Problem 38
Question
Exer. 11-46: Simplify. $$ \left(25 z^{4}\right)^{-3 / 2} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(\frac{1}{125z^6}\).
1Step 1: Understand Exponent Notation
First, notice that the expression is written using exponent notation with a negative fractional exponent, \(-\frac{3}{2}\). This means we have both a negative exponent and a root involved.
2Step 2: Apply Negative Exponent Rule
The negative exponent \(-\frac{3}{2}\) indicates that we should take the reciprocal of the base inside the parentheses: \(\left(25z^{4}\right)^{-\frac{3}{2}} = \frac{1}{\left(25z^{4}\right)^{\frac{3}{2}}}\).
3Step 3: Separate Base and Use Exponent
Break down \(\left(25z^{4}\right)^{\frac{3}{2}}\) into separate bases: \(25^{\frac{3}{2}}\) and \((z^{4})^{\frac{3}{2}}\).
4Step 4: Simplify the Base 25
To simplify \(25^{\frac{3}{2}}\), recognize that \(\frac{3}{2}\) suggests performing a square root followed by cubing: \((\sqrt{25})^3 = 5^3 = 125\).
5Step 5: Simplify the Power of z
Utilize the power of a power property \( (z^{4})^{\frac{3}{2}} = z^{\frac{4 \times 3}{2}} = z^{6} \).
6Step 6: Combine Simplified Results
Substitute the simplified terms back together: \(\frac{1}{125z^6}\).
7Step 7: Write the Final Simplified Answer
The fully simplified form of the expression is \(\frac{1}{125z^6}\).
Key Concepts
Negative ExponentsFractional ExponentsPower of a PowerReciprocal
Negative Exponents
When dealing with exponents, a negative exponent may seem a bit intimidating. But don't worry, it's quite simple once you understand the basic rule. A negative exponent indicates that you should take the reciprocal of the base. This means that instead of multiplying the base by itself, we divide 1 by the base raised to the corresponding positive exponent.
Here's an easy to follow rule:
Here's an easy to follow rule:
- If you have an expression like \(b^{-n}\), it becomes \(\frac{1}{b^n}\).
- \((25z^4)^{-\frac{3}{2}}\) transforms to \(\frac{1}{(25z^4)^{\frac{3}{2}}}\).
Fractional Exponents
Fractional exponents might sound mysterious at first, but they are just another way of representing roots and powers in a single expression. When you see a fractional exponent, think of it as a combination of two operations: a power and a root.
- The numerator of the fraction tells you the power.
- The denominator tells you the root.
- The base \(a\) is raised to the power \(m\).
- Then, you take the \(n\)th root.
Power of a Power
The power of a power property is a handy rule when simplifying expressions with exponents. This rule states that when an exponent is raised to another exponent, you multiply the exponents together.
Essentially,
Essentially,
- If you have \((a^m)^n\), it simplifies to \(a^{m \times n}\).
- \((z^4)^{\frac{3}{2}}\) translates to \(z^{4 \times \frac{3}{2}} = z^6\).
Reciprocal
A reciprocal is a number which, when multiplied by the original number, results in the product of one. In mathematical terms, the reciprocal of a number \(x\) is \(\frac{1}{x}\). The concept of reciprocals is crucial when working with negative exponents, as it allows us to switch from negative to positive exponents by transforming the structure of the expression.
The logical reason behind using the reciprocal is that a negative exponent, as explained earlier, indicates division rather than multiplication. Thus,
The logical reason behind using the reciprocal is that a negative exponent, as explained earlier, indicates division rather than multiplication. Thus,
- For \( (b^{-n})\),
- it becomes \( \frac{1}{b^n} \).
- \((25z^4)^{-\frac{3}{2}}\) into \(\frac{1}{(25z^4)^{\frac{3}{2}}}\).
Other exercises in this chapter
Problem 38
Find the values of \(x\) and \(y\), where \(x\) and \(y\) are $$ 8+(3 x+y) i=2 x-4 i $$
View solution Problem 38
Express as a polynomial. $$ (x+3 y)^{3} $$
View solution Problem 38
Exer. 33-40: Replace the symbol \(\square\) with either \(=\) or \(\neq\) to make the resulting statement true for all real numbers \(a, b\), \(c\), and \(d\),
View solution Problem 39
Find the solutions of the equation $$ x^{2}-6 x+13=0 $$
View solution