Problem 38
Question
For the following problems, use the zero-factor property to solve the equations. $$ y(y-1)=0 $$
Step-by-Step Solution
Verified Answer
Answer: The solutions for the variable y are y = 0 and y = 1.
1Step 1: Apply the zero-factor property
To apply the zero-factor property, we need to set each factor equal to zero: $$y=0$$ and $$(y-1)=0$$.
2Step 2: Solve the first equation
The first equation is already solved: $$y=0$$.
3Step 3: Solve the second equation
To solve the second equation, add 1 to both sides of the equation: $$(y-1)+1=0+1$$ which simplifies to $$y=1$$.
4Step 4: Present the solutions
The solutions to the given quadratic equation are $$y=0$$ and $$y=1$$.
Key Concepts
Quadratic EquationsSolving EquationsFactorization
Quadratic Equations
Quadratic equations are mathematical expressions of the form \( ax^2 + bx + c = 0 \). They involve terms up to the second degree, which means the highest exponent for the variable is 2. These equations are fundamental in algebra and appear in various real-life scenarios, such as physics and engineering. The standard form of a quadratic equation can be solved using several methods, including factoring, the quadratic formula, or completing the square. Quadratic equations can have different types of solutions, including:
- Two distinct real solutions
- One repeated real solution
- No real solution but two complex solutions
Solving Equations
Solving equations is the process of finding the value(s) of the variable(s) that make the equation true. In the context of quadratic equations, solving usually involves determining the values of the variable that satisfy the equation. One of the simplest ways to solve a quadratic equation is by using the zero-factor property, which states that if the product of two factors is zero, then at least one of the factors must be zero. This property becomes very useful when an equation is factored properly.Here's a step-by-step approach:
- Transform the equation into a factored form like \( (x - p)(x - q) = 0 \)
- Apply the zero-factor property, setting each factor equal to zero (\( x - p = 0 \) and \( x - q = 0 \))
- Solve these simpler linear equations to find the values of \( x \)
Factorization
Factorization in algebra involves breaking down a complex expression into a product of simpler factors. For quadratic equations, often the first step is to express the quadratic expression in a factored form. This process is called factorizing. When a quadratic is written as a product of two binomials, it can be easily set to zero and solved using the zero-factor property. Factorizing a quadratic equation typically involves:
- Identifying two numbers that multiply to give \( ac \) (product of coefficients \( a \) and \( c \)) and add to \( b \) (the coefficient of the linear term)
- Rewriting the quadratic equation using these two numbers
- Grouping terms and factoring each group
- Factoring the entire expression to find the simplified factors
Other exercises in this chapter
Problem 38
For the following problems, solve the equations, if possible. $$ x^{2}+36=0 $$
View solution Problem 38
For the following problems, solve for the indicated variable. $$ x^{2}=4 a^{2}, \text { for } x $$
View solution Problem 39
For the following problems, solve the equations using the quadratic formula. $$ a^{2}+3 a-4=0 $$
View solution Problem 39
Factor \(12 a x-6 b x+20 a y-10 b y\) by grouping.
View solution