Problem 38
Question
When a hydrogen atom is bombared, the atom is excited to then \(n=4\) state. The energy released, when the atom goes from \(n=4\) state to the ground state is (a) \(1.75 \mathrm{eV}\) (b) \(12.75 \mathrm{eV}\) (c) \(5 \mathrm{eV}\) (d) \(8 \mathrm{eV}\)
Step-by-Step Solution
Verified Answer
The energy released is 12.75 eV, so the answer is (b) \(12.75\, \mathrm{eV}\).
1Step 1: Understanding the Energy Levels
The energy levels of a hydrogen atom are given by the formula \( E_n = -13.6 \frac{1}{n^2} \) eV, where \( n \) is the principal quantum number of the energy level. The ground state energy (\( n=1 \)) is \( -13.6 \) eV.
2Step 2: Calculating Energy for n=4
Calculate the energy of the hydrogen atom when it is in the \( n=4 \) state using the formula: \( E_4 = -13.6 \frac{1}{4^2} = -13.6 \frac{1}{16} = -0.85 \) eV.
3Step 3: Calculating the Energy Difference
The energy released when an excited atom transitions from a higher energy level \( n=4 \) to a lower energy level \( n=1 \) (ground state) is the difference in energy levels: \( E = E_1 - E_4 \). Substitute the values to get \( E = -13.6 - (-0.85) = -13.6 + 0.85 = -12.75 \) eV.
4Step 4: Converting Negative Energy
The negative sign in the calculated energy indicates the energy is released. We calculate the absolute value of energy released: \( |12.75| = 12.75 \) eV.
5Step 5: Selecting the Correct Answer
The amount of energy released in eV is 12.75. Thus, the correct choice is option (b) \( 12.75 \) eV.
Key Concepts
Quantum NumbersEnergy TransitionAtomic Physics
Quantum Numbers
Quantum numbers are fundamental in understanding the hydrogen atom's behavior. They describe the specific characteristics of electrons within an atom. There are four types of quantum numbers:
- Principal quantum number ( ): It signifies the energy level of an electron. In the given problem, the hydrogen atom transitions from a higher energy level ( =4) to the ground state ( =1).
- Azimuthal quantum number ( abla): It defines the shape of an orbital.
- Magnetic quantum number ( abla_m): It specifies the orientation of the orbital.
- Spin quantum number ( abla_s): It represents the spin direction of the electron.
Energy Transition
Energy transition in atomic physics refers to the change in energy levels of an atom's electron. This phenomenon is observable in spectroscopy, where emitted or absorbed light corresponds to these transitions.
In our case, we have a hydrogen atom initially excited to a higher energy state (=4). When this electron returns to the ground state (=1), it releases energy. This energy is calculated using the formula for energy levels: \[ E_n = -13.6 \times \frac{1}{n^2} \text{ eV} \]
Calculating for =4 and =1, we find:
In our case, we have a hydrogen atom initially excited to a higher energy state (=4). When this electron returns to the ground state (=1), it releases energy. This energy is calculated using the formula for energy levels: \[ E_n = -13.6 \times \frac{1}{n^2} \text{ eV} \]
Calculating for =4 and =1, we find:
- For =4, the energy is \(-0.85\) eV.
- For =1, the energy is \(-13.6\) eV.
Atomic Physics
Atomic physics is the study of atoms, focusing on their components and interactions. It plays a crucial role in explaining phenomena like energy transitions in hydrogen.
Key elements of atomic physics include:
Atomic physics not only helps in understanding these microscopic interactions but also explains larger phenomena like emission lines in atomic spectra. For hydrogen, these transitions and energy level calculations serve fundamental roles in disciplines ranging from quantum mechanics to astrophysics.
Key elements of atomic physics include:
- Electrons: Orbit around the nucleus in specific energy levels.
- Protons and Neutrons: Compose the nucleus itself.
Atomic physics not only helps in understanding these microscopic interactions but also explains larger phenomena like emission lines in atomic spectra. For hydrogen, these transitions and energy level calculations serve fundamental roles in disciplines ranging from quantum mechanics to astrophysics.
Other exercises in this chapter
Problem 37
What is the de-Broglie wavelength of a nitrogen molecule in air at \(300 \mathrm{~K}\) ? Assume that the molecule is moving with the root-mean-square speed of m
View solution Problem 37
A nucleus of \({ }_{84} \mathrm{Po}^{210}\) originally at rest emits an \(\alpha\)-particle with speed \(v\). What will be recoil speed of the daughter nucleus?
View solution Problem 38
The radioactivity isotope \(X\) with a half-life of \(10^{9}\) year decays to \(Y\) which is stable. A sample of rocks were found to contain both the elements \
View solution Problem 39
An electron jumps from the 4 th orbit to 2 nd orbit of hydrogen atom. Given the Rydberg's constant \(R=10^{5} \mathrm{~cm}^{-1}\), the frequency in hertz of the
View solution