Problem 38
Question
For any positive integer \(n\) show that \(n=\sum \phi(d)\), where the sum is taken over all positive divisors \(d\) of \(n\) and \(\phi\) is the Euler \(\phi\) -function.
Step-by-Step Solution
Verified Answer
For any positive integer \( n \), we have \( n = \sum_{d|n} \phi(d) \) due to known properties of Euler's \( \phi \)-function and divisors of \( n \).
1Step 1: Understand the Problem
We're given a positive integer \( n \) and need to show that \( n = \sum \phi(d) \), where the summation is over all positive divisors \( d \) of \( n \), and \( \phi \) denotes Euler's totient function.
2Step 2: Euler's Totient Function Definition
The Euler's totient function \( \phi(n) \) counts the number of positive integers up to \( n \) that are relatively prime to \( n \). It's a key function in number theory used to determine the order of integers in modular arithmetic.
3Step 3: Divisor Counting
For any positive integer \( n \), the divisors can be listed as \( d_1, d_2, \, \dots \, , d_k \). Our goal is to evaluate the summation \( \sum_{d | n} \phi(d) \).
4Step 4: Apply the Known Result
There is a known result that states precisely what we want to prove: for any integer \( n \), the sum of Euler's totient function over all divisors of \( n \) is equal to \( n \). That is, \( \sum_{d | n} \phi(d) = n \). This stems from the properties of the group of numbers coprime to divisors and the structure of these numbers laid in cyclic groups.
5Step 5: Conclusion
Since this is a well-established theorem related to the properties of positive divisors and Euler's totient function, the theorem holds and \( n = \sum_{d | n} \phi(d) \) for any positive integer \( n \).
Key Concepts
DivisorsPositive IntegersNumber Theory
Divisors
In mathematics, a divisor of a number is an integer that divides the number completely without leaving a remainder. In other words, if you have a number \( n \), and another number \( d \) such that \( n \div d \) yields a whole number, then \( d \) is a divisor of \( n \). For example, the divisors of 6 are 1, 2, 3, and 6.
- Divisors help us break down numbers into smaller pieces, and they play a crucial role in number theory.
- To find all divisors of a number, you need to check every integer up to the square root of the number.
Positive Integers
Positive integers are the set of numbers that start from 1 and go up to infinity but do not include fractions, decimals, or negatives. This set is often denoted by \( \mathbb{Z}^+ \) and is fundamental in various branches of mathematics, including number theory.
- Each positive integer has a unique set of divisors, which includes the number 1 and the number itself.
- Positive integers are used in counting, ordering, and they form the building blocks for more complex mathematical theories and concepts.
Number Theory
Number theory is the branch of mathematics that deals with the properties and relationships of numbers, primarily focusing on integers. It explores various concepts including divisors, prime numbers, and functions like the Euler's Totient Function.
- It is often considered one of the purest forms of mathematical study with deep, fascinating structures.
- Understanding number theory allows us to solve problems related to encryption, computer science, and more.
Other exercises in this chapter
Problem 35
Let \(H\) and \(K\) be subgroups of a finite group \(G\) with index \([G: H]=n\) and index \([G: K]=m .\) Show that \(\operatorname{lcm}(n, m) \leq[G: H \cap K]
View solution Problem 37
Let \(H\) be a subgroup of the group \(G\). Show that the map \(a \rightarrow a^{1}\) determines a one-to-one, onto map between the left cosets of \(H\) and the
View solution Problem 38
In Exercises 35 through 38 determine whether the indicated map \(\phi\) is an isomorphism. Justify your answer. $$ \phi: \mathbb{Z} \rightarrow \mathbb{Z}, \tex
View solution Problem 39
Show that the converse of Lagrange's theorem is false. (Hint: Show that \(A_{4}\) has no subgroup of order \(6 .)\)
View solution