Problem 38
Question
Sketch the graph of \(f\). $$ f(x)=\frac{1}{3} \log _{3} x $$
Step-by-Step Solution
Verified Answer
The graph of \(f(x)=\frac{1}{3} \log_3 x\) is a slowly increasing curve starting from (1,0), passing through (3,1/3), and moving towards (9,2/3).
1Step 1: Identify the Function Type
The function given is a logarithmic function of the form \(f(x) = a \log_{b} x\). In this case, \(a = \frac{1}{3}\) and \(b = 3\). The base of the logarithm is \(3\).
2Step 2: Determine the Domain
The domain of the function \(f(x) = \frac{1}{3} \log_{3} x\) is \(x > 0\), since logarithms are only defined for positive values of \(x\).
3Step 3: Find the Y-Intercept
To find the y-intercept, set \(x = 1\).\[ f(1) = \frac{1}{3} \log_{3}(1)\]Since \(\log_{3}(1) = 0\), the y-intercept is \(f(1) = 0\). The point is \((1,0)\).
4Step 4: Find Characteristic Points
Pick a few characteristic points for better understanding of the graph.- **For \(x = 3\):**\[ f(3) = \frac{1}{3} \log_{3}(3) = \frac{1}{3} \times 1 = \frac{1}{3}\]- **For \(x = 9\):**\[ f(9) = \frac{1}{3} \log_{3}(9) = \frac{1}{3} \times 2 = \frac{2}{3}\]This gives us points \((3, \frac{1}{3})\) and \((9, \frac{2}{3})\).
5Step 5: Sketch the Graph
Start plotting the graph with previously determined points \((1,0)\), \((3, \frac{1}{3})\), and \((9, \frac{2}{3})\). The graph will pass through these points and approach the y-axis asymptotically, without touching or crossing it. Since the leading coefficient \(\frac{1}{3}\) is positive, the graph rises slowly as \(x\) increases.
Key Concepts
Domain of a FunctionCharacteristic PointsY-InterceptAsymptote
Domain of a Function
The domain of a function refers to all the possible input values (usually represented as "x") that the function can accept. For the logarithmic function given, \(f(x) = \frac{1}{3} \log_{3} x\), the domain is defined as \(x > 0\).
This is because a logarithmic function is only defined for positive values of \(x\).
This is because a logarithmic function is only defined for positive values of \(x\).
- Logarithms are not defined for zero or negative numbers.
- That's why the domain excludes non-positive values and begins from just above zero to infinity.
Characteristic Points
Characteristic points on a graph are specific points which help us understand the shape and trajectory. For the function given, identifying such points can be key to outlining the curve of the graph.
- Start with easy values like the base of the logarithm itself to find coordinates. For instance:
- When \(x = 3\): \(f(3) = \frac{1}{3} \log_{3}(3) = \frac{1}{3}\) gives us the point \((3, \frac{1}{3})\).
- When \(x = 9\): \(f(9) = \frac{1}{3} \log_{3}(9) = \frac{2}{3}\) gives us the point \((9, \frac{2}{3})\).
- These points help create a more precise graph and allow us to see how the function behaves for increasing x-values.
Y-Intercept
The y-intercept is where the graph crosses the y-axis. For any function, you find this by setting \(x = 1\) because any number to the power of zero is 1, simplifying any logarithmic function in the form \(f(x) = a \log_b x\).
- In our example, we calculate: \[ f(1) = \frac{1}{3} \log_{3}(1) = \frac{1}{3} \times 0 = 0 \]
- This gives us the y-intercept point \((1,0)\).
Asymptote
An asymptote is a line that a graph approaches but never actually touches or intersects. In the case of logarithmic functions like \(f(x) = \frac{1}{3} \log_{3} x\), there's a vertical asymptote at \(x = 0\).
- The graph continues to approach the y-axis as x gets closer to zero, but it never actually reaches the axis.
- Asymptotes are crucial for understanding the boundaries and limits of the function's behavior.
Other exercises in this chapter
Problem 37
Exer. 37-42: Sketch the graph of \(f\). $$ f(x)=\log (x+10) $$
View solution Problem 37
Exer. 25-42: Find the inverse function of \(f\). $$ f(x)=\sqrt[3]{x}+1 $$
View solution Problem 38
Exer. 35-38: Use common logarithms to solve for \(x\) in terms of \(y\). $$ y=\frac{10^{x}+10^{-x}}{10^{x}-10^{-x}} $$
View solution Problem 38
Exer. 37-42: Sketch the graph of \(f\). $$ f(x)=\log (x+100) $$
View solution