Problem 38
Question
Evaluate the expression without using a calculator.\(\ln e^{10}\)
Step-by-Step Solution
Verified Answer
The value of \(\ln e^{10}\) is 10.
1Step 1: Apply Logarithmic Identity
Using the logarithmic identity \(\ln a^b = b \ln a\), the expression \(\ln e^{10}\) can be rewritten as \(10 \ln e\).
2Step 2: Evaluate \(\ln e\)
The value of \(\ln e\) is 1. This is a widely known fact as the natural logarithm base is \(e\). So, the expression becomes \(10 \times 1\).
3Step 3: Simplify the Result
Multiplying 10 by 1 results in 10. So the value of \(\ln e^{10}\) is 10.
Key Concepts
Natural LogarithmLogarithmic IdentityEvaluate Expression
Natural Logarithm
The natural logarithm is a specific type of logarithm that has the base of the constant e, approximately equal to 2.71828. Unlike the more commonly known base-10 logarithm, the natural logarithm is denoted as \( \ln \). It is a vital concept in higher mathematics because it has unique properties that simplify complex calculations.
Natural logarithms are used extensively in calculus, scientific calculations, and in various mathematical models such as exponential growth and decay.
One of the key characteristics of the natural logarithm is its relationship with the number \( e \). In simple terms, \( \ln e \) equals 1 because the base raised to the power of 1 results in e itself. Understanding the behavior of natural logarithms opens doors to easier manipulation and evaluation of expressions like \( \ln e^{10} \).
Natural logarithms are used extensively in calculus, scientific calculations, and in various mathematical models such as exponential growth and decay.
One of the key characteristics of the natural logarithm is its relationship with the number \( e \). In simple terms, \( \ln e \) equals 1 because the base raised to the power of 1 results in e itself. Understanding the behavior of natural logarithms opens doors to easier manipulation and evaluation of expressions like \( \ln e^{10} \).
Logarithmic Identity
Logarithmic identities are essential tools that enable the simplification of complex mathematical expressions. One such identity is \( \ln a^b = b \ln a \). This specific identity helps us transform expressions where the argument of the logarithm is an exponential value.
Here's a breakdown of how it works:
Here's a breakdown of how it works:
- Take the logarithm of an exponent, \( a^b \) becomes \( b \ln a \).
- The power b acts as a multiplier for the logarithm of the base a.
Evaluate Expression
Evaluating expressions without calculators benefits significantly from strong algebraic manipulations and identities. When you need to evaluate \( \ln e^{10} \), you can effectively use logarithmic properties to simplify the process.
Start with the identity we discussed: \( \ln e^{10} \) translates to \( 10 \ln e \). Since we know \( \ln e = 1 \), it becomes quick multiplication: 10 multiplied by 1, which equals 10.
This simplification is not just a trick but a practical application of mathematical properties. Recognizing the parameters of natural logs and employing identities turns the seemingly cumbersome into straightforward arithmetic.
Start with the identity we discussed: \( \ln e^{10} \) translates to \( 10 \ln e \). Since we know \( \ln e = 1 \), it becomes quick multiplication: 10 multiplied by 1, which equals 10.
This simplification is not just a trick but a practical application of mathematical properties. Recognizing the parameters of natural logs and employing identities turns the seemingly cumbersome into straightforward arithmetic.
Other exercises in this chapter
Problem 38
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(5\left(10^{x-6}\right)=7\)
View solution Problem 38
Approximate the logarithm using the properties of logarithms, given \(\log _{b} 2 \approx 0.3562\), \(\log _{b} 3 \approx 0.5646\), and \(\log _{b} 5 \approx 0.
View solution Problem 39
Stocking a Lake with Fish \(\quad\) A lake is stocked with 500 fish, and the fish population \(P\) increases according to the logistic curve \(P=\frac{10,000}{1
View solution Problem 39
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(3\left(5^{x-1}\right)=21\)
View solution