Problem 38
Question
Write with positive exponents. Simplify if possible. $$ \frac{1}{n^{-8 / 9}} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \( n^{8/9} \).
1Step 1: Recognize the Negative Exponent
The expression given is \( \frac{1}{n^{-8/9}} \). \( n^{-8/9} \) has a negative exponent. Recall that a negative exponent indicates a reciprocal: \( a^{-b} = \frac{1}{a^b} \).
2Step 2: Convert to Positive Exponent
Apply the rule for negative exponents. \( n^{-8/9} = \frac{1}{n^{8/9}} \). Substituting in the expression gives \( \frac{1}{n^{-8/9}} = \frac{1}{\frac{1}{n^{8/9}}} \).
3Step 3: Simplify the Expression
Simplify \( \frac{1}{\frac{1}{n^{8/9}}} \) by recognizing it as a complex fraction. Simplify using the rule \( \frac{a}{\frac{b}{c}} = a \cdot \frac{c}{b} \). In this case, it simplifies to \( n^{8/9} \).
Key Concepts
Negative ExponentsReciprocal RuleSimplifying Expressions
Negative Exponents
When you see a negative exponent, it might look a bit confusing at first. The main thing to remember is that a negative exponent indicates something very special: an inverse or reciprocal.
For example, when you see something like \( n^{-b} \), it simply means that the base \( n \) is on the bottom of a fraction, and its exponent becomes positive: \( n^{-b} = \frac{1}{n^b} \).
This transformation allows us to convert any negative exponent into a more typical positive exponent form, making calculations much simpler.
For example, when you see something like \( n^{-b} \), it simply means that the base \( n \) is on the bottom of a fraction, and its exponent becomes positive: \( n^{-b} = \frac{1}{n^b} \).
This transformation allows us to convert any negative exponent into a more typical positive exponent form, making calculations much simpler.
- Understanding that negative exponents are not scary at all is key; it's just about flipping the base across the fraction line.
- By converting to positive exponents, you make the math easier to handle.
Reciprocal Rule
The Reciprocal Rule is closely tied to negative exponents. It helps us understand how to simplify expressions, especially when dealing with fractions.
When a number or variable is raised to a negative exponent, it implies that the base is dividing 1.
So, if you see \( a^{-b} \), the reciprocal rule tells us that you can express this as \( \frac{1}{a^b} \). This swaps the position of the base \( a \) from the numerator to the denominator (or vice versa if needed).
When a number or variable is raised to a negative exponent, it implies that the base is dividing 1.
So, if you see \( a^{-b} \), the reciprocal rule tells us that you can express this as \( \frac{1}{a^b} \). This swaps the position of the base \( a \) from the numerator to the denominator (or vice versa if needed).
- It's all about inverting the position of the base to deal with negative exponents effectively.
- For instance, \( n^{-8/9} \) becomes \( \frac{1}{n^{8/9}} \) using this rule.
Simplifying Expressions
After dealing with negative exponents and applying the reciprocal rule, the next step is simplifying expressions. This often involves organizing and reducing mathematical expressions to their simplest form.
In our example, after changing \( n^{-8/9} \) to a positive exponent form \( \frac{1}{n^{8/9}} \), we find ourselves with a complex fraction \( \frac{1}{\frac{1}{n^{8/9}}} \). Simplifying expressions like these can be tricky, but there's a straightforward method: multiply by the reciprocal.
In our example, after changing \( n^{-8/9} \) to a positive exponent form \( \frac{1}{n^{8/9}} \), we find ourselves with a complex fraction \( \frac{1}{\frac{1}{n^{8/9}}} \). Simplifying expressions like these can be tricky, but there's a straightforward method: multiply by the reciprocal.
- Remember that for \( \frac{1}{\frac{b}{c}} \), you can simplify it by calculating \( c \cdot \frac{1}{b} \).
- By using this approach, \( \frac{1}{\frac{1}{n^{8/9}}} \) simplifies just to \( n^{8/9} \).
Other exercises in this chapter
Problem 38
Solve. $$ \sqrt{3 y+6}=\sqrt{7 y-6} $$
View solution Problem 38
Rationalize each denominator. Assume that all variables represent positive real numbers. \(\frac{2 \sqrt{a}-3}{2 \sqrt{a}-\sqrt{b}}\)
View solution Problem 38
Add or subtract as indicated. Assume that all variables represent positive real numbers. $$ \frac{\sqrt[4]{48}}{5 x}-\frac{2 \sqrt[4]{3}}{10 x} $$
View solution Problem 38
Multiply. Write your answers in the form \(a+b i\). $$ 5 i(4-7 i) $$
View solution