Problem 38
Question
Let \(a, b, c\) be real numbers, \(a \neq 0 .\) If \(\alpha\) is a root of \(a^{2} x^{2}+b x+c=0, \beta\) is a root of \(a^{2} x^{2}-b x-c=0\) and \(0<\alpha<\beta\), then the equation \(a^{2} x^{2}+2 b x+2 c=0\) has a root \(\gamma\) that always satisfies (A) \(\gamma=\frac{\alpha+\beta}{2}\) (B) \(\gamma=\alpha+\frac{\beta}{2}\) (C) \(\gamma=\alpha\) (D) \(\alpha<\gamma<\beta\)
Step-by-Step Solution
Verified Answer
The root \(\gamma\) satisfies \(\alpha < \gamma < \beta\) (D).
1Step 1: Identify the given quadratic equations
We are given two quadratic equations: \(a^2x^2 + bx + c = 0\) with root \(\alpha\), and \(a^2x^2 - bx - c = 0\) with root \(\beta\). We need to find the relationship between these roots.
2Step 2: Use the relationship between coefficients and roots
For the first equation, by Vieta's formulas, we know: \(\alpha_1 + \alpha_2 = -\frac{b}{a^2}\) and \(\alpha_1 \alpha_2 = \frac{c}{a^2}\). Similarly, for the second equation, \(\beta_1 + \beta_2 = \frac{b}{a^2}\) and \(\beta_1 \beta_2 = \frac{-c}{a^2}\). Since we are given \(0 < \alpha < \beta\), the equations suggest some peculiarities about the nature of the roots.
3Step 3: Investigate the new equation
The new equation \(a^2x^2 + 2bx + 2c = 0\) transforms the previous systems. Using Vieta's formulas again, we find the sum of roots \( -\frac{2b}{a^2}\) and the product of roots \(\frac{2c}{a^2}\).
4Step 4: Determine the root behavior of the new equation
We want to look at how the roots \(\gamma\) fit into the arrangement. Since \(0 < \alpha < \beta\), and considering the shift in the coefficients, this introduces a central root \(\gamma\) that is likely positioned between \(\alpha\) and \(\beta\). This suggests that \(\gamma\) should fall into a position such that \(\alpha < \gamma < \beta\), similar to an average.
Key Concepts
Vieta's formulasRoots of Quadratic EquationsRelationship Between Roots and Coefficients
Vieta's formulas
Vieta's formulas are a powerful tool for understanding the relationships between the roots and coefficients of a polynomial equation.
These formulas make it easy to find the sum and product of the roots without solving the equation completely.
For a quadratic equation, specifically in the form of \(ax^2 + bx + c = 0 \), Vieta's formulas help us by providing these succinct relationships between the coefficients and the roots:
In our context, Vieta's formulas assist in discerning the characteristics of the roots \(\alpha\) and \(\beta\) of our initial quadratic equations.
They reveal how these roots relate directly to the coefficients, aiding in further exploration of their properties.
These formulas make it easy to find the sum and product of the roots without solving the equation completely.
For a quadratic equation, specifically in the form of \(ax^2 + bx + c = 0 \), Vieta's formulas help us by providing these succinct relationships between the coefficients and the roots:
- The sum of the roots: \( r_1 + r_2 = -\frac{b}{a} \)
- The product of the roots: \( r_1 \cdot r_2 = \frac{c}{a} \)
In our context, Vieta's formulas assist in discerning the characteristics of the roots \(\alpha\) and \(\beta\) of our initial quadratic equations.
They reveal how these roots relate directly to the coefficients, aiding in further exploration of their properties.
Roots of Quadratic Equations
The roots or solutions of a quadratic equation like \(ax^2 + bx + c = 0\) are values of \(x\) which make the equation true.
To find these roots, you typically use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula helps in understanding how changes in coefficients \(a\), \(b\), and \(c\) influence the solutions.
In simpler terms:
They explore how such adjustments manifest between real roots, aligning excellently with the introduction of an intermediate root \(\gamma\) within a new equation.
To find these roots, you typically use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula helps in understanding how changes in coefficients \(a\), \(b\), and \(c\) influence the solutions.
In simpler terms:
- "\(-b\)" acts as a shift, moving the roots along the number line.
- "\(b^2 - 4ac\)" or the discriminant, determines the nature of roots (real or imaginary).
- "4a" beneath the square root affects the breadth around the average, affecting spread.
They explore how such adjustments manifest between real roots, aligning excellently with the introduction of an intermediate root \(\gamma\) within a new equation.
Relationship Between Roots and Coefficients
Understanding the relationship between roots and coefficients allows us to predict and explore how roots will behave under different algebraic manipulations.
With a quadratic, the nature and position of the roots are deeply connected to its coefficients.
For example:
With a quadratic, the nature and position of the roots are deeply connected to its coefficients.
For example:
- Root positions are critically linked to the sign and value of \(b\).
Other exercises in this chapter
Problem 36
If \(a\) and \(b\) are odd integers then \([x]^{2}+a[x]+b=0\) (where [ \(\cdot\) ] denotes greatest integer function) has (A) finite number of roots (B) infinit
View solution Problem 37
If \(\log _{9}\left(x^{2}-5 x+6\right)>\log _{3}(x-4), x\) belongs to (A) \((-\infty, 4)\) (B) \((4, \infty)\) (C) \((-\infty,-4) \cup(4, \infty)\) (D) no real
View solution Problem 39
Number of solutions of the equation \(x^{2}-2-2[x]=0\) ([.] denotes greatest integer function) is (A) 1 (B) 2 (C) 3 (D) None of these
View solution Problem 40
The number of real roots of the equation \(2^{\sin ^{2} x}-2^{\cos ^{2} x}=\) 1 is (A) 2 (B) 1 (C) infinite (D) None of these
View solution