Problem 38
Question
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. \(x\) -intercept \(=4\) and \(y\) -intercept \(=-2\)
Step-by-Step Solution
Verified Answer
The equation of the line in point-slope form is \(y = 0.5(x-4)\) and in slope-intercept form is \(y = 0.5x - 2\)
1Step 1: Calculate the Slope
The formula to find the slope (m) given two points (x1,y1) and (x2,y2) is: \(m = \frac{y2 - y1}{x2 - x1}\). In this case, the two points are the x and y intercepts: (4,0) and (0,-2). When these points are inserted into the slope equation, the slope (m) equals: \[m = \frac{-2 - 0}{0 - 4} = 0.5\]
2Step 2: Write the equation in point-slope form
The point-slope form of a line is \(y - y1 = m(x - x1)\). Replacing \(m = 0.5\) and choosing any of the two points, preferentially the one with the least complex numbers, let's choose (4,0), the point-slope form of the line will be: \(y - 0 = 0.5(x - 4)\)
3Step 3: Write the equation in slope-intercept form
The slope-intercept form is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. The line can be rewritten from point-slope form to get it into slope-intercept form: \[y = 0.5x -2\].
Key Concepts
Understanding Point-Slope FormExploring Slope-Intercept FormUnderstanding Intercepts
Understanding Point-Slope Form
The point-slope form is a way to represent the equation of a line using the slope and a single point on the line. It's written as:
For example, if we have a line that passes through the point (4,0) with a slope of 0.5, the point-slope form becomes:
\( y - 0 = 0.5(x - 4) \).
This form is particularly useful for quickly forming an equation when both the slope and a point are known.
- \( y - y_1 = m(x - x_1) \)
- \( m \) is the slope.
- \( (x_1, y_1) \) is a point on the line.
For example, if we have a line that passes through the point (4,0) with a slope of 0.5, the point-slope form becomes:
\( y - 0 = 0.5(x - 4) \).
This form is particularly useful for quickly forming an equation when both the slope and a point are known.
Exploring Slope-Intercept Form
The slope-intercept form of a line is a straightforward and popular way to write a line's equation. It is represented as:
In our example, transforming the equation \( y - 0 = 0.5(x - 4) \) to the slope-intercept form gives us \( y = 0.5x - 2 \), highlighting both the slope and where it crosses the y-axis.
- \( y = mx + b \)
- \( m \) is the slope of the line.
- \( b \) is the y-intercept, the point where the line crosses the y-axis.
In our example, transforming the equation \( y - 0 = 0.5(x - 4) \) to the slope-intercept form gives us \( y = 0.5x - 2 \), highlighting both the slope and where it crosses the y-axis.
Understanding Intercepts
Intercepts are the points where a line crosses the axes. They are helpful in understanding and graphing the behavior of lines.**X-Intercept**The x-intercept is where the line crosses the x-axis. At this point:
**Y-Intercept**Similarly, the y-intercept is where the line crosses the y-axis. Here:
Knowing the intercepts gives you solid foundation points while graphing a line, making it easier to see the line's position and slope.
- The value of \( y \) is zero.
**Y-Intercept**Similarly, the y-intercept is where the line crosses the y-axis. Here:
- The value of \( x \) is zero.
Knowing the intercepts gives you solid foundation points while graphing a line, making it easier to see the line's position and slope.
Other exercises in this chapter
Problem 37
Write the standard form of the equation of the circle with the given center and radius. $$ \text { Center }(-3,-1), r=\sqrt{3} $$
View solution Problem 38
Begin by graphing the standard cubic function, \(f(x)=x^{3} .\) Then use transformations of this graph to graph the given function. $$ g(x)=(x-2)^{3} $$
View solution Problem 38
Find: a. \((f \circ g)(x)\) b. the domain of \(f \circ g\) $$f(x)=9-x^{2}, g(x)=\sqrt{x^{2}-9}$$
View solution Problem 38
In Exercises \(33-44\), find and simplify the difference quotient $$\frac{f(x+h)-f(x)}{h}, h \neq 0$$for the given function. $$f(x)=2 x^{2}$$
View solution