Problem 386
Question
For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral \(\int_{S} \mathbf{F} \cdot \mathbf{n} d s\) for the given choice of \(\mathbf{F}\) and the boundary surface \(S\). For each closed surface, assume \(\mathbf{N}\) is the outward unit normal vector. Use the divergence theorem to calculate surface integral \(\iint_{S} \mathbf{F} \cdot d \mathbf{S},\) where \(\mathbf{F}(x, y, z)=x^{4} \mathbf{i}-x^{3} z^{2} \mathbf{j}+4 x y^{2} z \mathbf{k}\) and \(S\) is the surface bounded by cylinder \(x^{2}+y^{2}=1\) and planes \(z=x+2\) and \(z=0\)
Step-by-Step Solution
Verified Answer
Use cylindrical coordinates and evaluate the volume integral with CAS for the solution.
1Step 1: Understand the Divergence Theorem
The divergence theorem states that for a vector field \(\mathbf{F}\), \[ \iint_{S} \mathbf{F} \cdot d\mathbf{S} = \iiint_{V} abla \cdot \mathbf{F} \, dV \]where \(V\) is the volume enclosed by the surface \(S\). We will use this theorem to convert the surface integral into a volume integral.
2Step 2: Compute the Divergence of \(\mathbf{F}\)
To find \(abla \cdot \mathbf{F}\), compute the divergence of \(\mathbf{F}(x, y, z) = x^{4} \mathbf{i} - x^{3} z^{2} \mathbf{j} + 4xy^{2}z \mathbf{k}\):\[ abla \cdot \mathbf{F} = \frac{\partial}{\partial x}(x^4) + \frac{\partial}{\partial y}(-x^3 z^2) + \frac{\partial}{\partial z}(4 x y^2 z) \]Calculating each term, we find:- \(\frac{\partial}{\partial x}(x^4) = 4x^3\)- \(\frac{\partial}{\partial y}(-x^3 z^2) = 0\)- \(\frac{\partial}{\partial z}(4xy^2z) = 4xy^2\)Therefore, \(abla \cdot \mathbf{F} = 4x^3 + 4xy^2\).
3Step 3: Set Up the Volume Integral
The volume \(V\) is bounded by the cylinder \(x^2 + y^2 = 1\) and the planes \(z = x + 2\) and \(z = 0\). We need to integrate \(abla \cdot \mathbf{F}\) over this volume:\[ \iiint_{V} (4x^3 + 4xy^2) \, dV. \]
4Step 4: Choose the Coordinate System and Integrate
To simplify the integration, use cylindrical coordinates:- \(x = r \cos\theta\), \(y = r \sin\theta\), and \(z = z\).- The differential volume element \(dV = r\, dz\, dr\, d\theta\).- Limits for \(r\): from 0 to 1 (the radius of the cylinder).- Limits for \(\theta\): from 0 to \(2\pi\).- Limits for \(z\): from 0 to \(x + 2 = r\cos\theta + 2\).The integral becomes:\[\int_{0}^{2\pi}\int_{0}^{1}\int_{0}^{r\cos\theta+2} (4r^3 \cos^3\theta + 4r^3 \cos\theta \sin^2\theta) \, r \, dz \, dr \, d\theta.\]
5Step 5: Evaluate the Integral
Evaluate the integral step-by-step starting with the \(z\)-integral:\**Outer Integral:** \\(\int_{0}^{2\pi} \int_{0}^{1} \left[ 4r^3 z \cos^3\theta + 4r^3 z \cos\theta \sin^2\theta \right]_{0}^{r\cos\theta+2} \, r \, dr \, d\theta.\)Substitute the limits for \(z\) to simplify the integral before diving into further integration with respect to \(r\) and \(\theta\). Integrate over all limits and simplify to find the volume integral result. This will require calculation using a CAS tool.
Key Concepts
Surface IntegralVector FieldCylindrical CoordinatesVolume Integral
Surface Integral
Surface integrals are used to calculate the flow of a vector field across a surface. When you have a surface \( S \) and a vector field \( \mathbf{F} \), the surface integral \( \iint_{S} \mathbf{F} \cdot d \mathbf{S} \) measures how much of \( \mathbf{F} \) crosses \( S \). This helps in understanding qualities like fluid flow across a barrier.
The symbol \( d\mathbf{S} \) represents the infinitesimal element of the surface with direction given by the unit normal vector. When this integral is computed over a closed surface, like a cylinder, you can use the Divergence Theorem for simplification. This theorem can transform a complicated surface integral into a more manageable volume integral.
Performing the surface integral directly can be challenging because it requires parameterizing the surface. This often involves complex calculations, which the Divergence Theorem helps avoid.
The symbol \( d\mathbf{S} \) represents the infinitesimal element of the surface with direction given by the unit normal vector. When this integral is computed over a closed surface, like a cylinder, you can use the Divergence Theorem for simplification. This theorem can transform a complicated surface integral into a more manageable volume integral.
Performing the surface integral directly can be challenging because it requires parameterizing the surface. This often involves complex calculations, which the Divergence Theorem helps avoid.
Vector Field
A vector field assigns a vector to every point in space. In mathematical terms, if you have vectors \( \mathbf{F}(x, y, z) = x^{4} \mathbf{i}-x^{3} z^{2} \mathbf{j}+4 x y^{2} z \mathbf{k} \), these vectors have different magnitudes and directions based on their position.
In our case, \( \mathbf{F} \) is defined by three components: one in the direction of the x-axis, another in the direction of the y-axis, and the third in the z-direction. Let's break it down:
In our case, \( \mathbf{F} \) is defined by three components: one in the direction of the x-axis, another in the direction of the y-axis, and the third in the z-direction. Let's break it down:
- \( x^4 \mathbf{i} \): impacts the x-direction, growing rapidly for larger \( x \).
- -\( x^3 z^2 \mathbf{j} \): affects the y-direction, changes based on both \( x \) and \( z \).
- \( 4xy^2z \mathbf{k} \): operates in the z-direction, dependent on \( x \), \( y \), and \( z \).
Cylindrical Coordinates
In cylindrical coordinates, a point in three-dimensional space is determined by the radius \( r \), angle \( \theta \), and height \( z \). This system is particularly useful for surfaces like cylinders or objects with rotational symmetry.
Cylindrical coordinates relate to Cartesian coordinates by:
This transformation is handy for integrals involving cylindrical shapes, as it simplifies the boundary conditions and volume element. The volume element in cylindrical coordinates is \( dV = r \, dz \, dr \, d\theta \).
When integrating over a cylinder or anything cylindrical, you set your integration limits based on the conditions of \( r \), \( \theta \), and \( z \). This makes evaluating the integral more manageable, especially with the boundaries given by rotations or heights.
Cylindrical coordinates relate to Cartesian coordinates by:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
- \( z = z \)
This transformation is handy for integrals involving cylindrical shapes, as it simplifies the boundary conditions and volume element. The volume element in cylindrical coordinates is \( dV = r \, dz \, dr \, d\theta \).
When integrating over a cylinder or anything cylindrical, you set your integration limits based on the conditions of \( r \), \( \theta \), and \( z \). This makes evaluating the integral more manageable, especially with the boundaries given by rotations or heights.
Volume Integral
A volume integral computes the cumulative effect of a function throughout a volume. For vector fields and the Divergence Theorem's applications, you want to integrate the divergence of a vector field over the volume bounded by a surface.
The divergence \( abla \cdot \mathbf{F} \) calculates how much the vector field spreads out from a point. In our example, \( abla \cdot \mathbf{F} = 4x^3 + 4xy^2 \), integrating this over a defined volume gives insight into total field behaviour inside that space.
You do this by transitioning:
The divergence \( abla \cdot \mathbf{F} \) calculates how much the vector field spreads out from a point. In our example, \( abla \cdot \mathbf{F} = 4x^3 + 4xy^2 \), integrating this over a defined volume gives insight into total field behaviour inside that space.
You do this by transitioning:
- Set up the integral \( \iiint_{V} (4x^3 + 4xy^2) \, dV \),
- Apply cylindrical coordinates to simplify,
- Adjust limits for \( r, \theta, \) and \( z \) based on the geometric constraints (cylinder and planes in this case).
Other exercises in this chapter
Problem 383
For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral \(\int_{S} \mathbf{F} \cdot \mathbf{n
View solution Problem 384
For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral \(\int_{S} \mathbf{F} \cdot \mathbf{n
View solution Problem 387
For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral \(\int_{S} \mathbf{F} \cdot \mathbf{n
View solution Problem 388
For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral \(\int_{S} \mathbf{F} \cdot \mathbf{n
View solution