Problem 38
Question
The ions of \(\mathrm{NaF}\) and \(\mathrm{MgO}\) all have the same number of electrons, and the internuclear distances are about the same ( \(235 \mathrm{pm}\) and \(212 \mathrm{pm}\) ). Why, then, are the melting points of \(\mathrm{NaF}\) and \(\mathrm{MgO}\) so different \(\left(992{ }^{\circ} \mathrm{C}\right.\) and \(2825^{\circ} \mathrm{C},\) respectively \() ?\)
Step-by-Step Solution
Verified1Step 1: Understanding the Scenario
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2Step 2: Radius Equilibrium & Covalent Bond
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Key Concepts
Ionic CompoundsElectron ConfigurationIonic Bonding Strength
Ionic Compounds
Ionic compounds are substances formed by the chemical bonding of ions, which are atoms or molecules carrying a positive or negative charge. They typically form when metals transfer electrons to non-metals, creating a strong electrostatic attraction between the positively charged cations and the negatively charged anions.
This attraction is known as ionic bonding.
Some key characteristics of ionic compounds include:
This attraction is known as ionic bonding.
Some key characteristics of ionic compounds include:
- High melting and boiling points due to the strong attraction between ions.
- Brittle nature, as the rigid arrangement of ions can cause the compound to shatter under stress.
- Conductivity in a molten state or when dissolved in water, because the movement of ions carries electrical current.
Electron Configuration
The electron configuration of an ion or atom refers to the distribution of its electrons in atomic or molecular orbitals. Understanding electron configurations provides insight into how ions are formed during chemical reactions, particularly ionic bonds.
For example, in both \(acl\) and \(mgo\), the ions have similar electron configurations after the transfer of electrons. In \(\text{NaF}\), sodium transfers one electron to fluorine, resulting in the electron configuration of \(\mathrm{Ne}\), the nearest noble gas. Similarly, in \(\mathrm{MgO}\), magnesium transfers two electrons to oxygen, also achieving a noble gas configuration, like \(\mathrm{Ne}\).
Key points to understand include:
For example, in both \(acl\) and \(mgo\), the ions have similar electron configurations after the transfer of electrons. In \(\text{NaF}\), sodium transfers one electron to fluorine, resulting in the electron configuration of \(\mathrm{Ne}\), the nearest noble gas. Similarly, in \(\mathrm{MgO}\), magnesium transfers two electrons to oxygen, also achieving a noble gas configuration, like \(\mathrm{Ne}\).
Key points to understand include:
- Electron transfer generates ions that achieve a more stable, lower energy state.
- Noble gases’ electron configuration is often a target due to its stability.
- Understanding electron configurations helps predict the structure and reactivity of ionic compounds.
Ionic Bonding Strength
The strength of ionic bonding is a fundamental concept determining the properties of ionic compounds, such as their melting points and solubility. This strength primarily depends on the charges of the ions and the distances between them.
For instance, the ionic bond in \(\mathrm{MgO}\) is stronger than in \(\mathrm{NaF}\) due to a few reasons:
For instance, the ionic bond in \(\mathrm{MgO}\) is stronger than in \(\mathrm{NaF}\) due to a few reasons:
- The charge on the magnesium ion \(\mathrm{Mg^{2+}}\) is higher than the charge on the sodium ion \(\mathrm{Na^{+}}\). This increases the attraction to the oxide ion \(\mathrm{O^{2-}}\) compared to the fluoride ion \(\mathrm{F^{-}}\).
- Even though both compounds have similar inter-nuclear distances, the higher charge in \(\mathrm{MgO}\) contributes to stronger bonds.
- Stronger ionic bonds generally result in higher melting points, as more energy is required to break the powerful attractions between ions.
Other exercises in this chapter
Problem 34
The fusion enthalpy for \(\mathrm{H}_{2} \mathrm{O}\) is about 2.5 times larger than the fusion enthalpy for \(\mathrm{H}_{2} \mathrm{~S}\). What does this say
View solution Problem 37
The chlorofluorocarbon \(\mathrm{CCl}_{2} \mathrm{~F}_{2}\) was once used as a refrigerant. Calculate what mass of this substance must evaporate to freeze \(2 \
View solution Problem 39
For the pair of compounds \(\mathrm{LiF}\) and \(\mathrm{CsI},\) tell which compound is expected to have the higher melting point and briefly explain why.
View solution Problem 40
Which of these substances has the highest melting point? The lowest melting point? Explain your choices briefly. (a) \(\mathrm{LiBr}\) (b) \(\mathrm{CaO}\) (c)
View solution