Problem 38
Question
Solve by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets. \(\left\\{\begin{array}{l}4 x-2 y-2 \\ 2 x-y-1\end{array}\right.\)
Step-by-Step Solution
Verified Answer
The system of equations has infinitely many solutions, represented in set notation as \[ \{ (x, y) \, | \, y = 2x-1, x \in R \}\]
1Step 1: Identify the given equations
The given system of linear equations is \[\left\{\begin{array}{l}4 x-2 y-2=0 \\ 2 x-y-1=0\end{array}\right.\] It can be noticed that equation (2) is exactly half of equation (1). So, these are not independent equations, but rather the same equation written in different forms.
2Step 2: Identify the type of solution
Since these are identical equations, they'll intersect at infinitely many points, i.e., they represent the same line. Therefore, the system of equations has infinitely many solutions.
3Step 3: Express the solution in set notation
The solution can be presented in set notation by converting one equation to y = f(x) form, i.e., \[y = 2x - 1\] So the solution set is \[ \{ (x, y) \, | \, y = 2x-1, x \in R \}\] where R denotes the set of all real numbers.
Key Concepts
Method of Solution for Linear SystemsNo Solution and Infinitely Many SolutionsSet Notation in Algebra
Method of Solution for Linear Systems
When dealing with systems of linear equations, there are several methods to find the solution, i.e., the set of values that satisfy all equations simultaneously. The most common methods include:
The exercise provided is an example where the elimination method might be the most straightforward since the second equation is a multiple of the first. This indicates that we are dealing with dependent equations, which leads to special cases in the solution set.
- Graphing: Plotting each equation on a graph to find the point(s) of intersection.
- Substitution: Solving one of the equations for one variable and then substituting the result into the other equation.
- Elimination (or Addition): Adding or subtracting the equations to eliminate one variable, making it easier to solve for the remaining one.
- Matrix method (Row Reduction or Gaussian Elimination): Transforming the system into a matrix and performing operations to solve for the variables.
The exercise provided is an example where the elimination method might be the most straightforward since the second equation is a multiple of the first. This indicates that we are dealing with dependent equations, which leads to special cases in the solution set.
No Solution and Infinitely Many Solutions
In algebra, systems of linear equations can have one of three possible types of solutions: a single solution, no solution, or infinitely many solutions. How do we distinguish between them?
In the given exercise, the conclusion that the system has infinitely many solutions comes from recognizing that both equations are proportional (the second is half of the first), indicating they are the same line. When asked for this type of solution in set notation, we must first rearrange the equation into a function of one variable and then describe all the points on the line. This involves indicating that one variable is free to take any value within a certain set, usually the set of all real numbers.
Unique Solution
If the graphs of the equations intersect at exactly one point, the system has a unique solution, representing that specific point of intersection.No Solution
If the graphs are parallel and never intersect, there will be no set of values that satisfy both equations simultaneously, indicating no solution.Infinitely Many Solutions
The case of infinitely many solutions occurs when the equations represent the same line. Any point on this line is a solution to the system, hence there are infinitely many solutions.In the given exercise, the conclusion that the system has infinitely many solutions comes from recognizing that both equations are proportional (the second is half of the first), indicating they are the same line. When asked for this type of solution in set notation, we must first rearrange the equation into a function of one variable and then describe all the points on the line. This involves indicating that one variable is free to take any value within a certain set, usually the set of all real numbers.
Set Notation in Algebra
Set notation is a standardized mathematical language used to describe collections of elements. In the context of algebra, we use set notation to specify the solution sets of equations or systems of equations.
When we express a solution set in algebra, we typically use braces \( \{ \} \) to collect all the solution elements which satisfy the given conditions. For example, if a solution to a single variable equation is any real number that's greater than 2, we would write this as \( \{ x \in \mathbb{R} \, | \, x > 2 \} \), where \( \in \) denotes 'element of', \( \mathbb{R} \) represents the set of real numbers, and the vertical bar \( | \) means 'such that'.
In the step-by-step solution provided, the set notation \( \{ (x, y) \, | \, y = 2x-1, x \in \mathbb{R} \} \) reads as 'the set of all pairs of real numbers \( (x, y) \) such that \( y \) equals \( 2x-1 \)’. This perfectly expresses the infinitely many solutions condition as it includes all xy-pairs lying on the line defined by the equation y = 2x - 1.
When we express a solution set in algebra, we typically use braces \( \{ \} \) to collect all the solution elements which satisfy the given conditions. For example, if a solution to a single variable equation is any real number that's greater than 2, we would write this as \( \{ x \in \mathbb{R} \, | \, x > 2 \} \), where \( \in \) denotes 'element of', \( \mathbb{R} \) represents the set of real numbers, and the vertical bar \( | \) means 'such that'.
In the step-by-step solution provided, the set notation \( \{ (x, y) \, | \, y = 2x-1, x \in \mathbb{R} \} \) reads as 'the set of all pairs of real numbers \( (x, y) \) such that \( y \) equals \( 2x-1 \)’. This perfectly expresses the infinitely many solutions condition as it includes all xy-pairs lying on the line defined by the equation y = 2x - 1.
Other exercises in this chapter
Problem 38
In Exercises 27–62, graph the solution set of each system of inequalities or indicate that the system has no solution. $$-2
View solution Problem 38
Solve each system by the method of your choice. $$\left\\{\begin{array}{l} x^{2}-y^{2}-4 x+6 y-4=0 \\ x^{2}+y^{2}-4 x-6 y+12=0 \end{array}\right.$$
View solution Problem 39
Exercises 37-39 will help you prepare for the material covered in the first section of the next chapter. Consider the following array of numbers: $$\left[\begin
View solution Problem 39
Write the partial fraction decomposition of each rational expression. $$\frac{x^{3}-4 x^{2}+9 x-5}{\left(x^{2}-2 x+3\right)^{2}}$$
View solution