Problem 38
Question
Multiply the algebraic expressions using the FOIL method, and simplify. \((y-1)(y+5)\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(y^2 + 4y - 5\).
1Step 1: Apply FOIL Method
FOIL stands for First, Outer, Inner, Last. We'll use this method to expand the expression. First, multiply the first terms:\(y imes y = y^2\).
2Step 2: Multiply Outer Terms
Now, multiply the outer terms:\(y imes 5 = 5y\).
3Step 3: Multiply Inner Terms
Next, multiply the inner terms:\(-1 imes y = -y\).
4Step 4: Multiply Last Terms
Finally, multiply the last terms:\(-1 imes 5 = -5\).
5Step 5: Combine the Terms
Now combine all the terms from the previous steps:\(y^2 + 5y - y - 5\).
6Step 6: Simplify the Expression
Combine like terms to simplify the expression:\(y^2 + (5y - y) - 5 = y^2 + 4y - 5\).
Key Concepts
Algebraic ExpressionsMultiplication of ExpressionsSimplifying Expressions
Algebraic Expressions
Algebraic expressions are combinations of variables, constants, and arithmetic operations. They are foundational in algebra and crucial for understanding and mastering various mathematical concepts. In the expression \((y-1)(y+5)\), each part of the expression is linked by multiplication, with 'y' being the variable go-between in both terms. Here’s why each component matters:
- Variables act as placeholders for numbers and can represent different values. In our example, 'y' is the variable.
- Constants are fixed values. In the terms \(-1\) and \(5\), these numbers are constants.
- Operations are used to combine these constants and variables. Typically, you're adding, subtracting, multiplying, and dividing.
Multiplication of Expressions
Multiplying algebraic expressions is a method used to find the product of two or more expressions. This is where the FOIL method shines. FOIL, standing for First, Outer, Inner, Last, helps simplify multiplication of two binomials, as seen in \((y-1)(y+5)\). Here's how it works:
- **First Terms:** Multiply the first terms from each binomial: \(y \times y = y^2\). This gives you the leading term of the new expression.
- **Outer Terms:** Next, multiply the outer terms, treating the expressions as ends: \(y \times 5 = 5y\). This begins forming the middle terms.
- **Inner Terms:** Then, multiply the inner terms which are closer to each other: \(-1 \times y = -y\). This adds further to those middle terms.
- **Last Terms:** Lastly, multiply last terms: \(-1 \times 5 = -5\). This concludes the formation of your expression.
Simplifying Expressions
Simplifying expressions involves combining like terms in a polynomial to present it in its simplest form. Once you've expanded an expression, like we did with the FOIL method, the next step is to simplify it. The aim is to make it more manageable and easier to understand. Take your expanded expression \(y^2 + 5y - y - 5\):
- **Identify Like Terms:** In this case, \(5y\) and \(-y\) are like terms because they contain the same variable 'y'.
- **Combine Like Terms:** Add or subtract like terms. For our expression, combine \(5y - y = 4y\).
- **Rewrite the Expression:** After combining, your expression simplifies to \(y^2 + 4y - 5\).
Other exercises in this chapter
Problem 38
\(33-38\) . Express the interval in terms of inequalities, and then graph the interval. $$ (-\infty, 1) $$
View solution Problem 38
\(29-38=\) Simplify the expression. Assume that the letters denote any real numbers. $$ \sqrt[4]{x^{4} y^{2} z^{2}} $$
View solution Problem 38
Perform the indicated operations. \(\frac{\frac{1}{12}}{\frac{1}{8}-\frac{1}{9}}\)
View solution Problem 39
Perform the multiplication or division and simplify. $$ \frac{2 x^{2}+3 x+1}{x^{2}+2 x-15}+\frac{x^{2}+6 x+5}{2 x^{2}-7 x+3} $$
View solution