Problem 38
Question
Solve by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets. \(\left\\{\begin{array}{l}{4 x-2 y=2} \\ {2 x-y=1}\end{array}\right.\)
Step-by-Step Solution
Verified Answer
The given system of equations represents the same line and thus has infinitely many solutions. The solution set, in set notation, is: \(\left\{ (x, 2x-1) \, | \, x \in \mathbb{R} \right\}\)
1Step 1: Check if the Equations are Equivalent
Examine the given two equations \(4x - 2y = 2\) and \(2x - y = 1\). We can see that the second equation is exactly the half of the first equation, which implies the two equations represent the same line and thus have infinitely many solutions.
2Step 2: Express the Solution in Set Notation
The set of all points on the line defined by either of the equations is the solution. The line is \(2x - y = 1\) or \(y = 2x - 1\). Therefore, the set of solutions is the set of all points \((x, y)\) on this line. The solution can be expressed in set notation as: \(\left\{ (x, 2x-1) \, | \, x \in \mathbb{R} \right\}\), where \(\mathbb{R}\) represents the set of all real numbers.
Key Concepts
Infinitely Many SolutionsSet NotationEquivalent EquationsLinear Equations
Infinitely Many Solutions
In a system of equations, sometimes both equations describe the same line. When this happens, the system is said to have infinitely many solutions. This means that any point on the line is a solution to both equations. For the system in the exercise,
- The first equation is \(4x - 2y = 2\).
- The second equation is \(2x - y = 1\).
Set Notation
Set notation is a way of describing a collection of objects, known as a set. In mathematics, set notation is often used to express the solution set of an equation or system of equations.
For the given system, the solution is the set of all points \((x, y)\) that satisfy the equation \(y = 2x - 1\). This is written as:
\[ \{ (x, 2x-1) \, | \, x \in \mathbb{R} \} \]This notation tells us:
For the given system, the solution is the set of all points \((x, y)\) that satisfy the equation \(y = 2x - 1\). This is written as:
\[ \{ (x, 2x-1) \, | \, x \in \mathbb{R} \} \]This notation tells us:
- The set consists of all pairs \((x, y)\),
- Each \(y\) is calculated as \(2x - 1\),
- \(x\) can be any real number \(\mathbb{R}\).
Equivalent Equations
Equations are considered equivalent if they have the same solutions. In the context of a system of linear equations, if scaling or manipulating one equation results in the other, then they are equivalent.
In our exercise:
In our exercise:
- Original equations are \(4x - 2y = 2\) and \(2x - y = 1\).
- By scaling the second equation by a factor of two, it matches the first one.
Linear Equations
A linear equation in two variables, such as \(ax + by = c\), represents a straight line when plotted on a coordinate plane. Each point on this line is a solution to the equation.
The given equations are:
This overlap is what gives the system infinitely many solutions, as explained above.
The given equations are:
- \(4x - 2y = 2\)
- \(2x - y = 1\)
This overlap is what gives the system infinitely many solutions, as explained above.
Other exercises in this chapter
Problem 37
write the partial fraction decomposition of each rational expression. $$\frac{x^{3}+x^{2}+2}{\left(x^{2}+2\right)^{2}}$$
View solution Problem 38
Solve: \(\sqrt{2 x-5}-\sqrt{x-3}=1 .\) (Section \(1.6,\) Example 4 )
View solution Problem 38
Solve each system by the method of your choice. $$ \left\\{\begin{array}{l} {x^{2}-y^{2}-4 x+6 y-4=0} \\ {x^{2}+y^{2}-4 x-6 y+12=0} \end{array}\right. $$
View solution Problem 38
Graph the solution set of each system of inequalities or indicate that the system has no solution. $$-2
View solution