Problem 38
Question
Give a geometric interpretation of the map \(\mathrm{x} \mapsto\) Ax for each given map \(\mathrm{A}\). $$A=\left[\begin{array}{rr}0 & 1 \\ -1 & 0\end{array}\right]$$
Step-by-Step Solution
Verified Answer
The map represents a 90-degree counterclockwise rotation about the origin.
1Step 1: Understand the Linear Transformation
We are trying to interpret the linear transformation defined by the matrix \( A = \begin{bmatrix} 0 & 1 \ -1 & 0 \end{bmatrix} \). This transformation maps a vector \( \mathbf{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \) in the plane to \( \mathbf{y} = A\mathbf{x} = \begin{bmatrix} 0 & 1 \ -1 & 0 \end{bmatrix} \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \).
2Step 2: Perform the Matrix Multiplication
Multiply the matrix \( A \) by the vector \( \mathbf{x} \).\[A\mathbf{x} = \begin{bmatrix} 0 & 1 \ -1 & 0 \end{bmatrix} \begin{bmatrix} x_1 \ x_2 \end{bmatrix} = \begin{bmatrix} (0)(x_1) + (1)(x_2) \ (-1)(x_1) + (0)(x_2) \end{bmatrix} = \begin{bmatrix} x_2 \ -x_1 \end{bmatrix}\]
3Step 3: Identify the Geometric Transformation
The result \( \begin{bmatrix} x_2 \ -x_1 \end{bmatrix} \) represents the vector \( \mathbf{x} \) rotated by 90 degrees counterclockwise around the origin. This is because the transformation swaps the components of the vector and changes the sign of the first component.
4Step 4: Conclusion
The map \( \mathbf{x} \mapsto A\mathbf{x} \) given by the matrix \( A \) represents a 90-degree counterclockwise rotation about the origin in the cartesian plane.
Key Concepts
Matrix MultiplicationGeometric InterpretationRotation Matrix
Matrix Multiplication
Matrix multiplication is a key step in understanding linear transformations like the one defined by the matrix\( A = \begin{bmatrix} 0 & 1 \ -1 & 0 \end{bmatrix} \). This operation involves combining a matrix with a vector to produce a new vector. Each element of the new vector is calculated as a sum of the products of the elements of the rows of the matrix with the columns of the vector. For our given matrix and vector, the operation looks like this:
- For the first row of the matrix, compute \((0)(x_1) + (1)(x_2) = x_2\).
- For the second row of the matrix, compute \((-1)(x_1) + (0)(x_2) = -x_1\).
Geometric Interpretation
The geometric interpretation of a linear transformation often involves visualizing how vectors are affected by the transformation. In this case, when the matrix \( A = \begin{bmatrix} 0 & 1 \ -1 & 0 \end{bmatrix} \) is applied to any vector \( \mathbf{x} \), it results in the vector \( \begin{bmatrix} x_2 \ -x_1 \end{bmatrix} \). This transformation swaps the original components of the vector and changes the sign of the first, effectively rotating the vector.
Understanding Rotation in 2D
In two-dimensional space, this matrix operation translates to a rotation. Specifically, this operation results in rotating the vector 90 degrees counterclockwise around the origin. The swap of components and sign change are visual indicators of this geometric transformation. Such insights are crucial for applications in graphics, physics, and more where transformations are used to simulate motion or perspective.Rotation Matrix
A rotation matrix is a specific type of linear transformation matrix used to rotate vectors around the origin of a coordinate system. Our matrix, \( A = \begin{bmatrix} 0 & 1 \ -1 & 0 \end{bmatrix} \), is one of the simplest rotation matrices, representing a 90-degree rotation.
Characteristics of Rotation Matrices
Rotation matrices have several important properties:- They are orthogonal, meaning their transpose is also their inverse.
- They preserve the length of vectors, as rotations do not change vector magnitudes.
- They alter only the direction of vectors, not their amplitude.
- The determinant of a 2D rotation matrix is always 1 or -1, indicating a pure rotation with no scaling.
Other exercises in this chapter
Problem 37
Give a geometric interpretation of the map \(\mathrm{x} \mapsto\) Ax for each given map \(\mathrm{A}\). $$A=\left[\begin{array}{rr}-1 & 0 \\ 0 & -1\end{array}\r
View solution Problem 37
Let $$A=\left[\begin{array}{rr} 1 & 1 \\ 1 & -2 \end{array}\right] \quad \text { and } \quad I_{2}=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]$$ S
View solution Problem 38
Let \(A=\left[\begin{array}{rrr}1 & 3 & 0 \\ 0 & 0 & -2 \\ -1 & 1 & 1\end{array}\right]\) and \(I_{3}=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 &
View solution Problem 39
Find the equation of the plane through \((0,0,0)\) and perpendicular to \([1,1,1]\) '.
View solution