Problem 38
Question
Find the domain of the following functions. $$ f(x, y)=\cos \sqrt{x^{2}+y^{2}} $$
Step-by-Step Solution
Verified Answer
The domain is all real numbers: \((x, y) \in \mathbb{R}^2\).
1Step 1: Identify the Structure of the Function
The given function is a composition of a square root and cosine function, specifically: \( f(x, y) = \cos \sqrt{x^2 + y^2} \). Understanding how these components work is crucial to finding the domain.
2Step 2: Determine the Domain of the Square Root Function
The expression inside the square root, \( x^2 + y^2 \), must be non-negative (\( \geq 0 \)), as the square root function is undefined for negative values. Since \( x^2 + y^2 \geq 0 \) for all real \( x \) and \( y \), this part of the function is always defined.
3Step 3: Consider the Cosine Function
The cosine function, \( \cos(\theta) \), is defined for all real numbers. Therefore, regardless of whether \( \sqrt{x^2 + y^2} \) is any non-negative real number, \( \cos \sqrt{x^2 + y^2} \) will be defined as well.
4Step 4: Integrate Both Conditions for the Composite Function
Since both the square root and cosine functions are defined for all real \( x \) and \( y \) that satisfy \( x^2 + y^2 \geq 0 \), the composite function \( f(x, y) = \cos \sqrt{x^2 + y^2} \) is defined for all \( x \) and \( y \) in \( \mathbb{R}^2 \).
Key Concepts
Domain of a FunctionComposite FunctionsSquare Root FunctionCosine Function
Domain of a Function
When dealing with multivariable calculus, understanding the domain of a function is crucial. The **domain** refers to the set of all possible input values that a function can accept without causing any mathematical errors. Specifically, a function like \( f(x, y) = \cos \sqrt{x^2 + y^2} \) requires us to determine which values of \( x \) and \( y \) make the function valid.
- To find the domain, observe each component of the composite function.
- Ensure that operations like square roots do not involve negative numbers.
- Check that trigonometric functions are defined for the values in question.
Composite Functions
In the realm of multivariable calculus, a **composite function** is a function made up of multiple simpler functions. It's like stacking one function on top of another. For instance, in \( f(x, y) = \cos \sqrt{x^2 + y^2} \), the square root function is nested inside the cosine function.
- This setup is notated as \( f(g(h(x, y))) \), where each function affects the outcome of the next.
- Each function has its own domain, and assessing them step-by-step helps find the overall domain.
Square Root Function
The **square root function** is fundamental in defining certain multivariable calculus problems. It is typically expressed as \( \sqrt{x^2 + y^2} \) in functions like \( f(x, y) = \cos \sqrt{x^2 + y^2} \).
- Critically, the square root must have a non-negative argument.
- This means \( x^2 + y^2 \geq 0 \). Quadratic expressions like \( x^2 + y^2 \) are naturally non-negative for all real \( x \) and \( y \).
Cosine Function
The **cosine function**, denoted as \( \cos(\theta) \), plays an important role in trigonometric calculus problems. It's a smooth, oscillating function defined for all real numbers, with outputs ranging between \(-1\) and \(1\).
- Cosine is unique as it faces no restrictions regarding its domain; \( \theta \) can be any real number.
- When paired with other functions, like a square root, check that the resulting input remains valid.
Other exercises in this chapter
Problem 36
Find the domain of the following functions. $$ f(x, y, z)=\sqrt{49-x^{2}-y^{2}-z^{2}} $$
View solution Problem 37
Find the domain of the following functions. $$ f(x, y, z)=\sqrt[3]{16-x^{2}-y^{2}-z^{2}} $$
View solution Problem 39
For the following exercises, plot a graph of the function. $$ z=f(x, y)=\sqrt{x^{2}+y^{2}} $$
View solution Problem 40
For the following exercises, plot a graph of the function. $$ z=x^{2}+y^{2} $$
View solution