Problem 38
Question
In Exercises \(35-42,\) find the multiplicative inverse of each number. $$\frac{1}{7}$$
Step-by-Step Solution
Verified Answer
The multiplicative inverse of \( \frac{1}{7} \) is \( 7 \).
1Step 1: Identify the given number
The given number is the fraction \( \frac{1}{7} \).
2Step 2: Find the multiplicative inverse of the given number
To find the multiplicative inverse of \( \frac{1}{7} \), reverse the numerator and denominator of \( \frac{1}{7} \) to get \( \frac{7}{1} \).
3Step 3: Simplify the resulting fraction
Simplify \( \frac{7}{1} = 7 \). Therefore, the multiplicative inverse of \( \frac{1}{7} \) is \( 7 \).
Key Concepts
Understanding FractionsAlgebra and Its BasicsInverse Operations Explained
Understanding Fractions
Fractions are a way to represent parts of a whole. They consist of two main components: the numerator and the denominator. The numerator is the top number, and it shows how many parts we have. The denominator is the bottom number, indicating the total number of equal parts the whole is divided into.
For example, in the fraction \(\frac{1}{7}\), "1" is the numerator, and "7" is the denominator. This fraction means we have 1 part of something divided into 7 equal parts.
Fractions can express quantities less than one (proper fractions), equal to one (such as \(\frac{7}{7}\)), or more than one (improper fractions like \(\frac{9}{7}\)). They're handy in both arithmetic and complex mathematical concepts like algebra.
For example, in the fraction \(\frac{1}{7}\), "1" is the numerator, and "7" is the denominator. This fraction means we have 1 part of something divided into 7 equal parts.
Fractions can express quantities less than one (proper fractions), equal to one (such as \(\frac{7}{7}\)), or more than one (improper fractions like \(\frac{9}{7}\)). They're handy in both arithmetic and complex mathematical concepts like algebra.
Algebra and Its Basics
Algebra is a branch of mathematics that uses symbols and letters to represent numbers and quantities in formulas and equations. It allows us to solve problems involving unknown values. By using variables, algebra helps us generalize mathematical operations and relationships.
An important aspect of algebra is understanding how different operations relate to each other. This includes knowing how to handle addition, subtraction, multiplication, and division with variables and constants.
An important aspect of algebra is understanding how different operations relate to each other. This includes knowing how to handle addition, subtraction, multiplication, and division with variables and constants.
- For example, in algebra, the expression \(x + 2 = 5\) helps us find the value of \(x\).
- Similarly, the concept of multiplicative inverses involves manipulating expressions to simplify equations or solve for unknowns.
Inverse Operations Explained
Inverse operations are operations that reverse the effect of each other. In the context of multiplication, finding an inverse means identifying a number which, when multiplied by the original number, yields 1.
To find the multiplicative inverse of a fraction, we simply flip the numerator and the denominator. For example, the multiplicative inverse of \(\frac{1}{7}\) is \(\frac{7}{1}\), or simply 7.
Finding inverses is crucial when solving equations. If you multiply a fraction by its inverse, you get 1, which is effectively like neutralizing the fraction in an equation.
To find the multiplicative inverse of a fraction, we simply flip the numerator and the denominator. For example, the multiplicative inverse of \(\frac{1}{7}\) is \(\frac{7}{1}\), or simply 7.
Finding inverses is crucial when solving equations. If you multiply a fraction by its inverse, you get 1, which is effectively like neutralizing the fraction in an equation.
- This concept is pivotal in algebra, particularly in equations where dividing by a fraction is needed.
- It's similar to how subtracting a number can be reversed by adding the same number, keeping equations balanced.
Other exercises in this chapter
Problem 37
Simplify each fraction by reducing it to its lowest terms. $$\frac{44}{50}$$
View solution Problem 38
Use the order of operations to simplify each expression. $$10^{2}-100 \div 5^{2} \cdot 2-1$$
View solution Problem 38
Use a form of the distributive property to rewrite each algebraic expression without parentheses. $$6(3 x-2)$$
View solution Problem 38
Find each sum without the use of a number line. $$10+(-3)+(-8)$$
View solution