Problem 38
Question
Use one or more of the basic trigonometric identities to derive the given identity. \(\sin (\theta) \sin (\phi)=\frac{\cos (\theta-\phi)-\cos (\theta+\phi)}{2}\)
Step-by-Step Solution
Verified Answer
The identity is derived using the product-to-sum identity for sine.
1Step 1: Use Product-to-Sum Identity for Sine
The product-to-sum identities relate the product of trigonometric functions to a sum or difference. For sine, the identity is: \[\sin(a)\sin(b)=\frac{1}{2}[\cos(a-b)-\cos(a+b)].\] Set \(a = \theta\) and \(b = \phi\).
2Step 2: Apply Values to Identity
Substitute \(a = \theta\) and \(b=\phi\) into the product-to-sum identity:\[\sin(\theta)\sin(\phi) = \frac{1}{2}[\cos(\theta-\phi)-\cos(\theta+\phi)].\]
3Step 3: Confirm Derived Equation
The derived expression matches the original identity to be proven: \[\sin(\theta)\sin(\phi) = \frac{\cos(\theta-\phi)-\cos(\theta+\phi)}{2}.\]
Key Concepts
Understanding the Sine FunctionExploring Product-to-Sum IdentitiesDecoding the Cosine Function
Understanding the Sine Function
The sine function is a fundamental component of trigonometry, closely linked to the geometry of right-angled triangles. In its simplest form, the sine of an angle in a right triangle is the ratio of the length of the side opposite the angle to the length of the hypotenuse. When dealing with angles in standard position on the unit circle, the sine function gives the y-coordinate of the point where the terminal side of the angle intersects the circle.
- Right Triangle Definition: If you have a right triangle, the sine of an angle \( \theta \) is given by \( \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \).
- Unit Circle Definition: On the unit circle, \( \sin(\theta) \) is the y-coordinate of the point at angle \( \theta \).
Exploring Product-to-Sum Identities
Product-to-sum identities are useful trigonometric formulas that simplify the multiplication of trigonometric functions into sums or differences. For sine functions, the specific identity used is:\[\sin(a)\sin(b) = \frac{1}{2}(\cos(a-b) - \cos(a+b))\] This transformation is effective when solving complex trigonometric equations or proving identities.
- Purpose: These identities allow us to express products as manageable sums or differences, making complex calculations more accessible and simplifying integration and other mathematical operations.
- Applications: They are often applied in physics and engineering to solve oscillatory systems and in signal processing.
Decoding the Cosine Function
The cosine function is another cornerstone of trigonometry, offering a way to relate angles and side lengths in triangles. Similar to the sine function, the cosine of an angle in a right triangle is known from its definition as the ratio of the adjacent side to the hypotenuse. In the unit circle scenario, the cosine function provides the x-coordinate of a point on the circle.
- Right Triangle Definition: For a right triangle, \( \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \).
- Unit Circle Definition: On the unit circle, \( \cos(\theta) \) corresponds to the x-coordinate of the point at angles measured from the positive x-axis.
Periodicity and Applications
The cosine function is periodic with a period of \( 2\pi \), making it pivotal in modeling periodic phenomena such as sound and light waves. Its symmetry and relationship with the sine function (\( \cos(\theta) = \sin(\theta + \frac{\pi}{2}) \)) are often used to manipulate expressions and solve trigonometric equations.Other exercises in this chapter
Problem 37
Sketch the set on a real number line. \(\\{y: y-\sqrt{7}
View solution Problem 38
A function \(f: S \rightarrow T\) is specified. Determine if \(f\) is invertible. If it is, state the formula for \(f^{-1}(t) .\) Otherwise, state whether \(f\)
View solution Problem 38
Sketch the given region. \(\\{(x, y):|x| \leq 5,|y|>2\\}\)
View solution Problem 38
A general linear equation of a line is given. Find the \(x\) -intercept, the \(y\) -intercept, and the slope of the line. $$ x / 2+2 y=4 $$
View solution