Problem 38
Question
Evaluate \(\sqrt{x-1}\) for \(x=17\)
Step-by-Step Solution
Verified Answer
The result for \(\sqrt{x-1}\) when \(x=17\) is 4.
1Step 1: Substitute the given value
We have the equation \(\sqrt{x-1}\). We will include the value given which is \(x=17\), so the equation changes to \(\sqrt{17-1}\) or \(\sqrt{16}\).
2Step 2: Calculate the square root
Now that we have \(\sqrt{16}\), we just need to evaluate the square root. The square root of 16 is 4.
Key Concepts
Square RootSubstitution MethodAlgebra
Square Root
The square root is a fundamental concept in mathematics. It helps in finding a number that, when multiplied by itself, gives the original number.
A square root is denoted by the radical symbol \( \sqrt{} \). For example, \( \sqrt{16} \) is the number that when multiplied by itself results in 16.
In simpler terms:
A square root is denoted by the radical symbol \( \sqrt{} \). For example, \( \sqrt{16} \) is the number that when multiplied by itself results in 16.
In simpler terms:
- If \( a^2 = b \), then \( a \) is the square root of \( b \).
Substitution Method
The substitution method is a technique often used in mathematics to make solving equations easier. It involves placing a known value into an expression or equation to simplify it, as seen in this exercise.
For instance, in the given expression \( \sqrt{x-1} \), we are instructed to substitute \( x \) with 17.
Let's break down the steps:
For instance, in the given expression \( \sqrt{x-1} \), we are instructed to substitute \( x \) with 17.
Let's break down the steps:
- Take the given value of \( x \), which is 17.
- Replace \( x \) in the expression with 17, changing \( \sqrt{x-1} \) to \( \sqrt{17-1} \).
- Simplify by subtracting: \( 17-1 = 16 \), resulting in \( \sqrt{16} \).
Algebra
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating these symbols. It is the language through which we describe mathematical relationships.
The aim is to find the unknown or express it in terms of known quantities.
In our exercise, we're dealing with a simple algebraic expression \( \sqrt{x-1} \).
Understanding algebra helps in evaluating expressions, finding solutions for equations, and modeling real-life situations effectively.
The aim is to find the unknown or express it in terms of known quantities.
In our exercise, we're dealing with a simple algebraic expression \( \sqrt{x-1} \).
- The expression involves a single variable \( x \), which we know the value of.
- Algebra allows us to generalize mathematical statements and form equations that can be solved for one or more variables.
- It's essential in problem-solving and is used across various fields, such as engineering, science, and economics.
Understanding algebra helps in evaluating expressions, finding solutions for equations, and modeling real-life situations effectively.
Other exercises in this chapter
Problem 38
add or subtract as indicated. Simplify the result, if possible. $$\frac{3 y^{2}-2}{3 y^{2}+10 y-8}-\frac{y+10}{3 y^{2}+10 y-8}-\frac{y^{2}-6 y}{3 y^{2}+10 y-8}$
View solution Problem 38
What are similar triangles?
View solution Problem 38
Simplify each rational expression. If the rational expression cannot be simplified, so state. $$\frac{x+2}{x^{2}-x-6}$$
View solution Problem 38
Simplify complex rational expression by the method of your choice. \(\frac{\frac{2}{x^{3} y}+\frac{5}{x y^{4}}}{\frac{5}{x^{3} y}-\frac{3}{x y}}\)
View solution