \( [A] \) against time gives a straight line. This linear behavior is due to the logarithmic relationship within first-order kinetics, described by the equation:\[\ln([A]) = \ln([A]_0) - kt\]Where \([A]_0\) is the initial concentration, and \(t\) represents time.
- The y-axis is \( \ln([A]) \), and the x-axis is time.
- The slope of the line equals \(-k\), allowing determination of the rate constant \( k \).
Other exercises in this chapter
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