Problem 39
Question
\(35-82\) Factor the expression completely. $$ x^{2}-2 x-8 $$
Step-by-Step Solution
Verified Answer
The expression factors to \((x - 4)(x + 2)\).
1Step 1: Understanding the Problem
The problem asks us to factor the expression \(x^2 - 2x - 8\). Factoring is the process of breaking down an expression into a product of simpler expressions. Our goal is to express the quadratic in the form \((x + a)(x + b)\).
2Step 2: Identify Coefficients
First, identify the coefficients of the quadratic expression: \(a = 1\) (the coefficient of \(x^2\)), \(b = -2\) (the coefficient of \(x\)), and \(c = -8\) (the constant term).
3Step 3: Finding Two Numbers
Find two numbers that multiply to \(ac\) (\(1 imes -8 = -8\)) and add to \(b\) (\(-2\)). These numbers are \(-4\) and \(2\), since \(-4 imes 2 = -8\) and \(-4 + 2 = -2\).
4Step 4: Rewrite and Group Terms
Rewrite the middle term \(-2x\) using the numbers found: \(x^2 - 4x + 2x - 8\). Group the terms into two pairs: \((x^2 - 4x) + (2x - 8)\).
5Step 5: Factor by Grouping
Factor out the greatest common factor from each pair: \(x(x - 4) + 2(x - 4)\). Observe that \(x - 4\) is a common factor.
6Step 6: Final Solution
Factor out the common term \(x - 4\) to get the final factorized form: \((x - 4)(x + 2)\). This is the completely factored expression.
Key Concepts
Quadratic ExpressionsFactoring by GroupingFinding CoefficientsFactoring Techniques
Quadratic Expressions
Quadratic expressions are polynomial expressions of degree two. They are typically written in the standard form as: \[ ax^2 + bx + c \] where:
- \(a\) is the coefficient of the \(x^2\) term,
- \(b\) is the coefficient of the \(x\) term,
- and \(c\) is the constant term, which does not involve \(x\).
Factoring by Grouping
Factoring by grouping is an effective method used to factor certain quadratic expressions. This approach involves rearranging and grouping terms so that they can be factored easily. The objective is to look for common factors within each group. For the expression \(x^2 - 2x - 8\), we need to express the middle term in such a way that the expression can be grouped into manageable pairs. We find a pair of numbers whose product is equal to the product of \(a\) and \(c\) (\(-8\)), and whose sum equals \(b\) (\(-2\)). Here, we use \(-4\) and \(2\) because \(-4 \times 2 = -8\) and \(-4 + 2 = -2\). This allows us to rewrite the quadratic expression as \(x^2 - 4x + 2x - 8\). Group and factor each pair: \((x^2 - 4x) + (2x - 8)\). Each group can now be factored separately.
Finding Coefficients
Finding coefficients accurately is the backbone of factoring any quadratic expression. Understanding how to determine these coefficients begins with observation of the quadratic expression in standard form. In \(x^2 - 2x - 8\), the coefficients are straightforward:
- \(a = 1\),
- \(b = -2\),
- and \(c = -8\).
Factoring Techniques
Several factoring techniques exist for solving quadratic expressions, each suited to varyingly structured problems. It is essential to choose the right one, as this can make the solution process more straightforward and correct. The technique used for \(x^2 - 2x - 8\) is 'factoring by grouping'. Its steps include:
- Identifying two numbers for multiplication and addition based on \(ac\) and \(b\).
- Rewriting the middle term with these numbers to form four terms.
- Grouping into pairs so each can be factored independently.
- Extracting the common factor from both pairs to complete the factorization.
Other exercises in this chapter
Problem 39
Perform the multiplication or division and simplify. $$ \frac{2 x^{2}+3 x+1}{x^{2}+2 x-15}+\frac{x^{2}+6 x+5}{2 x^{2}-7 x+3} $$
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\(29-46\) Simplify each expression. $$ \left(2 y^{2}\right)^{3} $$
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Express the inequality in interval notation, and then graph the corresponding interval. $$ x \leq 1 $$
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\(39-48=\) Simplify the expression. $$ \sqrt{32}+\sqrt{18} $$
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