Problem 38
Question
Now let's move on to factorizations that may require two or more techniques. Factor completely, or state that the polynomial is prime. Check factorizations using multiplication or a graphing utility. $$y^{2}-18 y-81$$
Step-by-Step Solution
Verified Answer
The factorized form of the given quadratic equation \(y^{2}-18y-81\) is \((y - 9)(y + 9)\).
1Step 1: Identify the coefficients
In the given quadratic equation \(y^{2}-18y-81\), the coefficient of \(y^{2}\) (a) is 1, the coefficient of y (b) is -18, and the constant term (c) is -81.
2Step 2: Find the factors
We need to find two numbers that multiply to -81 and add up to -18. The numbers are -9 and 9, because (-9) * 9 equals -81 and (-9) + 9 equals 0.
3Step 3: Write the factorized equation
Replace the coefficients in the form \((variable - factor1)(variable - factor2)\). In this case, the factorized quadratic equation would be \((y - 9)(y + 9)\).
4Step 4: Check the factors
Multiply the factors back together to verify the original equation. (\(y - 9) * (y + 9)\) simplifies back to \(y^{2}- 18y - 81\), proving the factorization to be correct.
Key Concepts
Quadratic Equation SolvingIdentifying CoefficientsFinding Factors of PolynomialsVerification of Factorization
Quadratic Equation Solving
Understanding how to solve quadratic equations is fundamental in algebra. A quadratic equation typically has the form \( ax^2 + bx + c = 0 \) where \( a \) is the coefficient of the squared term, \( b \) is the linear term's coefficient, and \( c \) is the constant term.
To solve, we often search for two numbers that satisfy specific conditions related to the coefficients in the equation. These conditions usually involve the numbers adding to equal \( b \) and multiplying to be \( ac \) (if the leading coefficient \( a \) is not 1). With these numbers, we can factor the equation or apply the quadratic formula \(-\frac{b \pm \sqrt{b^2-4ac}}{2a}\) for finding the solutions. Factorization is preferable when it's possible because it often simplifies the process.
To solve, we often search for two numbers that satisfy specific conditions related to the coefficients in the equation. These conditions usually involve the numbers adding to equal \( b \) and multiplying to be \( ac \) (if the leading coefficient \( a \) is not 1). With these numbers, we can factor the equation or apply the quadratic formula \(-\frac{b \pm \sqrt{b^2-4ac}}{2a}\) for finding the solutions. Factorization is preferable when it's possible because it often simplifies the process.
Identifying Coefficients
To work with quadratic equations effectively, first, we must identify the coefficients correctly. Coefficients are the numerical or constant parts of the terms in a polynomial. In the quadratic term \( ax^2 \) the coefficient is \( a \) and it is integral in determining the shape of the graph. For the linear term \( bx \) in the equation, \( b \) affects the slope, and the constant term \( c \) is where the graph intersects the y-axis when \( x = 0 \).
When we know these coefficients, we can easily plot the graph of the quadratic, use them to factor the equation or find the vertex of the parabola. Clear identification is crucial to avoid mistakes in subsequent calculations.
When we know these coefficients, we can easily plot the graph of the quadratic, use them to factor the equation or find the vertex of the parabola. Clear identification is crucial to avoid mistakes in subsequent calculations.
Finding Factors of Polynomials
Factoring polynomials requires finding an expression that consists of two or more simpler expressions multiplied together to produce the original polynomial. For a quadratic, we often look for two binomial factors that can be valid when multiplied together.
Factorization Techniques:
- Guess and Check: Using knowledge of numbers, we guess pairs that multiply to the constant term and add to the coefficient of \( x \).
- Factoring by grouping: In some cases, we can group terms and factor common elements out to find pairs of binomials.
- Using formulae: Some quadratics can be factored by applying special product formulae such as the difference of squares or perfect square trinomials.
Verification of Factorization
After factoring a polynomial, it's essential to verify that we've done it correctly. We do this by multiplying the factors back together to check if we get the original polynomial.
If we correctly factor \( y^2 - 18y - 81 \) into \( (y - 9)(y + 9) \), re-multiplying the factors should yield the original expression. If we don't, we might need to revisit the factorization process and correct any mistakes. Verification builds our confidence that factorization is accurate, ensuring our understanding and work's integrity. Moreover, it's a step towards ensuring that any subsequent work based on that factorization is also correct.
If we correctly factor \( y^2 - 18y - 81 \) into \( (y - 9)(y + 9) \), re-multiplying the factors should yield the original expression. If we don't, we might need to revisit the factorization process and correct any mistakes. Verification builds our confidence that factorization is accurate, ensuring our understanding and work's integrity. Moreover, it's a step towards ensuring that any subsequent work based on that factorization is also correct.
Other exercises in this chapter
Problem 37
Factor each polynomial using the greatest common factor. If there is no common factor other than 1 and the polynomial cannot be factored, so state. $$100 y^{5}-
View solution Problem 37
Use the method of your choice to factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$8 x^{2}-2 x-
View solution Problem 38
Factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. \(x^{2}-9 x y+14 y^{2}\)
View solution Problem 38
Use factoring to solve each quadratic equation. Check by substitution or by using a graphing utility and identifying \(x\) -intercepts. $$x^{2}-25=0$$
View solution