Problem 38
Question
Write names for the following coordination compounds: (a) \(\mathrm{Na}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NO}\right]\) (b) \(\left[\mathrm{CoO}\left(\mathrm{NH}_{3}\right)_{5}\right] \mathrm{Br}\) (c) \(\mathrm{Na}_{2}\left[\mathrm{NiBr}_{4}\right]\) (d) \(\left[\mathrm{Rh}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]_{3}\)
Step-by-Step Solution
Verified Answer
The names for the coordination compounds are:
(a) Pentaamminecyanidonitrosyliron(III)
(b) Pentaammineoxocobalt(III) bromide
(c) Tetrabromidonickel(II) sodium
(d) Hexaaquarhodium(III) tris(dicyanoargentate(I))
1Step 1: (a) Naming Na3[Fe(CN)5NO]
First, identify the metal and its oxidation state. In this compound, the metal is iron (Fe). The ligands include five cyanides (CN-) and one nitrosyl (NO). The total charge of the coordination complex is -3, as there are three sodium ions (Na+) in the compound. Iron's oxidation state is +3, which balances the charge. The name for the coordination compound is then:
Pentaamminecyanidonitrosyliron(III)
2Step 2: (b) Naming [CoO(NH3)5]Br
Identify the metal and its oxidation state. In this compound, the metal is cobalt (Co). The ligands include one oxide (O2-) and five ammonia (NH3) molecules. The total charge of the coordination complex is +1, as there is one bromide ion (Br-) in the compound. Cobalt's oxidation state is +3, which balances the charge. The name for the coordination compound is:
Pentaammineoxocobalt(III) bromide
3Step 3: (c) Naming Na2[NiBr4]
Identify the metal and its oxidation state. In this compound, the metal is nickel (Ni). The ligands include four bromides (Br-). The total charge of the coordination complex is -2, as there are two sodium ions (Na+) in the compound. Nickel's oxidation state is +2, which balances the charge. The name for the coordination compound is:
Tetrabromidonickel(II) sodium
4Step 4: (d) Naming [Rh(H2O)6][Ag(CN)2]3
In this compound, there are two coordination complexes: [Rh(H2O)6] and [Ag(CN)2].
Identify the metal and its oxidation state in [Rh(H2O)6]. The metal is rhodium (Rh), and the ligands include six water (H2O) molecules. The charge of this complex is +3, which gives Rh an oxidation state of +3. The name for this coordination complex is:
Hexaaquarhodium(III)
Identify the metal and its oxidation state in [Ag(CN)2]. The metal is silver (Ag), and the ligands include two cyanides (CN-). The charge of this complex is -1, which gives Ag an oxidation state of +1. The name for this coordination complex is:
Dicyanoargentate(I)
Putting both names together, the name for the full coordination compound is:
Hexaaquarhodium(III) tris(dicyanoargentate(I))
Key Concepts
Ligand NamingOxidation State DeterminationComplex Ion Formation
Ligand Naming
In coordination chemistry, ligands play a crucial role, working as donor molecules that attach to the central metal atom or ion. Naming these ligands correctly is important to accurately describe the coordination compound. Ligands can be anions, neutral molecules, or even cations. To ensure clarity, different types of ligands follow specific naming rules.
- Anionic ligands: These often end in '-o'. For example, a chloride ion (Cl-) is named chloro, and a cyanide ion (CN-) is cyano.
- Neutral ligands: These are usually called by their common names, such as "aqua" for water (H2O) and "ammine" for ammonia (NH3).
- Cationic ligands: These are rare but follow similar rules to anionic and neutral ligands.
Oxidation State Determination
Determining the oxidation state of the central metal atom or ion in a coordination compound is a vital aspect. The oxidation state provides key information about the electronic state and overall charge balance within the coordination compound.
In step-by-step terms:
In step-by-step terms:
- Summing Up Ligand Charges: Begin by adding up the charges provided by each ligand. For instance, the cyanides (CN-) each contribute a charge of -1.
- Determining the Overall Charge: Next, look at the overall charge of the coordination complex bracketed entity. For example, a coordination complex with a charge of -3 signifies that the sum of all components must equal -3.
- Calculating Metal Charge: Using the known charge on the ligands and the overall charge of the complex, solve for the oxidation state of the metal. For Na3[Fe(CN)5NO], with a complex charge of -3, and knowing each CN- is -1 and NO is neutral, iron's oxidation state calculates to +3.
Complex Ion Formation
Complex ion formation occurs when ligands attach to a central metal atom or ion, creating a structured complex that behaves as a single charged entity in solution. This formation is key to the unique properties and functionality of coordination compounds.
- Central Metal Atom: This is usually a transition metal that can accept electrons from the ligands because of its availability of d-orbitals.
- Ligands: These molecules or ions donate at least one pair of electrons to form a coordinate covalent bond with the metal. Their arrangement around the metal atom creates the geometry of the complex, such as octahedral, tetrahedral, or square planar.
- Coordination Number: This signifies the number of ligand donor atoms bonded to the central metal atom. For example, in [Rh(H2O)6][Ag(CN)2]3, rhodium has a coordination number of 6, indicating an octahedral arrangement.
Other exercises in this chapter
Problem 36
Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexaammineiron(II) nitrate (b) tetraa
View solution Problem 37
Write the names of the following compounds, using the standard nomenclature rules for coordination complexes: (a) \(\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right
View solution Problem 39
Consider the following three complexes: \(\left(\right.\) Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Cl}\) 2)
View solution Problem 40
Consider the following three complexes: \(\left(\right.\) Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\) \(\left(\rig
View solution