Problem 38
Question
Find the midpoint between the two points \((-3,3),(2,-2)\)
Step-by-Step Solution
Verified Answer
The midpoint is \(\left(-0.5, 0.5\right)\)
1Step 1: Identify the coordinates of the points
The given points are \((-3,3)\) and \((2,-2)\), so we have \(x1 = -3, y1 = 3, x2 = 2, y2 = -2\)
2Step 2: Insert the coordinates into the formula
Substitute the values of \(x1, y1, x2, y2\) into the midpoint formula. We get \(M = \left( \frac{-3+2}{2} , \frac{3+(-2)}{2} \right)\)
3Step 3: Calculate the coordinates of the midpoint
Perform the calculations which gives us the midpoint \(M = \left( \frac{-1}{2} , \frac{1}{2} \right)\)
Key Concepts
Coordinate GeometryCartesian CoordinatesDistance and Midpoints
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that establishes a connection between algebra and geometry. This field utilizes a coordinate system to relate points on a plane through numbers and equations. It allows us to answer geometric questions with algebraic equations. Thanks to coordinate geometry, we can pinpoint exact positions on a plane using coordinates and analyze shapes through equations.
- Visualizing shapes and lines with coordinates.
- Translating geometric problems into algebraic models.
Cartesian Coordinates
The Cartesian coordinate system is a two-dimensional system used to determine the position of points. It is named after the French mathematician René Descartes, and it revolutionized geometry by introducing a link between algebra and geometry, where each point is defined by a pair of numerical coordinates:
- The point \((x, y)\) consists of an "x" coordinate (horizontal) and a "y" coordinate (vertical).
- The origin, where \(x = 0\) and \(y = 0\), is the center point from which all calculations are made.
Distance and Midpoints
The concepts of distance and midpoints are fundamental in coordinate geometry. The midpoint formula helps us find the exact middle point between two coordinates by averaging the x and y values of the initial points. Using the coordinates from the example, given \((-3, 3)\) and \(2, -2)\):
- Midpoint Formula: \((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\)
- Calculate: \((-3 + 2) / 2 = -1/2\) and \((3 - 2) / 2 = 1/2\)
Other exercises in this chapter
Problem 37
Solve the equation by completing the square. $$x^{2}+11 x+\frac{21}{4}=0$$
View solution Problem 37
Simplify the expression. $$(\sqrt{a}-b)^{2}$$
View solution Problem 38
Solve the equation. Check for extraneous solutions. $$x=\sqrt{6 x-9}$$
View solution Problem 38
Decide how many solutions the equation has. $$x^{2}+16 x+64=0$$
View solution