Problem 38
Question
Find the limit, if it exists. If the limit does not exist, explain why. $$\lim _{x \rightarrow-4^{-}} \frac{|x+4|}{x+4}$$
Step-by-Step Solution
Verified Answer
The limit is -1.
1Step 1: Understand the Expression
The given expression is \( \lim _{x \rightarrow-4^{-}} \frac{|x+4|}{x+4} \). We need to find the limit as \( x \) approaches -4 from the left. This means we consider values of \( x \) that are just less than -4.
2Step 2: Simplify the Absolute Value
For values of \( x \) less than -4, the expression inside the absolute value \( |x+4| \) becomes negative because \( x+4 < 0 \). Therefore, \( |x+4| = -(x+4) \).
3Step 3: Substitute and Simplify
Substitute \( |x+4| = -(x+4) \) into the expression: \[ \frac{|x+4|}{x+4} = \frac{-(x+4)}{x+4} \]. Simplifying this gives us \( \frac{-(x+4)}{x+4} = -1 \).
4Step 4: Evaluate the Limit
As \( x \to -4^{-} \), the expression simplifies to -1. Therefore, the limit of \( \frac{|x+4|}{x+4} \) as \( x \to -4^{-} \) is \( -1 \).
Key Concepts
Understanding Absolute ValueExploring One-Sided LimitsSimplifying Expressions for Limits
Understanding Absolute Value
The concept of absolute value is essential in understanding limits, especially when dealing with expressions that involve inequalities. Absolute value, denoted as \(|x|\), represents the distance of a number from zero on the number line. Consequently, it is always a non-negative number. When looking at \(|x + 4|\), you should consider two cases:
- If \(x + 4\) is positive or zero, then \(|x + 4| = x + 4\).
- If \(x + 4\) is negative, then \(|x + 4| = -(x + 4)\).
Exploring One-Sided Limits
One-sided limits are significant when investigating the behavior of functions as the input approaches a specific point from one direction. Specifically, a one-sided limit at \(x \rightarrow c^{-}\) considers values of \(x\) that are slightly less than \(c\), whereas a limit of \(x \rightarrow c^{+}\) would consider values slightly greater. In this exercise, we are asked to find \(\lim_{x \rightarrow -4^{-}} \dfrac{|x+4|}{x+4}\). Here, the expression needs examination only from the left-hand side because it's a left-hand limit (denoted by \(-\)). Staying strictly on the left hand side of \(-4\) ensures that the nature of the fraction \(|x + 4|/(x + 4)\) remains consistent, which is vital in accurately identifying the limit value without ambiguity.One-sided limits help illuminate the behavior of expressions at boundary points and are quite useful when dealing with piecewise and discontinuous functions, like the one observed here with absolute values.
Simplifying Expressions for Limits
Simplifying expressions is an essential skill for solving limit problems, especially when involving complicated operations like division or absolute values. Simplification often involves algebraic manipulation to reveal the core structure of an expression.In the case of \(\frac{|x+4|}{x+4}\), simplification happens by addressing the absolute value. As established, when \(x < -4\), \(|x+4|\) simplifies to \(-(x+4)\). Therefore, the fraction simplifies to:
- \(\frac{-(x+4)}{x+4} = -1\).
Other exercises in this chapter
Problem 37
A Function from a Description Find a formula from a function \(f\) that satisfies the following conditions. Asymptote Behavior How close to \(-3\) do we have to
View solution Problem 38
Velocity on the Moon If an arrow is shot upward on the moon with a velocity of \(58 \mathrm{m} / \mathrm{s},\) its height (in meters) after \(t\) seconds is giv
View solution Problem 38
Show that $$\lim _{x \rightarrow \infty} f(x)=\lim _{t \rightarrow 0^{+}} f\left(\frac{1}{t}\right)$$ and $$\lim _{x \rightarrow-\infty} f(x)=\lim _{t \rightarr
View solution Problem 39
Velocity of a Particle The displacement \(s\) (in meters) of a particle moving in a straight line is given by the equation of motion \(s=4 t^{3}+6 t+2,\) where
View solution