Problem 38
Question
Solve each inequality. $$ \sqrt{c+5}+\sqrt{c+10} > 2 $$
Step-by-Step Solution
Verified Answer
The solution is \( c > -5 \).
1Step 1: Isolate Square Roots
First, rearrange the inequality to separate terms with square roots on one side. This is already done in our inequality, so we can focus on the analysis as it is: \( \sqrt{c+5} + \sqrt{c+10} > 2 \).
2Step 2: Determine Domain Constraints
For both \( \sqrt{c+5} \) and \( \sqrt{c+10} \) to be real, we need \( c+5 \geq 0 \) and \( c+10 \geq 0 \). This implies \( c \geq -5 \) and \( c \geq -10 \). Therefore, the relevant constraint is \( c \geq -5 \).
3Step 3: Consider Critical Points
Let's consider when both square root terms could add up to just 2. If we hypothesize \( \sqrt{c+5} = 1 \) and \( \sqrt{c+10} = 1 \), this leads to solving \( c+5 = 1 \) and \( c+10 = 1 \). Solving them yields contradictions with the domain, so we focus instead on examining test intervals.
4Step 4: Test Critical Values in Relation to Domain
To check when \( \sqrt{c+5} + \sqrt{c+10} \) exceeds 2, consider test points such as \( c = 0, 1, 2,...\) for simplicity and intuition within the domain. For instance, \( c = 0 \) gives \( \sqrt{5} + \sqrt{10} > 2 \). Since \( \sqrt{5} \approx 2.24 \) and \( \sqrt{10} \approx 3.16 \), this sum exceeds 2.
5Step 5: Confirm General Trend
The inequality \( \sqrt{c+5} + \sqrt{c+10} > 2 \) persists for \( c \geq -5 \), as the value of each square root function increases with \( c \), and thus their sum is always greater than 2 for non-negative 'c' values. Therefore, every \( c \geq -5 \) satisfies the inequality.
Key Concepts
Square RootsReal NumbersTest IntervalsDomain Constraints
Square Roots
Square roots are mathematical functions that find the number, which when multiplied by itself, gives the original number. For example, the square root of 4 is 2 because \( 2 \times 2 = 4 \). Square roots can be tricky when dealing with inequalities, but the rules are straightforward:
- Square roots of non-negative numbers are always real.
- Negative numbers do not have real square roots. Instead, they have imaginary counterparts.
Real Numbers
Real numbers include all numbers on the number line, encompassing both rational and irrational numbers. They are essential for solving inequalities involving square roots since the solutions must be real to make sense in a mathematical and real-world context.
- Real numbers can be positive, negative, or zero.
- They encompass integers, fractions, and non-repeating decimals.
Test Intervals
Test intervals are a method used to solve inequalities by breaking down possible solutions into manageable segments. You test values within each interval to see if they satisfy the inequality.
- Choose points within the domain that make calculations simple.
- Checking consecutive values can reveal a pattern or confirm the inequality is satisfied.
Domain Constraints
Domain constraints are the permissible values for a variable that keep expressions within an inequality defined and real.
- They derive from conditions such as non-negativity under square roots or denominator restrictions in fractions.
- Determining domain constraints is crucial as it defines the scope within which the problem can be solved.
Other exercises in this chapter
Problem 37
For Exercises \(36-38,\) use the following information. Damaso asked Emilia to choose a number between 1 and \(35 .\) He told her to subtract 12 from that numbe
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Simplify each expression. $$ \left(a^{-\frac{2}{3}}\right)^{-\frac{1}{6}} $$
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Simplify. \(\sqrt{12}+\sqrt{48}-\sqrt{27}\)
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