Problem 38
Question
Solve each of the following verbal problems algebraically. You may use either a one or a two-variable approach. A certain mutual fund contains 100 stocks. On a certain day all of the stocks changed price. Three times the number of stocks that went up is 14 more than 8 times the number of stocks that went down. Find how many stocks went up and how many went down.
Step-by-Step Solution
Verified Answer
74 stocks went up, 26 stocks went down.
1Step 1: Define the Variables
Let the number of stocks that went up be represented by \( x \), and the number of stocks that went down be represented by \( y \).
2Step 2: Set Up the Equation for Total Stocks
We know the total number of stocks is 100. This gives us the equation:\[ x + y = 100 \]
3Step 3: Set Up the Relationship Between Stocks
Three times the number of stocks that went up is 14 more than 8 times the number of stocks that went down. This can be written as:\[ 3x = 8y + 14 \]
4Step 4: Solve the System of Equations
We have two equations: 1. \( x + y = 100 \) 2. \( 3x = 8y + 14 \)First, solve the first equation for \( y \):\[ y = 100 - x \]Now, substitute \( y = 100 - x \) into the second equation:\[ 3x = 8(100 - x) + 14 \]
5Step 5: Simplify and Solve for x
Distribute and simplify the equation:\[ 3x = 800 - 8x + 14 \]Combine like terms:\[ 3x + 8x = 814 \]\[ 11x = 814 \]Solve for \( x \):\[ x = \frac{814}{11} \]\[ x = 74 \]
6Step 6: Find the Value of y
Substitute \( x = 74 \) back into the equation \( y = 100 - x \):\[ y = 100 - 74 \]\[ y = 26 \]
7Step 7: Conclusion
The number of stocks that went up is 74, and the number of stocks that went down is 26.
Key Concepts
System of EquationsVariable DefinitionSolving Equations Step-by-Step
System of Equations
A system of equations involves solving two or more equations that share common variables. When dealing with algebra word problems, these systems help us find the relationship between different quantities. In our example, the total number of stocks and how they changed in price are related.
- The first equation tells us the sum of two variables: the number of stocks that went up and the number of stocks that went down.
- The second equation tells us how these variables relate in another way: three times the number of stocks that went up is equal to 14 more than eight times the number of stocks that went down.
Variable Definition
Defining variables is one of the core steps in solving algebra word problems. It involves assigning symbols (usually letters) to represent unknown quantities. In the given exercise, we used two variables:
- Let the number of stocks that went up be represented by \( x \).
- Let the number of stocks that went down be represented by \( y \).
Solving Equations Step-by-Step
To solve the system of equations, it is essential to follow a sequence of steps. Here’s a breakdown:
- Step 1: Define the Variables - Set \( x \) for stocks that went up, and \( y \) for stocks that went down.
- Step 2: Establish Equations - From the problem, we got: \( x + y = 100 \) and \( 3x = 8y + 14 \).
- Step 3: Solve One Equation for One Variable - Using \( x + y = 100 \): \( y = 100 - x \).
- Step 4: Substitute - Insert \( y = 100 - x \) into the second equation: \( 3x = 8(100 - x) + 14 \). Simplify: \( 3x = 800 - 8x + 14 \).
- Step 5: Combine Like Terms - \( 3x + 8x = 814 \). Hence, \( 11x = 814 \).
- Step 6: Solve for One Variable - \( x = \frac{814}{11} \). Therefore, \( x = 74 \).
- Step 7: Find the Other Variable - Substitute \( x = 74 \) back into \( y = 100 - x \). We get \( y = 26 \).
Other exercises in this chapter
Problem 37
Solve each of the following verbal problems algebraically. You may use either a one or a two-variable approach. A bag contains 36 marbles, some of which are red
View solution Problem 38
In Exercises \(29-62,\) solve the system of equations using any method you choose. $$\left\\{\begin{aligned} 3 y &=24-9 x \\ 3 x+y &=8 \end{aligned}\right.$$
View solution Problem 39
Use the graphical method to solve the given system of equations for \(x\) and \(y.\) $$\left\\{\begin{array}{l}y=4 \\ x=-1\end{array}\right.$$
View solution Problem 39
In Exercises \(29-62,\) solve the system of equations using any method you choose. $$\left\\{\begin{aligned} 5 x+2 y &=4 y+9 \\ y &=x-3 \end{aligned}\right.$$
View solution