Problem 38
Question
In how many ways may \(n\) people sit around a round table? (Assume that when people are sitting around a round table, all that really matters is who is to each person's right. For example, if we can get one arrangement of people around the table from another by having everyone get up and move to the right one place and sit back down, we get an equivalent arrangement of people. Notice that you can get a list from a seating arrangement by marking a place at the table, and then listing the people at the table, starting at that place and moving around to the right.) There are at least two different ways of doing this problem. Try to find them both. (h)
Step-by-Step Solution
Verified Answer
(n-1)!
1Step 1: Fix One Person
Since the seats are arranged in a circle, we can fix one person in one seat to remove the effect of the circular permutation. Suppose we fix one person in a particular seat.
2Step 2: Arrange Remaining n-1 Persons
After fixing one person, we need to arrange the remaining \(n-1\) people. The number of ways to do this is \( (n-1)! \).
3Step 3: Generalize the Result
Hence, the number of ways to arrange \(n\) people around a round table is \( (n-1)! \)
Key Concepts
circular permutationsfactorialcombinatorics problem-solving strategies
circular permutations
When it comes to arranging people or objects in a circle, we deal with a special type of permutation known as circular permutations. Unlike linear permutations where the order matters from left to right, in circular permutations, what matters is the relative positioning of the items. Essentially, if you can rotate one arrangement to get another, those two arrangements are considered the same.
To simplify the problem of counting circular permutations, we can fix one person in place and then arrange the others around them. This way, we've effectively converted a circular permutation into a linear permutation of the remaining items.
To simplify the problem of counting circular permutations, we can fix one person in place and then arrange the others around them. This way, we've effectively converted a circular permutation into a linear permutation of the remaining items.
factorial
A factorial, represented by the symbol \, is a mathematical function that multiplies a number by all the positive integers less than itself. For example, \(5! = 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 120 \). Factorials are key in permutation and combination problems because they represent the number of ways to arrange a set of items.
In our problem, after fixing one person to break the circle, we are left with \(n-1\) people to arrange. The number of ways to arrange these \(n-1\) people is represented by \((n-1)!\). Thus, the formula for the number of ways \(n\) people can sit around a round table is \((n-1)!\).
Remember that the key to understanding factorials is recognizing they represent a sequence of multiplications that describe arrangements.
In our problem, after fixing one person to break the circle, we are left with \(n-1\) people to arrange. The number of ways to arrange these \(n-1\) people is represented by \((n-1)!\). Thus, the formula for the number of ways \(n\) people can sit around a round table is \((n-1)!\).
Remember that the key to understanding factorials is recognizing they represent a sequence of multiplications that describe arrangements.
combinatorics problem-solving strategies
Combinatorics, the branch of mathematics dealing with combinations and permutations, provides powerful strategies for solving problems involving arrangements. One common strategy is **fixing** an element to simplify circular permutations. By fixing one person, the problem converts from a circular to a linear permutation.
Another strategy is **breaking down complex problems** into smaller, manageable steps, just like the exercise does. First, we fix one person; then we consider the arrangement of the remaining \(n-1\) people.
Finally, always verify that different methods yield the same result. This reinforces your understanding and ensures accuracy. In this problem, both fixing one person and recognizing rotational symmetry should lead to the same result, \((n-1)!\).
Another strategy is **breaking down complex problems** into smaller, manageable steps, just like the exercise does. First, we fix one person; then we consider the arrangement of the remaining \(n-1\) people.
Finally, always verify that different methods yield the same result. This reinforces your understanding and ensures accuracy. In this problem, both fixing one person and recognizing rotational symmetry should lead to the same result, \((n-1)!\).
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