Problem 38
Question
Exer. 35-38: Find the values of \(x\) and \(y\), where \(x\) and \(y\) are real numbers. $$ 8+(3 x+y) i=2 x-4 i $$
Step-by-Step Solution
Verified Answer
The solution is \(x = 4\) and \(y = -16\).
1Step 1: Identify the real and imaginary components on both sides
We start by writing the given complex equation:\[8 + (3x + y)i = 2x - 4i\]In a complex number of the form \(a + bi\), \(a\) is the real part and \(b\) is the imaginary part. So, we have the real parts as \(8\) and \(2x\) respectively, and the imaginary parts as \((3x + y)i\) and \(-4i\).
2Step 2: Set up equations from the corresponding parts
Since the real and imaginary parts are equal, we set up the following equations:1. Real part: \[ 8 = 2x \]2. Imaginary part: \[ 3x + y = -4 \]
3Step 3: Solve the equation for the real part
From the equation \(8 = 2x\), divide both sides by 2 to solve for \(x\):\[x = \frac{8}{2} = 4\]
4Step 4: Substitute the value of x into the imaginary part equation
Substitute \(x = 4\) into the equation for the imaginary part:\[3(4) + y = -4\]which simplifies to:\[ 12 + y = -4 \]
5Step 5: Solve the equation for y
Subtract 12 from both sides to solve for \(y\):\[y = -4 - 12 = -16\]
Key Concepts
Understanding the Real PartDiscovering the Imaginary PartFormulating EquationsArriving at the Solutions
Understanding the Real Part
In the world of complex numbers, the real part is an integral value representing the non-imaginary component of a number. Complex numbers are expressed in the form \(a + bi\), where \(a\) is the real part and \(b\) represents the coefficient of the imaginary part.
In our given equation, \(8 + (3x + y)i = 2x - 4i\), the real part on the left side is \(8\) and on the right side is \(2x\).
The equation for the real part equates these:
In our given equation, \(8 + (3x + y)i = 2x - 4i\), the real part on the left side is \(8\) and on the right side is \(2x\).
The equation for the real part equates these:
- 8 = 2x
Discovering the Imaginary Part
The imaginary part of a complex number captures the coefficient of \(i\), an imaginary unit satisfying \(i^2 = -1\). When working with complex numbers, the term multiplying \(i\) is essential in defining the number's imaginary component.
For the complex equation \(8 + (3x + y)i = 2x - 4i\), the imaginary part is given by the expressions:
For the complex equation \(8 + (3x + y)i = 2x - 4i\), the imaginary part is given by the expressions:
- \((3x + y)\) on the left, corresponding to \(\text{i}\)
- \(-4\) on the right, also corresponding to \(\text{i}\)
- \(3x + y = -4\)
Formulating Equations
Creating equations from the components of a complex number allows us to solve problems step by step. The process involves separating each component into its own concise mathematical expression.
By breaking down our complex number \(8 + (3x + y)i = 2x - 4i\) into real and imaginary parts, two main equations emerge:
By breaking down our complex number \(8 + (3x + y)i = 2x - 4i\) into real and imaginary parts, two main equations emerge:
- Real: \(8 = 2x\)
- Imaginary: \(3x + y = -4\)
Arriving at the Solutions
Solving the equations obtained from complex numbers is a process that leads to determining the variables involved. For our example, once we have the two equations—one from the real part (\(8 = 2x\)) and one from the imaginary part (\(3x + y = -4\))—we can easily solve them to find \(x\) and \(y\).
Here's how it's done:
Here's how it's done:
- Solve \(8 = 2x\) to get \(x = 4\).
- Substitute \(x = 4\) into the other equation: \(3(4) + y = -4\). Calculate \(12 + y = -4\).
- Finally, solve for \(y\) to find that \(y = -16\).
Other exercises in this chapter
Problem 38
Exer. 21-70: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ (x-3)(x+3) \geq(x+5)^{2} $$
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Exer. 1-50: Solve the equation. $$ 3 y^{4}-5 y^{2}+1=0 $$
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Exer. \(31-44\) : Solve by using the quadratic formula. $$ \frac{5}{3} s^{2}+3 s+1=0 $$
View solution Problem 39
The temperature \(T\) within a cloud at height \(h\) (in feet) above the cloud base can be approximated using the equation \(T=B-\left(\frac{3}{1000}\right) h\)
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