Problem 38
Question
Replace the polar equations in Exercises \(23-48\) by equivalent Cartesian equations. Then describe or identify the graph. $$ r \sin \theta=\ln r+\ln \cos \theta $$
Step-by-Step Solution
Verified Answer
The polar equation converts to the Cartesian equation \( y = \ln x \), representing a logarithmic function graph for \( x > 0 \).
1Step 1: Convert Polar Equations to Cartesian Coordinates
To convert a polar equation to Cartesian form, recall that the relationships between polar and Cartesian coordinates are: - For polar coordinates \( (r, \theta) \), the corresponding Cartesian coordinates are \( (x, y) \) where \( x = r \cos \theta \) and \( y = r \sin \theta \).- The polar radius \( r \) can be found as \( r = \sqrt{x^2 + y^2} \), and \( \theta \) as \( \theta = \tan^{-1}\left(\frac{y}{x}\right) \).With this information, consider the polar equation: \[ r \sin \theta = \ln r + \ln \cos \theta \]
2Step 2: Substitute Polar Terms into Cartesian Terms
Express each term in the equation using Cartesian coordinates:- Replace \( r \sin \theta \) with \( y \).- Recognize \( \ln r + \ln \cos \theta = \ln(r \cos \theta) \) using the property of logarithms \( \ln a + \ln b = \ln(ab) \).- Substitute \( r \cos \theta \) with \( x \) (since \( x = r \cos \theta \)).This gives us:\[ y = \ln x \]
3Step 3: Identify the Graph
The Cartesian equation \( y = \ln x \) corresponds to a natural logarithm function.- The graph of \( y = \ln x \) is defined for \( x > 0 \).- It forms a curve passing through the point \( (1, 0) \), increases slowly, and approaches negative infinity as \( x \) approaches zero from the positive side.This is the curve of a logarithmic function.
Key Concepts
Cartesian CoordinatesPolar EquationsNatural Logarithm FunctionGraph Identification
Cartesian Coordinates
Cartesian coordinates help us describe the position of a point in a plane using a pair of numerical values, representing distances from fixed reference lines. Here are the key things you need to know about them:
- The Cartesian coordinate system consists of two axes: the x-axis (horizontal) and the y-axis (vertical).
- Each point in the plane is represented with a pair of coordinates \((x, y)\), where \(x\) is the horizontal distance from the origin, and \(y\) is the vertical distance.
- Unlike polar coordinates, which use a radius and an angle, Cartesian coordinates make it easy to plot points and functions directly on graphs.
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
Polar Equations
Polar equations represent relationships using polar coordinates, where each point is identified by a radius and an angle. Here's how they work:
- Polar coordinates \((r, \theta)\) consist of the distance \(r\) from the origin and the angle \(\theta\).The angle is measured from the positive x-axis in a counter-clockwise direction.
- Polar equations can describe curves that are not easily represented in Cartesian coordinates, like spirals and circles.
- To solve a polar equation in Cartesian form, transform it using the relationships \(x = r \cos \theta\) and \(y = r \sin \theta\), then simplify.
Natural Logarithm Function
The natural logarithm function, denoted as \(\ln x\), is a special logarithmic function with the base of Euler's number \(e\) (approximately 2.718). Here are its important characteristics:
- \(\ln x\) is defined only for positive values of \(x\).
- It signifies the power to which the base \(e\) must be raised to obtain the number \(x\).
- The natural logarithm grows logarithmically, increasing at a slower rate as \(x\) becomes larger.
- It's useful in solving equations involving exponential growth or decay and frequently appears in continuous compounding problems.
Graph Identification
Identifying a graph involves recognizing the visual representation of equations or functions in a coordinate system. Here's how you can understand it better:
- The graph of a function gives a visual way to see all solutions of the equation.
- For \(y = \ln x\), the graph is a natural logarithmic curve which is steep near \(x = 0\) and flattens as \(x\) increases.
- It’s defined only for \(x > 0\), and approaches negative infinity as \(x\) goes to zero but stays positive.
- This curve emerges prominently in the first quadrant of a Cartesian plane.
Other exercises in this chapter
Problem 38
Find the centroid of the semicircular region \(0 \leq r \leq a\) \(0 \leq \theta \leq \pi .\)
View solution Problem 38
Exercises \(35-38\) give information about the foci, vertices, and asymptotes of hyperbolas centered at the origin of the \(x y\) -plane. In each case, find the
View solution Problem 38
Exercises \(35-38\) give foci and corresponding directrices of hyperbolas centered at the origin of the \(x y\) -plane. In each case, find the hyperbola's eccen
View solution Problem 38
Find the points of intersection of the pairs of curves in Exercises \(31-38\) . $$ r^{2}=\sqrt{2} \cos 2 \theta, \quad r^{2}=\sqrt{2} \sin 2 \theta $$
View solution