Problem 38
Question
For exercises \(5-48\), simplify. $$ \frac{y^{3}+5 y^{2}}{y^{3}-16 y}-\frac{36 y}{y^{3}-16 y} $$
Step-by-Step Solution
Verified Answer
\frac{y + 9}{y + 4}
1Step 1: Factor the Denominator
First, factor the common denominator in each term. The common denominator in this case can be factored as follows: \[ y^3 - 16y = y(y^2 - 16) = y(y - 4)(y + 4) \]
2Step 2: Rewrite Fractions with Common Denominator
Rewrite each fraction using the factored denominator: \[ \frac{y^3 + 5y^2}{y(y - 4)(y + 4)} - \frac{36y}{y(y - 4)(y + 4)} \]
3Step 3: Combine the Fractions
Since the fractions have the same denominator, combine them into a single fraction: \[ \frac{(y^3 + 5y^2) - 36y}{y(y - 4)(y + 4)} \]
4Step 4: Simplify the Numerator
Expand and then factor the numerator if possible: \[ y^3 + 5y^2 - 36y \] Group and factor by grouping: \[ y(y^2 + 5y - 36) \] Factor the trinomial: \[ y(y + 9)(y - 4) \]
5Step 5: Cancel Common Factors
The term \(y(y + 9)(y - 4)\) in the numerator and \(y(y - 4)(y + 4)\) in the denominator have common factors that can be cancelled:\[ \frac{y(y + 9)(y - 4)}{y(y - 4)(y + 4)} \] The common factors \(y\) and \(y - 4\) are cancelled out, leaving: \[ \frac{y + 9}{y + 4} \]
Key Concepts
Factoring PolynomialsCommon DenominatorsFractions
Factoring Polynomials
Factoring polynomials is a helpful technique when working with algebraic expressions. It involves breaking down a complicated polynomial into simpler products of polynomials. In this exercise, we started by factoring the common denominator. Consider the polynomial in the denominator, \(y^3 - 16y\). We can factor this as follows:
- Factor out a common factor of \( y \): \( y(y^2 - 16)\)
- Recognize that \( y^2 - 16 \) is a difference of squares: \((y - 4)(y + 4) \)
- Combine them into a complete factored form: \[ y(y - 4)(y + 4) \]
Common Denominators
When adding or subtracting fractions, it's essential to have a common denominator. This term enables the fractions to be written over the same denominator, allowing for straightforward combining.
In our exercise, both fractions already share the same factored denominator, \[ y(y - 4)(y + 4) \]. This lets us combine them as follows: \[ \frac{y^3 + 5y^2}{y(y - 4)(y + 4)} - \frac{36y}{y(y - 4)(y + 4)} = \frac{(y^3 + 5y^2) - 36y}{y(y - 4)(y + 4)} \] Having common denominators makes the process of adding or subtracting fractions straightforward as we only need to combine the numerators while keeping the denominator unchanged.
In our exercise, both fractions already share the same factored denominator, \[ y(y - 4)(y + 4) \]. This lets us combine them as follows: \[ \frac{y^3 + 5y^2}{y(y - 4)(y + 4)} - \frac{36y}{y(y - 4)(y + 4)} = \frac{(y^3 + 5y^2) - 36y}{y(y - 4)(y + 4)} \] Having common denominators makes the process of adding or subtracting fractions straightforward as we only need to combine the numerators while keeping the denominator unchanged.
Fractions
Fractions are essential in algebra, as they represent division between two expressions. Simplifying fractions involves reducing them to their simplest form. In our exercise, we combined the fractions and then focused on simplifying the numerator. The steps were:
- Combine the numerators: \( y^3 + 5y^2 - 36y \)
- Factor the numerator: \[ y(y + 9)(y - 4) \]
- Cancel out common factors with the denominator: \[ \frac{y(y + 9)(y - 4)}{y(y - 4)(y + 4)} \]
Other exercises in this chapter
Problem 38
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