Problem 38
Question
Use a vertical format to add or subtract. $$ \left(4 x^{2}-7 x+2\right)+\left(-x^{2}+x-2\right) $$
Step-by-Step Solution
Verified Answer
The simplified form of the given algebraic expression is \(3x^{2} - 6x\).
1Step 1: Identification of Like Terms
Like terms in an expression are terms with exactly the same variable factors. So in this case, \(4x^{2}\) and \(-x^{2}\) are like terms, \(-7x\) and \(x\) are like terms, and \(2\) and \(-2\) are like terms.
2Step 2: Addition/Subtraction of Like Terms
Once like terms are identified, the coefficients of those terms are added or subtracted based on the operation between them. Here, we add or subtract the coefficients of the like terms identified in Step 1: \( (4x^{2} - x^{2}),\) \((-7x + x)\), and \( (2 - 2) \).
3Step 3: Simplification
When the addition or subtraction of like terms is done, simplify the expression. In our case, simplifying yields: \( 3x^{2} - 6x + 0\) or \( 3x^{2} - 6x\).
Key Concepts
Like TermsAddition of PolynomialsSubtraction of Polynomials
Like Terms
When dealing with polynomials, understanding like terms is crucial for simplifying expressions. Like terms have the same variables raised to the same power. For instance, in the expression \(4x^{2} - 7x + 2\), both \(4x^{2}\) and \(-x^{2}\) are like terms because they each have the variable \(x\) squared. Similarly, \(-7x\) and \(x\) are like terms because they both have the variable \(x\) raised to the first power. Furthermore, constant terms like \(2\) and \(-2\), which have no variable part, are also considered like terms.
In general, when identifying like terms in any polynomial expression, focus on these characteristics:
In general, when identifying like terms in any polynomial expression, focus on these characteristics:
- The variable component must match exactly.
- The exponent of the variable must be the same for the terms.
- Only the coefficients in front of the terms are added or subtracted.
Addition of Polynomials
The addition of polynomials is straightforward when like terms have been identified. This process involves adding up the coefficients of the like terms while keeping the variable part unchanged. Let's take the problem: \( (4x^{2}-7x+2)+(-x^{2}+x-2) \). First, align the polynomials so that like terms are positioned in the same column:
- \(4x^{2}\)
- \(-7x\)
- \(+2\)
- \(-x^{2}\)
- \(+x\)
- \(-2\)
- For \(x^{2}\) terms: \(4x^{2} + (-x^{2}) = 3x^{2}\).
- For \(x\) terms: \(-7x + x = -6x\).
- For constants: \(2 + (-2) = 0\).
Subtraction of Polynomials
Subtracting polynomials can be seen as adding the opposite. This means that when subtracting, you distribute a minus sign (effectively changing the signs) across the terms of the polynomial being subtracted. Consider the expressions: \(4x^{2} - 7x + 2\) and \(-x^{2} + x - 2\). If you want to subtract, you change the signs of the second polynomial:
- \(-x^{2}\) becomes \(+x^{2}\)
- \(+x\) becomes \(-x\)
- \(-2\) becomes \(+2\)
- \(4x^{2} - 7x + 2 + x^{2} - x + 2\)
- Combine \(x^{2}\) terms: \(4x^{2} + x^{2} = 5x^{2}\).
- Combine \(x\) terms: \(-7x - x = -8x\).
- Combine constant terms: \(2 + 2 = 4\).
Other exercises in this chapter
Problem 38
Factor the trinomial. $$ 14 y^{2}-15 y+4 $$
View solution Problem 38
PERFECT SQUARES Factor the expression. $$ x^{2}+12 x y+36 y^{2} $$
View solution Problem 38
Factor the expression completely. \(5 s^{3}+30 s^{2}+40 s\)
View solution Problem 38
Solve the equation by factoring. $$ c^{2}+10 c-48=12 c $$
View solution