Problem 38
Question
Graph each quadratic function. Label the vertex and sketch and label the axis of symmetry. $$ F(x)=\left(x+\frac{1}{2}\right)^{2}-2 $$
Step-by-Step Solution
Verified Answer
Vertex: \((-\frac{1}{2}, -2)\); Axis: \(x = -\frac{1}{2}\); Upward-opening parabola.
1Step 1: Identify the Standard Form
The given quadratic function is \( F(x) = \left(x+\frac{1}{2}\right)^2-2 \). This is already in vertex form \( y = a(x-h)^2 + k \). By comparing, we see that \( h = -\frac{1}{2} \) and \( k = -2 \).
2Step 2: Determine the Vertex
The vertex of a quadratic in the form \( y = a(x-h)^2 + k \) is \( (h, k) \). From Step 1, we have \( h = -\frac{1}{2} \) and \( k = -2 \), so the vertex is \( \left(-\frac{1}{2}, -2\right) \).
3Step 3: Identify the Axis of Symmetry
The axis of symmetry of a quadratic function is a vertical line passing through the vertex. Since the x-coordinate of the vertex is \( -\frac{1}{2} \), the axis of symmetry is the line \( x = -\frac{1}{2} \).
4Step 4: Sketch the Graph
Plot the vertex \((-\frac{1}{2}, -2)\) on a graph. Draw a vertical dashed line at \(x = -\frac{1}{2}\) for the axis of symmetry. Since the coefficient of \((x + \frac{1}{2})^2\) is positive, the parabola opens upwards. Sketch the curve symmetrically around the axis of symmetry. Label the vertex and the axis.
Key Concepts
Vertex FormAxis of SymmetryGraphing Parabolas
Vertex Form
The vertex form of a quadratic function is an important way to express a quadratic equation, especially when you want to easily identify the vertex of the parabola it represents. It has the general structure: \[ y = a(x-h)^2 + k \] where:
Moving from standard form or factored form to vertex form often involves a process called completing the square. The vertex form is a friendly tool in graphing parabolas because it allows you to graph a key feature of the parabola, the vertex, without needing to find it separately.
- \(a\) determines the "width" and the "direction" of the parabola (upward if \(a > 0\), downward if \(a < 0\)).
- \(h\) and \(k\) represent the x and y coordinates of the parabola's vertex, respectively.
Moving from standard form or factored form to vertex form often involves a process called completing the square. The vertex form is a friendly tool in graphing parabolas because it allows you to graph a key feature of the parabola, the vertex, without needing to find it separately.
Axis of Symmetry
Understanding the axis of symmetry is crucial when learning about parabolas. The axis of symmetry is a vertical line that splits the parabola into two mirror-image halves. For a quadratic function in vertex form \( y = a(x-h)^2 + k \), the axis of symmetry is given by the equation \( x = h \).
In the given exercise, where the quadratic function is \( F(x) = \left(x + \frac{1}{2}\right)^2 - 2 \), the vertex is \( \left(-\frac{1}{2}, -2\right) \). Here, the axis of symmetry is the vertical line \( x = -\frac{1}{2} \) because that is the x-coordinate of the vertex.
In the given exercise, where the quadratic function is \( F(x) = \left(x + \frac{1}{2}\right)^2 - 2 \), the vertex is \( \left(-\frac{1}{2}, -2\right) \). Here, the axis of symmetry is the vertical line \( x = -\frac{1}{2} \) because that is the x-coordinate of the vertex.
- It is a simple line which helps us understand how the parabola is symmetric.
- The parabola reflects over this line, meaning for every point \((x, y)\) on the parabola, there is a matching point \((-x, y)\) on the other side.
Graphing Parabolas
Graphing parabolas involves plotting the key features derived from the quadratic equation. These include the vertex, axis of symmetry, and knowing the direction the parabola opens. Using vertex form to graph a parabola is a straightforward process.
Start by plotting the vertex of the parabola, which gives you a fixed starting point. In our example, the vertex of the function \( F(x) = \left(x + \frac{1}{2}\right)^2 - 2 \) is at \( (-\frac{1}{2}, -2) \). Mark this point on your graph.
Start by plotting the vertex of the parabola, which gives you a fixed starting point. In our example, the vertex of the function \( F(x) = \left(x + \frac{1}{2}\right)^2 - 2 \) is at \( (-\frac{1}{2}, -2) \). Mark this point on your graph.
- Next, draw the axis of symmetry, a vertical dashed line passing through \( x = -\frac{1}{2} \).
- After pinpointing these elements, check the coefficient \( a \) from the equation to know the direction of the parabola. Since \( a \) is positive, the parabola opens upwards.
Other exercises in this chapter
Problem 38
Solve. The length and width of a rectangle must have a sum of 50 . Find the dimensions of the rectangle that will have maximum area.
View solution Problem 38
Solve each equation by completing the square. $$ x^{2}-2 x-2=0 $$
View solution Problem 39
Use the quadratic formula to solve each equation. These equations have real solutions and complex, but not real, solutions. $$ (n-2)^{2}=2 n $$
View solution Problem 39
Solve each inequality. Write the solution set in interval notation. $$ \frac{-1}{x-1}>-1 $$
View solution