Problem 38
Question
\(\lim _{x \rightarrow 0}\left(\tan \left(\frac{\pi}{4}+x\right)\right)^{1 / x}\) is equal to: \(\quad\) [Sep. \(\mathbf{0 2}, \mathbf{2 0 2 0}\) (II)] (a) \(e\) (b) 2 (c) 1 (d) \(e^{2}\)
Step-by-Step Solution
Verified Answer
The limit is \( e^2 \), so the answer is (d).
1Step 1: Understanding the Problem
We need to find \( \lim _{x \rightarrow 0}\left(\tan \left(\frac{\pi}{4}+x\right)\right)^{1 / x} \). This is a limit problem involving an exponential limit type, which generally points towards the use of the limit definition of the exponential function or logarithms.
2Step 2: Simplifying the Expression
Notice that when \( x = 0 \), \( \tan \left(\frac{\pi}{4} + x\right) = \tan \left(\frac{\pi}{4}\right) = 1 \). However, since \( \lim _{x \rightarrow 0} 1^{1/x} \) can be potentially indeterminate, we need another approach.
3Step 3: Logarithmic Transformation
Take the natural log of the expression to simplify: \[ \ln\left( \left(\tan\left(\frac{\pi}{4} + x\right)\right)^{1/x} \right) = \frac{\ln\left( \tan\left(\frac{\pi}{4} + x\right)\right)}{x}. \] This is the form \( \frac{0}{0} \) as \( x \to 0 \), a classic case for applying L'Hôpital's Rule.
4Step 4: Applying L'Hôpital's Rule
Using L'Hôpital's Rule, differentiate the numerator and denominator: - Derivative of numerator \( \ln\left( \tan\left(\frac{\pi}{4} + x\right)\right)\) is \( \frac{1}{\tan\left(\frac{\pi}{4} + x\right)} \cdot \sec^2\left(\frac{\pi}{4} + x\right) \). - Derivative of denominator \( x \) is \( 1 \).Then the limit becomes \[ \lim_{x \to 0} \frac{\sec^2\left(\frac{\pi}{4} + x\right)}{\tan\left(\frac{\pi}{4} + x\right)}. \]
5Step 5: Evaluating at the Limit
As \( x \to 0 \), \( \tan\left(\frac{\pi}{4} + x\right) \to 1 \) and \( \sec^2\left(\frac{\pi}{4} + x\right) \to 2 \). Thus, the limit simplifies to: \[ \lim_{x \to 0} \frac{2}{1} = 2. \] This means the original natural logarithm limit is \( 2 \).
6Step 6: Converting Back from Logarithmic Form
Since we initially transformed the expression using a logarithm, we have \( \ln(L) = 2 \) where \( L \) is the original limit. Therefore, exponentiate to find \( L = e^2 \).
Key Concepts
L'Hôpital's RuleExponential LimitsTrigonometric Limits
L'Hôpital's Rule
L'Hôpital's Rule is a powerful tool in calculus for evaluating limits that yield an indeterminate form. Usually, these forms are either \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). When you encounter such forms, L'Hôpital's Rule allows you to differentiate the numerator and the denominator separately and then find the limit again. Thus,
- If \( \lim_{x \to c} \frac{f(x)}{g(x)} = \frac{0}{0} \), then \( \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)} \), provided the right-hand side limit exists.
- This rule is very useful when faced with complex functions that are hard to simplify directly.
Exponential Limits
Exponential limits involve expressions that grow exponentially or decay exponentially. They often appear in the format of raised powers involving variables, such as \( x^{1/x} \) or \( (some extstyle{ }function)^{1/x} \). To evaluate limits of this type, one common technique is to use logarithms to simplify the expression:
- Take the natural logarithm of the entire expression, simplifying its complexity.
- Transform the exponent into a product, which simplifies differentiation.
Trigonometric Limits
Trigonometric limits often involve functions like sine, cosine, or tangent. These functions can behave unpredictably around certain points, especially near zero or singularities. When tackled within limit problems:
- The key is to remember the fundamental properties and identities, such as \( \tan(x) = \frac{\sin(x)}{\cos(x)} \) and small-angle approximations like \( \sin(x) \approx x \) for small \( x \).
- Considering transformations, like \( \tan(\frac{\pi}{4} + x) \) in our exercise, which is affected by the changes made to angular values, helps predict behavior as \( x \to 0 \).
Other exercises in this chapter
Problem 36
\(\lim _{x \rightarrow a} \frac{(a+2 x)^{\frac{1}{3}}-(3 x)^{\frac{1}{3}}}{(3 a+x)^{\frac{1}{3}}-(4 x)^{\frac{1}{3}}}(a \neq 0)\) is equal to : [Sep. 03, 2020 (
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If \(\lim _{x \rightarrow 1} \frac{x+x^{2}+x^{3}+\ldots+x^{n}-n}{x-1}=820,(n \in \mathbf{N})\) then the value of \(n\) is equal to
View solution Problem 39
\(\lim _{x \rightarrow 0}\left(\frac{3 x^{2}+2}{7 x^{2}+2}\right)^{1 / x^{2}}\) is equal to: \(\quad\) [Jan. 8, 2020 (I)] (a) \(\frac{1}{e}\) (b) \(\frac{1}{e^{
View solution Problem 40
\(\lim _{x \rightarrow 0} \int_{0}^{x} \frac{t \sin (10 t) d t}{x}\) is equal to: [Jan. \(8,2020(\mathrm{II})]\) (a) 0 (b) \(\frac{1}{10}\) (c) \(-\frac{1}{5}\)
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