Problem 38
Question
In Exercises 37-42, find the exact values of \( \sin 2u \), \( \cos 2u \), and \( \tan 2u \) using the double-angle formulas. \( \cos u = - \dfrac{4}{5}, \dfrac{\pi}{2} < u < \pi \)
Step-by-Step Solution
Verified Answer
The exact values are \( \sin 2u = - \frac{24}{25} \), \( \cos 2u = \frac{7}{25} \), and \( \tan 2u = - \frac{24}{7} \)
1Step 1: Compute sin(u)
We already know that \( \cos u = - \frac{4}{5} \). To find \( \sin u \) we use the Pythagorean identity \( \sin^2 u + \cos^2 u = 1 \). So, \( \sin^2 u = 1 - \cos^2 u = 1 - (- \frac{4}{5})^2 = 1 - \frac{16}{25} = \frac{9}{25} \) As \( \sin \) is positive in the second quadrant, we get \( \sin u = \frac{3}{5} \)
2Step 2: Compute sin(2u)
Using the double-angle formula \( \sin 2u = 2 \sin u \cos u \), we substitute the values of \( \sin u \) and \( \cos u \) to find \( \sin 2u = 2 (\frac{3}{5})(- \frac{4}{5}) = - \frac{24}{25} \)
3Step 3: Compute cos(2u)
Using the double-angle formula \( \cos 2u = \cos^2 u - \sin^2 u \), we substitute the values of \( \sin u \) and \( \cos u \) to find \( \cos 2u = (- \frac{4}{5})^2 - (\frac{3}{5})^2 = \frac{16}{25} - \frac{9}{25} = \frac{7}{25} \)
4Step 4: Compute tan(2u)
We know that \( \tan u = \frac{\sin u}{\cos u} \). Therefore, \( \tan 2u = \frac{\sin 2u}{\cos 2u} = \frac{-\frac{24}{25}}{\frac{7}{25}} = - \frac{24}{7} \)
Key Concepts
Trigonometric IdentitiesUnit CircleQuadrants of Trigonometric Functions
Trigonometric Identities
Trigonometric identities are equations that involve trigonometric functions and are true for every value of the occurring variables where both sides of the equality are defined. One essential identity is the Pythagorean identity, given by \( \sin^2 u + \cos^2 u = 1 \). This identity helps to relate sine and cosine functions and can be used to derive other identities.
The double-angle identities are another critical set of trigonometric identities. These are especially useful when dealing with problems that involve twice an angle. The double-angle identities for sine, cosine, and tangent are:
The double-angle identities are another critical set of trigonometric identities. These are especially useful when dealing with problems that involve twice an angle. The double-angle identities for sine, cosine, and tangent are:
- \( \sin 2u = 2 \sin u \cos u \)
- \( \cos 2u = \cos^2 u - \sin^2 u \)
- \( \tan 2u = \frac{2 \tan u}{1 - \tan^2 u} \)
Unit Circle
The unit circle is a powerful tool in trigonometry, and it provides a visual way to understand trigonometric functions. It is a circle with a radius of one centered at the origin of a coordinate plane. Any angle \( u \) in standard position with its vertex at the origin can be represented on the unit circle by a point \((x,y)\). Here, \( x = \cos u \) and \( y = \sin u \).
Because the unit circle allows you to neatly see the values of sine and cosine at various angles, it becomes easier to understand how these values change as the angle changes. Each point on the unit circle can be mapped to an angle, and from these points, sine, cosine, and even tangent values can be derived. This conceptual map is useful when solving problems that involve angles not typically found in standard trigonometric tables.
For this particular problem, with \( \cos u = -\frac{4}{5} \) and knowing that \( \dfrac{\pi}{2} < u < \pi \) puts us in the second quadrant, the unit circle enables us to conclude that \( \sin u \) must be positive, as previously shown in the exercise solution.
Because the unit circle allows you to neatly see the values of sine and cosine at various angles, it becomes easier to understand how these values change as the angle changes. Each point on the unit circle can be mapped to an angle, and from these points, sine, cosine, and even tangent values can be derived. This conceptual map is useful when solving problems that involve angles not typically found in standard trigonometric tables.
For this particular problem, with \( \cos u = -\frac{4}{5} \) and knowing that \( \dfrac{\pi}{2} < u < \pi \) puts us in the second quadrant, the unit circle enables us to conclude that \( \sin u \) must be positive, as previously shown in the exercise solution.
Quadrants of Trigonometric Functions
In trigonometry, the coordinate plane is divided into four quadrants, each of which affects the sign of trigonometric functions based on the angle’s terminal side. Understanding these quadrants is crucial because it allows mathematicians to determine the sign of the values such as sine and cosine for specific angles.
The four quadrants are:
The four quadrants are:
- **Quadrant I**: Both sine and cosine are positive.
- **Quadrant II**: Sine is positive, and cosine is negative.
- **Quadrant III**: Both sine and cosine are negative.
- **Quadrant IV**: Sine is negative, and cosine is positive.
Other exercises in this chapter
Problem 37
In Exercises 9-50, verify the identity \( (1 + \sin y) [1 + \sin (-y)] = \cos^2 y \)
View solution Problem 37
In Exercises 37 - 58, use the fundamental identities to simplify the expression. There is more than one correct form of each answer. \( \cot \theta \sec \theta
View solution Problem 38
In Exercises 37 - 42, find the exact value of the expression. \( \cos \dfrac{\pi}{16} \cos \dfrac{3\pi}{16} - \sin \dfrac{\pi}{16} \sin \dfrac{3\pi}{16} \)
View solution Problem 38
In Exercises 25-38, find all solutions of the equation in the interval \( [0, 2\pi) \). \( \sin x - 2 = \cos x - 2 \)
View solution